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Conjugate antipodes on the round sphere

Example

Assume exactly ACω through the declared constant-curvature and sphere interfaces. Let R>0, let n≥2, and give SRn={x∈Rn+1:∣x∣=R} the round metric induced from Euclidean space. Let p∈SRn, let v∈TpSRn be a unit vector, and let γ(t)=exp⁡p(tv),t∈[0,πR], be the radial unit-speed geodesic. Then γ(πR)=−p, the antipode of p, and the antipode is conjugate to p along γ with multiplicity n−1.

Facts & Assumptions

Given: The countable-choice axiom ACω; an integer n≥2; a radius R>0; a point p on the round sphere SRn; and a unit tangent vector v∈TpSRn with radial geodesic γ(t)=exp⁡p(tv) on [0,πR].

[A1]

The exact choice assumption is ACω of The Axiom of Countable Choice (ACω). It is inherited through the induced-sphere constant-curvature interface, the constant-curvature Jacobi classification, and the maximal-geodesic/parallel-extension interfaces; the rank and evaluation computations below make no selection, and no full Axiom of Choice is used.

[F1]

On the radius-R round sphere, for every point p and every unit tangent vector v the cut time is cp(v)=πR (Cut locus of a point on a round sphere, Example).

[F2]

The cut locus of every point of the radius-R round sphere is the singleton containing the antipode: Cut⁡(p)={−p} (Cut locus of a point on a round sphere, Example).

[F3]

The cut time is the supremum of the positive radial minimizing times of the unit-speed geodesic through v, and the cut locus consists of the cut-time endpoints over all unit directions; the radial endpoint at time cp(v) is therefore a point of Cut⁡(p) (Cut time in a unit tangent direction, Cut point and cut locus of a point).

[F4]

Under ACω, the maximal geodesic with initial velocity v is the curve t↦exp⁡p(tv) on its interval of definition, so the supplied γ is an affinely parametrized geodesic with γ(0)=p and γ˙(0)=v (Domain and exponential map of a connection, Geodesic of an affine connection).

[F5]

A geodesic of a metric-compatible connection has constant speed; since ∣γ˙(0)∣g=∣v∣g=1, the supplied γ has unit speed, so T:=γ˙ satisfies g(T,T)=1 and T(πR)≠0 (Geodesics have constant speed for a metric-compatible connection).

[F6]

For n≥2 the round sphere SRn with its induced metric has constant sectional curvature 1/R2 (The round sphere has positive constant sectional curvature).

[F7]

On a Riemannian manifold of constant sectional curvature K, the curvature operator is R(X,Y)Z=K(g(Y,Z)X−g(X,Z)Y) (Curvature tensor of constant sectional curvature).

[F8]

On a constant-curvature manifold of curvature K>0, along a unit-speed geodesic, the normal Jacobi fields J with J(0)=0 are exactly J(t)=sK(t)E(t), where sK(t)=sin⁡(K t)/K and E is a unique parallel normal field; the tangential Jacobi fields are exactly J(t)=(at+b)γ˙(t) with a,b∈R (Jacobi fields in constant sectional curvature).

[F9]

Metric compatibility of the Levi--Civita connection along a curve gives (g(U,V))′=g(DtU,V)+g(U,DtV) for smooth fields U,V along γ; a geodesic satisfies Dtγ˙=0 (Levi civita connection, Metric compatible connection on a riemannian vector bundle, Local frame formula for covariant differentiation along a curve, Covariant derivative along a curve).

[F10]

The trigonometric special values include sin⁡(π/2)=1 and sin⁡π=0 (Quarter-turn values and shifts by pi/2 and pi).

[F11]

Every prescribed vector at a point has a unique parallel extension to the whole interval, and a field is parallel exactly when DtE=0 (Existence and uniqueness of parallel sections, Parallel section along a curve).

[F12]

For every prescribed initial value and derivative at 0 there is exactly one Jacobi field along the interval with that data; with J(0)=0 and DtJ(0)=w the field is unique (Existence and uniqueness of jacobi fields from initial data).

[F13]

The tangent space TpM of a smooth n-manifold is an n-dimensional real vector space (The tangent space of an n-manifold has dimension n).

[F14]

The Riemannian metric is positive definite, and the map w↦gp(v,w) is a linear functional whose kernel is exactly the orthogonal complement v⊥={w∈TpM:gp(v,w)=0} (Riemannian metric and riemannian manifold, Kernel and image of a linear map).

[F15]

For a linear map of a finite-dimensional space, dim⁡V=dim⁡ker⁡T+dim⁡im⁡T (Rank-nullity: dim⁡FV=nullity⁡T+rank⁡T).

[F16]

The endpoints γ(0) and γ(πR) are conjugate along γ exactly when the space Kγ(0,πR)={J∈J(γ):J(0)=0, J(πR)=0} contains a nonzero Jacobi field, and then the multiplicity is dim⁡RKγ(0,πR) (Conjugate points along a geodesic and their multiplicity).

[F17]

A smooth field J along a geodesic is Jacobi exactly when Dt2J+R(J,γ˙)γ˙=0 (Jacobi field).

