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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-03
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Loop classes form the group π1(X,x0) under concatenation

Statement

For every pointed topological space (X,x0), the product

[α][β]=[α∗β]

is well defined and makes π1(X,x0) a group. Its identity is the class of the constant loop cx0, and [α]−1=[αˉ].

Facts & Assumptions

Given: A topological space X, a basepoint x0∈X, and based loops at x0.

[L1]

The loop-class set, concatenation order, constant loop and reversed loop are those of Based loops and the fundamental group.

[L3]

A path homotopy is a continuous map I×I→X that fixes both path endpoints throughout the homotopy (Homotopies of continuous maps, homotopies relative to a subspace, and path homotopies relative to the endpoints).

[L5]

For continuous maps into the convex line R, the straight-line formula is a continuous homotopy (For continuous maps into a convex subset of Rn, the straight-line formula defines a continuous homotopy).

[L6]

Continuous maps defined on finitely many closed sets and agreeing on overlaps paste to a continuous map (Continuity may be checked on any open cover, and on any finite closed cover; composites of continuous maps are continuous, claim 3).

[L7]

A group operation is associative, has a two-sided identity and gives every element a two-sided inverse (Group and abelian group).

Proof

technique · direct
1.1

If A is an endpoint-fixed homotopy from α0 to α1 and B one from β0 to β1, define K(s,t)=A(2s,t) for s≤12 and K(s,t)=B(2s−1,t) for s≥12; the clauses agree because A(1,t)=x0=B(0,t), and [L2], [L4], and [L6] make K continuous, so α0∗β0 and α1∗β1 are endpoint-homotopic. Thus the proposed product is independent of representatives.

L1L2L3L4L6
1.2

If ϕ:I→I is continuous with ϕ(0)=0 and ϕ(1)=1, then [L5] makes (s,t)↦(1−t)s+tϕ(s) continuous. Composing with α by [L4] gives a continuous H(s,t):=α((1−t)s+tϕ(s)); it takes values in I, fixes s=0,1, and joins α to α∘ϕ. Hence endpoint-fixing reparametrisation preserves a path class.

L3L4L5
1.3

The formula H(s,t)=α(2s(1−t)) for s≤12 and H(s,t)=α(2(1−s)(1−t)) for s≥12 is continuous by [L2], [L4], and [L6], fixes both endpoints at x0, starts at α∗αˉ, and ends at cx0; applying the same construction to αˉ contracts αˉ∗α.

L1L2L3L4L6
2.1

Put w:=(α∗β)∗γ and define ϕ(s)=s/2 for 0≤s≤12, ϕ(s)=s−14 for 12≤s≤34, and ϕ(s)=2s−1 for 34≤s≤1; [L2] makes this continuous, the clauses agree at the seams, ϕ fixes 0,1, and direct substitution gives w∘ϕ=α∗(β∗γ), so step 1.2 proves associativity on classes.

step 1.2L1L2
2.2

For ϕR(s)=min⁡{2s,1} one has α∘ϕR=α∗cx0, and for ϕL(s)=max⁡{2s−1,0} one has α∘ϕL=cx0∗α; these continuous endpoint-fixing maps and step 1.2 show that [cx0] is a two-sided identity.

step 1.2L1L2
3.1

Step 1.1 gives a well-defined operation, step 2.1 gives associativity, step 2.2 gives the identity, and step 1.3 gives the two-sided inverse [αˉ]; these are exactly the axioms in [L7], so π1(X,x0) is a group.

step 1.1step 1.3step 2.1step 2.2L7∎

Depends on

Used by

Cited to discharge well-definedness by Based loops and the fundamental group.

Dependency tree · two levels

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Sources