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GIT quotients of the projective line for different linearizations

Example

Assume AC inherited from the Proj, cohomology and quotient suppliers (The Axiom of Choice); the explicit weight and orbit computations make no additional choice.

Let G=Gm=C× act on X=P1=P(Ce0⊕Ce1) by t⋅[e0:e1]=[t−1e0:te1], so that the fixed points are [1:0] and [0:1], and let L=OP1(1) with the standard linearization L0 for which the monomial e0ie1n−i is an eigenvector of weight 2i−n in Γ(X,L⊗n) (G-linearizations of invertible sheaves on a complex G-variety). Then:

(i) for L0 the invariant sections are the multiples of (e0e1)n/2 for even n, so Xss(L0)=Xs(L0)={[e0:e1]:e0e1≠0}≅Gm; the action on this locus is transitive with finite stabilizer μ2={t∈Gm:t2=1} at every point, so every orbit is closed there, and X/ ⁣/L0G is a one-point scheme, so the quotient is a geometric quotient onto a point (Good and geometric quotient on the stable locus);

(ii) for the twist L+=L0⊗χ by the character χ(t)=t the invariant sections of L+⊗n are the multiples of e1n, so Xss(L+)={e1≠0}≅A1 and Xs(L+)=∅: the fixed point [0:1] has stabilizer G and lies in the closure of every other orbit, so the good quotient Xss(L+)→Proj⁡C[e1] collapses the affine line to a point and is not geometric;

(iii) for the twist L−=L0⊗χ−1 the roles of the two charts are exchanged: Xss(L−)={e0≠0}≅A1, Xs(L−)=∅; for k∈Z with ∣k∣≥2 the twist L0⊗χk has no nonzero invariant section of positive degree, so Xss=∅ and the GIT quotient is the empty scheme;

(iv) all these linearizations have the same underlying ample invertible sheaf O(1) and the same action on X, so the example shows the dependence of (Xss,Xs,π) on the linearization alone; the standard case with n=1 is the computation of Newstead's Example 4.1 (stated there for n≥2; for n=1 the same argument gives (Pn)ss=(Pn)s≅Cn∖{0} and quotient Pn−1, which for n=1 is a point) and of Hoskins' Example 5.8 with n=1.

Facts & Assumptions

Given: AC inherited from the Proj, cohomology and quotient suppliers; the action t⋅[e0:e1]=[t−1e0:te1] of G=Gm on X=P1, the sheaf L=O(1) with its standard linearization L0, and the twists L0⊗χk by the characters χk, k∈Z.

[F1]

Sections and weights. By Cohomology of O(d) on projective space, Γ(X,L⊗n)=C[e0,e1]n, and for the standard linearization L0 the monomial e0ie1n−i is an eigenvector of weight 2i−n; twisting by χ adds n to the weight and twisting by χ−1 subtracts n, so for L0⊗χk the weight of e0ie1n−i is 2i−n+kn. This follows from the contragredient action on coordinate linear forms: their weights are 1,−1, while the fibre twist multiplies the section action in tensor degree n by tkn. (G-linearizations of invertible sheaves on a complex G-variety, Twisting sheaf on Proj)

[F2]

Semistability and quotients. A point is semistable for a linearized ample sheaf exactly when some invariant section of a positive tensor power does not vanish there; the quotient is Proj⁡ of the invariant section ring, the charts are the nonvanishing loci of invariant sections, and the restriction of the quotient to the stable locus is geometric. (Semistable and stable points for a linearization, The invariant section ring and the projective GIT quotient, The projective GIT quotient from the invariant section ring, Good and geometric quotient on the stable locus)

[F3]

Projective line computations. G=Gm is reductive: its rational modules decompose into character spaces by Torus rational modules and affine actions are lattice gradings, so it is linearly reductive and hence reductive by Complete reducibility and the Reynolds operator for a complex reductive group. L=O(1) is ample: its coordinate sections have nonvanishing loci equal to the two standard affine charts, which cover X; the invariant ring of a linearized L0⊗χk is the span of the monomials of weight zero, and Proj⁡C[u] is a one-point scheme whether deg⁡u=1 or 2: its only chart D+(u) has ring C[u,u−1]0=C (Standard opens are affine). Also Proj⁡C=∅ by Points of Proj of a graded ring. The stabilizer of [0:1] under the given action is all of G, so the point is never stable. (Absolute ampleness by affine section opens, projective variety classical)

Verification

1.1F1F2F3algebra

The standard linearization (i). By [F1] the weight of e0ie1n−i in L0⊗n is 2i−n, which vanishes exactly when i=n/2; hence the invariant sections of positive degree are the multiples of (e0e1)n/2 for even n, and the invariant section ring is C[e0e1]. Therefore Xss(L0)={e0e1≠0}, the complement of the two fixed points, and X/ ⁣/L0G=Proj⁡C[e0e1], a one-point scheme. On the locus e0e1≠0 write z=e0/e1; then z↦t−2z, so the action is transitive onto C× with stabilizer μ2 at every point, and the unique orbit is the whole locus and is therefore closed there. Hence Xs(L0)=Xss(L0)≅Gm, and by [F2] the good quotient restricts to a geometric quotient onto the point.

1.2F1F2F3algebra

The twist by χ (ii). By [F1] the weight of e0ie1n−i in L+⊗n is 2i, so the invariant sections of positive degree are the multiples of e1n and the invariant ring is C[e1]; hence Xss(L+)={e1≠0}≅A1 and X/ ⁣/L+G=Proj⁡C[e1] is a point, so the quotient collapses the affine line to a point. The point [0:1] (that is, z=0 in the coordinate z=e0/e1) is fixed with stabilizer G, and every other orbit z≠0 has closure containing 0, so no point of Xss(L+) is stable: Xs(L+)=∅ and the quotient is not geometric.

2.1F1F2F3algebra

The opposite twist and the higher twists (iii). For L−=L0⊗χ−1 the weight is 2i−2n, vanishing exactly for i=n; the invariant sections are the multiples of e0n, the invariant ring is C[e0], and Xss(L−)={e0≠0}≅A1 with Xs(L−)=∅ by the same fixed-point argument as in step 1.2. For k≥2 the weight is 2i−n+kn, which vanishes only for i=n(1−k)/2<0, impossible for a monomial; for k≤−2 it vanishes only for i=n(1−k)/2>n, also impossible. Hence for ∣k∣≥2 there is no nonzero invariant section of positive degree, Xss(L0⊗χk)=∅, and the quotient is Proj⁡C=∅.

3.1step 1.1step 1.2step 2.1F2∎

Conclusion (iv). All the linearizations considered have the same underlying ample sheaf O(1) and the same action on X: the standard linearization gives the nonempty stable locus Gm with quotient a point, the two single twists give the two affine lines with non-geometric one-point quotients and empty stable loci, and the remaining twists give the empty quotient. This exhibits the dependence of the GIT data on the linearization alone and matches the computations in Newstead's Lecture 4 example (stated there for n≥2, with the same argument at n=1) and in the corresponding example of Hoskins' notes.

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