Verification

technique · locate the antipode as the cut-time endpoint, solve the scalar Jacobi equation in constant positive curvature, bound the endpoint-vanishing space by an initial-derivative injection into $v^\perp$, and match it with the $n-1$ normal zero modes
1.1F1F2F3F4F5F9

By [F4] the supplied curve γ(t)=exp⁡p(tv) is the affinely parametrized geodesic with γ(0)=p and γ˙(0)=v, and by [F5] it is unit speed, so T:=γ˙ satisfies g(T,T)=1, T(πR)≠0, and DtT=0 by the geodesic equation in [F9]. By [F1] the cut time of v is cp(v)=πR, so the radial endpoint γ(πR) is the cut-time endpoint; by [F3] it belongs to Cut⁡(p), and by [F2] Cut⁡(p)={−p}. Hence γ(πR)=−p, the antipode of p. The interval [0,πR] is nondegenerate because R>0.

1.2F6F7F8F10

By [F6] and [F7] the curvature is K=1/R2, so the constant-curvature scalar solution is sK(t)=Rsin⁡(t/R). Hence sK(0)=0, and by [F10], sK(πR)=Rsin⁡π=0 while sK(πR/2)=Rsin⁡(π/2)=R≠0.

2.1F7F9F17step 1.1

Let J be any Jacobi field along γ and put φ(t)=g(J(t),T(t)). Since DtT=0, two applications of the product rule [F9] give φ′′=g(Dt2J,T). By the Jacobi equation [F17], Dt2J=−R(J,T)T, and the constant-curvature formula [F7] gives R(J,T)T=K(g(T,T)J−g(J,T)T). Pairing with T and using g(T,T)=1 yields g(R(J,T)T,T)=K(φ−φ)=0, so φ′′=0 and φ(t)=at+b is affine.

2.2F8F9F11F15step 1.2

Conversely, fix w∈v⊥ and let E be the unique parallel field along γ with E(0)=w [F11]. Since (g(E,T))′=g(DtE,T)+g(E,DtT)=0 by [F9] and g(E(0),T(0))=g(w,v)=0, the field E is normal. The normal classification [F8] therefore makes Jw(t)=sK(t)E(t) a Jacobi field with Jw(0)=0, and step 1.2 gives Jw(πR)=sK(πR)E(πR)=0, so Jw∈Kγ(0,πR). The assignment w↦Jw is linear and injective: if Jw=0, then evaluating at πR/2 gives sK(πR/2)E(πR/2)=0, and since sK(πR/2)≠0, the parallel field E vanishes at one point, hence E=0 by uniqueness in [F11] and w=E(0)=0. Therefore dim⁡Kγ(0,πR)≥dim⁡v⊥ by [F15].

3.1F12F15step 1.1step 2.1

Suppose instead that J∈Kγ(0,πR). By step 2.1, φ=g(J,T) is affine, and φ(0)=g(0,T(0))=0 while φ(πR)=g(0,T(πR))=0; since πR>0, an affine function with two distinct zeros vanishes identically, so φ≡0. In particular g(DtJ(0),T(0))=φ′(0)=0, that is W:=DtJ(0)∈v⊥. By [F12], J is the unique Jacobi field with J(0)=0 and DtJ(0)=W, so the map J↦DtJ(0) is an injective linear map from Kγ(0,πR) into v⊥, and dim⁡Kγ(0,πR)≤dim⁡v⊥ by [F15].

4.1F13F14F15F16step 2.2step 3.1

The linear functional w↦gp(v,w) on TpM has kernel v⊥ by [F14] and is surjective because gp(v,v)>0 gives gp(v,λv)=λgp(v,v) for every λ∈R. Since dim⁡TpM=n by [F13], rank--nullity [F15] gives dim⁡v⊥=n−1. Combining the two bounds of steps 2.2 and 3.1 yields dim⁡Kγ(0,πR)=n−1. By the conjugacy definition [F16], the antipode γ(πR)=−p is conjugate to p along γ, with multiplicity n−1.

5.1A1F16step 1.1step 4.1

Boundary and choice audit. The sphere is nonempty and p is supplied, so no empty case arises; n≥2 excludes the zero- and one-dimensional spheres, where the constant-curvature normal classification [F8] would not apply with positive curvature; the parameter interval [0,πR] is nondegenerate and γ is a nonconstant unit-speed geodesic, so no constant-geodesic or degenerate-segment case occurs. The zero Jacobi field is excluded from witnessing conjugacy by [F16], and the endpoint-vanishing space is computed exactly, not merely bounded. Exactly the inherited ACω of [A1] is assumed. This example asserts conjugacy at the antipode and its multiplicity; it makes no if-and-only-if claim about geodesics other than the exhibited radial one.

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Source locator

Lee, Riemannian Manifolds: An Introduction to Curvature, Chapter 10, printed pp.179–183 / PDF labels P195–P199, Lemma 10.8 solves the constant-curvature normal Jacobi equation and the surrounding discussion records that antipodal points of the round sphere are conjugate. Datar, Lectures on Riemannian Geometry, Proposition 24.1.1, printed pp.174–175 / PDF labels P181–182, gives the same normal-field formula for space forms, and Lecture 22 §22.3 gives the endpoint-vanishing definition of multiplicity used here. The transport of the endpoint argument to the radius-R sphere, the cut-time identification of the antipode, and the rank computation of the normal space are proved locally above from the declared interfaces.

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