Alphabeta Math
DefinitionDefinition: Literature-sourcedProof: Not applicablePipeline-generatedjudge pass (gpt-6-sol)audited 2026-09-30
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Harmonic measure on a bounded regular plane domain

Definition

Let Ω⊆C be a bounded complex domain (A complex domain is a nonempty connected open subset of C) every boundary point of which is regular in the sense of Barriers and regular boundary points, and let z∈Ω. The Euclidean boundary ∂Ω is closed and, Ω being bounded, also bounded, hence compact (Heine-Borel in Rn: with the Euclidean metric a subset of Rn is compact if and only if it is closed and bounded, and the proof by bisection uses no choice principle; the same holds on the real line), and it carries the Borel σ-algebra (The Borel sigma-algebra of a topological space).

For every real continuous function φ:∂Ω→R, let Hφ denote the regularized Perron envelope of the bounded plane Dirichlet problem with boundary datum φ (The Perron envelope and its regularization).

A harmonic measure for Ω at z is a Radon Borel probability measure ωΩz on ∂Ω, in the sense of Radon measure on an LCH space, such that

Hφ(z)=∫∂Ωφ dωΩz for every real continuous φ:∂Ω→R.

The measure is written in the superscript slot z because it is a measure attached to the point z; for a fixed Borel set E⊆∂Ω the assignment z↦ωΩz(E) is a scalar function on Ω, a distinct object from the measure itself.

Remarks

  • Existence and uniqueness are not part of this definition. A harmonic measure for Ω at z is a Radon probability measure satisfying the displayed identity for all continuous data. Existence and uniqueness are proved later on this page, for every bounded regular plane domain and every z∈Ω; this item only fixes the object and its test identity.
  • No probabilistic interpretation is used. This library defines no Brownian motion and no hitting distribution, and none is invoked: the defining property above is the totality of what "harmonic measure" means here.
  • The test identity is linear and normalized. Taking φ≡1 in the defining identity and using that the constant function 1 solves its own Dirichlet problem gives ∫1 dωΩz=1 for every candidate measure, which is why probability measures rather than arbitrary finite measures are used.

Depends on

Used by

Dependency tree · two levels

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Sources