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A locally integrable density functional is represented by g dlambda
Example
Let , assume the Axiom of Countable Choice, and let be locally integrable on . Then is a positive linear functional on represented by the Radon measure .
Facts & Assumptions
Given: , the Axiom of Countable Choice, and locally integrable.
Verification
If has support , then . Hence is well defined and linear; it is positive because .
The density construction makes [given] a Borel measure. Every compact set is contained in a ball, so local integrability makes finite on compact sets. Moreover, is LCH, and its rational open boxes form a countable basis. The second-countable regularity theorem therefore makes regular, hence Radon. Its defining integral gives , so RMK uniqueness identifies it as the representing measure.
Depends on
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Second countability: an at most countable basis for the topology
- Positive functionals on C_c(X) are integration against a Radon measure
- Uniqueness of the RMK representing measure among Radon measures
- A locally integrable function on $\mathbb{R}^n$
- The measure with density $f$ relative to $\mu$
- Lebesgue measure is a Radon measure on R^n
- $\mathbb{R}^n$ is locally compact and $\sigma$-compact
- $\mathbb{Q}^n$ is a countable dense subset of $\mathbb{R}^n$, and rational open boxes form a countable basis
- Locally finite Borel measures on second-countable LCH spaces are regular
Used by
Nothing in the library uses this result yet.
Dependency tree · two levels
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Sources
- Donald L. Cohn, Measure Theory, 2nd ed., Chapter 7 (standard reference, not scraped)