Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-21
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Two paths can induce distinct change-of-basepoint isomorphisms on S1S1

Example

Let W=S1S1 have wedge point w, and let zw lie on the first circle. Write a,bπ1(W,w) for the standard loops in the first and second circles. Choose a simple path ρ in the first circle from w to z, and put σ=bρ. Then ρ and σ have the same endpoints but induce distinct isomorphisms

cρ,cσ:π1(W,w)π1(W,z).

Facts & Assumptions

Given: The points, paths, and standard loop classes in the Example.

[L1]

The group π1(W,w) is the free group F(a,b) on the two standard circle loops (π1(S1S1) is the free group on two generators).

[F1]

Loop concatenation is the fundamental-group operation, and path reversal represents inversion (Loop classes form the group π1(X,x0) under concatenation).

[F2]

The reduced words on a basis and its formal inverses form the free group on that basis (Reduced words form the free group on an alphabet).

Verification

technique · direct
1.1

For a path η from w to z, define cη([α])=[ηˉαη]. Endpoint-fixed homotopies are preserved by concatenating fixed paths, while the standard cancellation homotopies for ηηˉ and ηˉη show that cη is a homomorphism with inverse cηˉ. Thus both ρ and σ define basepoint-change isomorphisms.

F1construct
2.1

Since σ=bρ, reversal of concatenation gives cσ([α])=[ρˉbˉαbρ]=cρ(b1[α]b). Hence cρˉcρ(a)=a, whereas cρˉcσ(a)=b1ab in the identification [L1].

step 1.1L1F1
3.1

The words a and b1ab are distinct reduced words by [F2]. Therefore their images under the isomorphism cρ are distinct, so cρcσ.

step 2.1F2

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

31 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.