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Fixed-trace and free-trace variations give different boundary equations

Example

Example. Assume the Axiom of Choice (The Axiom of Choice). Let Ω⊆Rn, n≥2, be a bounded C1 domain, let f∈L2(Ω;R), and put I(u)=12∫Ω∣Du∣2 dx−∫Ωfu dx. (a) Fixed trace: a local minimiser in the H1 norm on the nonempty affine class Kg={v∈H1(Ω):Tv=g}, with g∈H1/2(∂Ω), solves the weak Dirichlet problem −Δu=f, Tu=g (The Dirichlet principle for the Poisson equation, The affine Dirichlet trace class is nonempty, convex and weakly closed). (b) Free trace: if u∈C2(Ω‾) is a local minimiser in the C2 norm on C2(Ω‾), then −Δu=f almost everywhere in Ω and ∂νu=0 on ∂Ω. Choosing the continuous representative f=−Δu makes the interior equation pointwise. This is the boundary condition suggested by The natural boundary condition for free boundary variations, proved directly here since a general L2 forcing need not give a C2 integrand.

The constant-shift identity is I(u+c)=I(u)−c∫Ωf. Thus I is invariant under global constants exactly when ∫Ωf=0, and it is never coercive on all of H1(Ω). If ∫Ωf≠0, no free local minimiser exists. On a connected domain satisfying the extension-domain hypothesis of Weak Neumann solvability on the mean-zero subspace, zero-mean forcing gives a unique mean-zero weak Neumann solution; nonzero mean cannot be repaired merely by normalising the solution. On a disconnected domain compatibility is required on each component and the additive constants are independent on those components.

Facts & Assumptions

Given: The Axiom of Choice; the real domain and data above; local minimality in H1 on Kg in (a), or in C2 on the whole C2 space in (b).

[F1]

The fixed-trace class is a translate of H01(Ω); its admissible directions are exactly that subspace (The affine Dirichlet trace class is nonempty, convex and weakly closed). The weak Euler–Lagrange identity holds for these directions (The weak Euler-Lagrange equation for integral functionals with fixed trace).

[F2]

The Dirichlet principle identifies its energy minimiser with the unique weak Poisson solution (The Dirichlet principle for the Poisson equation).

[F3]

First Green identity holds for u∈C2(Ω‾) and smooth tests under Countable Choice, supplied by AC (First Green identity). A locally integrable function pairing to zero with all compactly supported tests is zero almost everywhere (The fundamental lemma of the calculus of variations). A continuous boundary flux pairing to zero with all ambient smooth tests vanishes on the boundary (The boundary fundamental lemma of the calculus of variations).

[F4]

The Neumann supplier requires a bounded connected extension domain and a bounded forcing functional F with F(1)=0; it gives a unique mean-zero solution and all other solutions differ by constants. It also records the componentwise compatibility needed in the disconnected case (Weak Neumann solvability on the mean-zero subspace).

[F5]

Holder makes v↦∫fv bounded on H1, and bounds all terms in the quadratic expansion below (Holder's inequality for integrals, including the endpoint cases). Fermat's theorem gives a zero derivative at a two-sided interior local minimum (Fermat's interior extremum theorem: if f has a local extremum at a point c interior to its domain and is differentiable at c, then f′(c)=0).

Verification

1.1F1F2F5givenalgebra

Fixed trace. For every φ∈H01(Ω), the curve u+tφ stays in Kg by [F1]. Its energy is exactly I(u)+t∫(Du⋅Dφ−fφ)+12t2∫∣Dφ∣2. Local minimality and [F5] give ∫Du⋅Dφ=∫fφ, the weak Dirichlet equation. Moreover the same expansion at t=1 shows I(u+φ)−I(u)=12∫∣Dφ∣2≥0, so this local minimiser is global and [F2] applies.

1.2F3F5given

Free trace. For every φ∈C∞(Ω‾), the curve u+tφ is admissible and close to u in the C2 norm as t→0. The same quadratic expansion and [F5] give ∫(Du⋅Dφ−fφ)=0. For compactly supported tests, Green identity [F3] then yields ∫(−Δu−f)φ=0, so −Δu=f almost everywhere by the fundamental lemma. Returning to arbitrary smooth tests gives ∫∂Ω(∂νu)φ=0 by Green identity; the continuous field Du and the boundary fundamental lemma force ∂νu=0.

2.1F4F5step 1.2algebra∎

Constants and compatibility. Direct expansion gives I(u+c)=I(u)−c∫f. If ∫f≠0, arbitrarily small constant shifts in the appropriate sign lower the energy, and large shifts make it tend to −∞; if ∫f=0, arbitrarily large shifts leave it fixed. In both cases coercivity on the full space fails. In case (b), testing the first variation with 1 gives ∫f=0. At each boundary point the one-sided C1 graph convention gives a smaller connected subgraph neighbourhood meeting only one component; at interior points use a ball in the component. Thus a component indicator extends locally constantly to Ω‾ and is a C2 admissible direction, giving the componentwise condition. Under the connected extension-domain hypotheses of [F4], the functional F(v)=∫fv is bounded by [F5] and satisfies F(1)=0 precisely for zero-mean forcing, so [F4] supplies the normalised weak solution.

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