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A fibre foliation of a mapping torus is taut

Example

Assume Countable Choice ACω. Let L be a nonempty closed connected smooth manifold and f:L→L a diffeomorphism, with mapping torus Mf=(L×R)/Z, where k⋅(x,t)=(fk(x),t+k), and fibre foliation Ff (Mapping torus foliations realize global Reeb stable examples). Every leaf is compact and diffeomorphic to L. There is a smooth path a:[0,1]→L, constant near its endpoints, with a(1)=f(a(0)), and its graph t↦[a(t),t] descends to a smooth embedded closed transversal meeting every fibre exactly once. Consequently Ff is taut and a single closed transversal meets all its leaves.

Facts & Assumptions

Given: A nonempty closed connected smooth manifold L, a diffeomorphism f:L→L, the mapping torus Mf=(L×R)/Z with its fibre foliation Ff whose leaves are the fibres L×{t}.

[F1]

The mapping-torus foliations realize the global Reeb-stable examples: the fibres of Mf are the leaves of Ff, each diffeomorphic to L and compact (Mapping torus foliations realize global Reeb stable examples).

[F2]

A foliation is taut when every leaf admits a closed transversal (Taut codimension-one foliations), and on a nonempty compact connected manifold the leaf-by-leaf condition is equivalent to the existence of a single closed transversal meeting every leaf (A taut foliation of a compact connected manifold has a single closed transversal).

[F3]

Gluing two Reeb components gives a foliation of the three-sphere and A Reeb component obstructs tautness give the negative comparison, the non-taut Reeb foliation of S3; the standing assumption is Countable Choice ACω as recorded for this pair (The countable-choice principle used in the foliation pair).

Verification

technique · direct
1.1F3

Gluing the two standard Reeb solid tori produces the Reeb foliation of S3, with their common boundary torus a leaf and each torus a Reeb component. The Reeb-component obstruction implies that no closed transversal meets that boundary leaf, so the resulting foliation is not taut. This supplies the negative comparison directly from the general obstruction.

1.2givenconstruct

A connected smooth manifold is path connected, so join a chosen x0∈L to f(x0) by a finite smooth chartwise path, smooth its finitely many corners and reparametrize it to be constant near 0 and 1; this gives a smooth path a:[0,1]→L with a(0)=x0, a(1)=f(x0) and stationary ends.

2.1F1step 1.2

Extend a by a(t+k)=fk(a(t)); the stationary ends make the extension smooth across every integer, and the graph t↦[a(t),t] is periodic under the diagonal mapping-torus action k⋅(x,t)=(fk(x),t+k), hence descends to a smooth closed curve in Mf.

3.1F1step 2.1

The descended curve is embedded because its composition with the base projection S1→S1 is the identity, so distinct parameters have distinct images; its derivative has base component 1, so it is everywhere positively transverse to the fibre foliation Ff.

4.1F2step 3.1

The curve meets every fibre exactly once, because the base component of its parametrization runs monotonically once around the circle; hence the leaf-by-leaf condition of tautness holds for Ff directly, with no fixed point of f assumed.

5.1F2F3step 4.1∎

Since L is nonempty, Mf is nonempty, compact and connected, [F2] upgrades the leaf-by-leaf condition to a single closed transversal meeting every leaf, so Ff is taut and a single closed transversal meets all its leaves. This verifies the positive model dual to the non-taut Reeb foliation example [F3], and the construction uses one finite chartwise path, hence only the standing countable choice from [F3].

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