Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)audited 2026-10-08
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Quasicircles, quasidisks, quasiarcs, and quasilines

Definition

Assume the Axiom of Choice. Write C^=C∪{∞} for the Riemann sphere with its standard holomorphic charts (The Riemann sphere is the published one-point compactification of the complex plane, The standard holomorphic charts on the Riemann sphere, with holomorphy and poles at infinity). Put T={z∈C:∣z∣=1} and D={z∈C:∣z∣<1}. Identify the quotient circle S1=R/Z with T by [t]↦e2πit (The circle as S1=R/Z with basepoint [0], [t]↦(cos⁡2πt,sin⁡2πt) is a homeomorphism from R/Z to the unit circle). A Jordan curve in C^ is the image of a topological embedding S1↪C^ (Homeomorphism, open map, closed map, embedding, and what it means for a property to be topological); by Jordan–Brouwer separation it has exactly two complementary components with common boundary. A sphere homeomorphism is K-quasiconformal if it preserves the standard complex orientation (Orientation-preserving homeomorphisms and the geometric definition of quasiconformality) and, in every connected holomorphic chart neighborhood, its coordinate expression is K-quasiconformal in the analytic sense (The ACL and Sobolev analytic definition of quasiconformality); K≥1 is a uniform upper bound for the local dilatations.

(a) A Jordan curve Γ⊆C^ is a K-quasicircle if Γ=F(T) for a K-quasiconformal sphere homeomorphism F. It is a quasicircle if it is a K-quasicircle for some finite K. Its quasicircle constant is K(Γ)=inf⁡{K≥1:Γ=F(T) for some K-quasiconformal sphere homeomorphism F}. The infimum is not asserted to be attained.

(b) A domain U⊆C^ is a K-quasidisk if U=G(D) for a K-quasiconformal sphere homeomorphism G; it is a quasidisk if this holds for some finite K. The two complementary components of a K-quasicircle are K-quasidisks.

(c) A K-quasiarc is the image of the open line segment (−1,1)⊂C under a K-quasiconformal homeomorphism of C; a quasiarc is a K-quasiarc for some finite K. A K-quasiline is the image of R under a K-quasiconformal homeomorphism of C; a quasiline is a K-quasiline for some finite K.

(d) Quasicircles are Möbius invariant with unchanged constant: for every Möbius transformation M, K(M(Γ))=K(Γ).

Facts & Assumptions

Given: the unit circle T, the unit disk D, and the chartwise analytic definition of quasiconformality on the sphere.

[F2]

A Jordan curve in the sphere has exactly two complementary components, and the curve is the common boundary of both (Jordan–Brouwer separation).

[F3]

Every Möbius transformation is biholomorphic on the sphere, hence conformal in its holomorphic charts, and its inverse is also Möbius (Möbius transformations of the Riemann sphere, Every Möbius transformation is a biholomorphism of the Riemann sphere).

[F4]

Composition with a conformal map preserves the quasiconformal upper bound, and inverses of conformal maps are conformal (Composition and inversion of quasiconformal maps and their Beltrami coefficients).

[F5]

The orientation-preserving convention for a quasiconformal homeomorphism is the one in Orientation-preserving homeomorphisms and the geometric definition of quasiconformality.

Proof

technique · direct, using Jordan separation and quasiconformal composition
1.1F1F2F3F4F5algebra

Let F be an orientation-preserving K-quasiconformal sphere homeomorphism and set Γ=F(T). By [F1], F composed with the standard parametrization of T is an embedding, so Γ is a Jordan curve. The identity C^∖Γ=F(D)⊔F(M(D)) holds because F is a bijection; both sets are open, nonempty and connected, so each is a complementary component (also as specified by [F2]). Here M(z)=1/z exchanges D and the exterior component of T. The first component is a K-quasidisk by definition; [F3]–[F5] show that F∘M is orientation-preserving and K-quasiconformal, so the second is also a K-quasidisk.

2.1F3F4F5algebra∎

If Γ=F(T) is a K-quasicircle and N is Möbius, then N(Γ)=(N∘F)(T); [F3]–[F5] show it is again a K-quasicircle. Applying the same argument to N−1 proves the reverse implication, so the admissible sets of constants for Γ and N(Γ) are identical and their infima agree.

Depends on

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