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A signed Simpson-Smolyak weight makes a nonnegative chaos coefficient estimate negative

Example

For k=1,…,8, put ϕ(x)=∏k=18(1−8x/k)2 on [0,1] and u(x,y)=ϕ(x)ϕ(y). This is a nonnegative polynomial. Under the uniform law on [0,1]2, the constant polynomial-chaos coefficient is c00=∫[0,1]2u>0. Yet the level-two composite-Simpson Smolyak rule on Λ2={(i,j):i+j≤2} returns −1/144. This shows why signed Smolyak weights matter when integrating chaos coefficients. Any tensor product of Gaussian rules with positive coordinate weights returns a nonnegative value on u; no Gaussian exactness for this high-degree polynomial is asserted.

Facts & Assumptions

Given: The uniform probability law on [0,1]2, ϕ(x)=∏k=18(1−8x/k)2, u(x,y)=ϕ(x)ϕ(y), the constant chaos basis Ψ00=1, and the Simpson hierarchy of Nested one-dimensional quadrature levels and differences.

[F1]

Nested one-dimensional quadrature levels and differences: Qℓ=QS(⋅;0,1,2ℓ+1), Δ0=Q0, and Δℓ=Qℓ−Qℓ−1.

[F2]

Composite Simpson rule on an even uniform grid: the endpoint weight at level ℓ is 1/(3⋅2ℓ+1), and the other weights are nonnegative.

[F3]

Smolyak cubature on a finite downward-closed index set: for Λ2={(i,j):i+j≤2}, the Smolyak functional is the sum of its six tensor details.

[F5]

A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion: a continuous function on a nondegenerate closed interval is Riemann integrable.

[F8]

The integral of a product function on a product rectangle is the product of the two integrals: the integral of a product function on a product rectangle factors into the coordinate integrals.

[F9]

The m-node Gaussian quadrature rule for a positive measure: a Gaussian rule returns a finite weighted sum of samples.

[F10]

Gaussian quadrature is exact through degree 2m−1 and has positive weights: for valid positive-measure moment data, every Gaussian weight is strictly positive.

[F11]

Tensor-product Gaussian quadrature: tensor weights are products of coordinate weights.

[F12]

Finite sums and finite products, by recursion and Laws of finite sums and finite products: finite sums distribute; finite sums and finite products of nonnegative terms are nonnegative.

[F13]

By trichotomy, every real z is zero, positive, or negative. Its square is 0 in the zero case, positive by Sign rules for products and monotonicity of multiplication in the positive case, and positive in the negative case because (−z)>0 and (−z)2=z2 by Sign rules for products: (−a)b=−(ab) and (−a)(−b)=ab. Thus every real square is nonnegative; Multiplication by zero: 0⋅a=0 supplies the zero case.

Verification

1.1givenF4F5F6F7F8F12F13choose

Every real square is nonnegative by [F13], so each factor in ϕ is nonnegative and [F12] gives ϕ(x)≥0 on [0,1]. The polynomial ϕ is continuous by [F4] and satisfies ϕ(0)=1. Continuity at zero gives η>0 such that ϕ(x)>1/2 for 0≤x<η; choose δ=min⁡(η/2,1/2), so 0<δ<η and δ<1. By [F5]–[F6], ∫0δϕ≥δ/2 and ∫δ1ϕ≥0; [F7] then gives ∫01ϕ≥δ/2>0. Applying [F8] to the continuous coordinate factors establishes integrability of u and gives c00=(∫01ϕ)2>0.

2.1givenF1F3F12F13step 1.1algebra

For each m=0,…,8, ϕ(m/8)=0 when m>0, because the factor indexed by k=m vanishes; ϕ(0)=1. The nested Simpson grids through level two are X0={0,1/2,1}, X1={m/4:0≤m≤4}, and X2={m/8:0≤m≤8}. Thus every sampled value of u on any tensor rule in Λ2 vanishes except at (0,0), where it is one; all sampled values are nonnegative by [F13] and [F12].

3.1givenF1F2F3F12step 2.1algebra

Let wℓ be the level-ℓ endpoint weight. By [F2], w0=1/6, w1=1/12, and w2=1/24. Expanding the six details from [F3] and using finite distributivity [F12] gives QΛ2=Q2⊗Q0+Q0⊗Q2−Q1⊗Q0−Q0⊗Q1+Q1⊗Q1. By step 2.1, its value on u is the combined coefficient at (0,0): 2w2w0−2w1w0+w12=2/(24⋅6)−2/(12⋅6)+1/122=−1/144<0. This differs in sign from c00>0 in step 1.1.

4.1givenF9F10F11F12F13step 3.1algebra∎

For tensor products of Gaussian rules with valid positive-measure moment data, [F10] makes every coordinate weight positive and [F11] makes each tensor weight a product of positive numbers. Since all samples of u are nonnegative by [F12]–[F13], [F9] and [F12] make the resulting finite sum nonnegative. Together with the negative Simpson estimate in step 3.1, this is a sign comparison; it does not claim that such a Gaussian rule exactly integrates u.

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