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The punctured line has a weight-two logarithmic class

Example

Assume AC (The Axiom of Choice). For U=C×⊂P1, H1(U,Q)=Q(−1), of weight 2 and type (1,1). In particular its weight is strictly larger than its cohomological degree.

Facts & Assumptions

Given: The Axiom of Choice; the smooth quasiprojective curve U=C×=P1(C)∖{0,∞} with its SNC compactification j:U↪X=P1, boundary D={0}⊔{∞} (Simple normal crossings divisors and simultaneous normal crossings position).

[F1]

The strata of the compactification. D[0]=X=P1, D[1]=D is the disjoint union of the two points 0 and ∞, and D[a]=∅ for a≥2; all are smooth projective complex varieties of pure dimensions 1 and 0. The two projective coordinate charts identify the analytic space of P1 with the Riemann sphere, homeomorphic to S2 by Stereographic projection identifies the Riemann sphere with the unit two-sphere. Under C≅R2, For n≥1, radial normalisation is a deformation retraction of Rn∖{0} onto Sn−1 gives the deformation retraction H(z,t)=((1−t)+t/∣z∣)z onto S1, so inclusion induces a homology isomorphism by Singular homology is invariant under deformation retracts.

[F2]

Cohomology of spheres (Homology of spheres, Cohomology over a field is dual to homology over that field). Over Q, H0(S1)=H1(S1)=Q and Hn(S1)=0 otherwise, and the same pattern holds for S2 in degrees 0 and 2; over the field Q evaluation identifies Hn(−;Q) with the full linear dual of Hn(−;Q). Hence H0(S1;Q)=H1(S1;Q)=Q with higher groups zero, and H0(S2;Q)=H2(S2;Q)=Q with H1(S2;Q)=0; a point and a two-point space have cohomology Q and Q2 in degree 0 and zero in positive degrees.

[F3]

The logarithmic mixed Hodge structure (Logarithmic construction of smooth-open mixed Hodge structures). For the SNC compactification of [F1] the logarithmic complex endows Hn(U;Q) with its weight filtration W, of weights at least n, satisfying WnHn(U;Q)=im⁡(Hn(X;Q)→Hn(U;Q)), with weight spectral sequence E1−a,q=Hq−2a(D[a];Q)(−a)⇒Hq−a(U;Q) degenerating at E2 and Gr⁡mWHn(U;Q)≅E2n−m,m; the local residue normalization of that construction assigns to the closed logarithmic form dz/z on U the rational class (2πi)−1dz/z∈H1(U;Q), whose normalized rational residue coordinates at 0 and at ∞ are 1 and −1; the ordinary analytic residue of the normalized form is (2πi)−1 times the corresponding coordinate.

[F4]

Tate twist and type (Rational mixed Hodge structures). The Tate structure Q(−1) is the pure rational Hodge structure of weight 2 and type (1,1), concentrated in H1,1; a mixed Hodge structure whose weight-graded pieces are Gr⁡2W=Q(−1) and Gr⁡mW=0 for m≠2 is pure of weight 2 and type (1,1).

[A1]

AC is assumed and is consumed only through [F3] and its suppliers; the finite computations below are choice-free. (The Axiom of Choice)

Verification

technique · direct: compute both sides of the weight spectral sequence of the logarithmic complex for $\mathbb P^1$ and identify the surviving degree-one term with the Tate twist
1.1F1F2givenalgebra

The two cohomologies. By [F1] and [F2], H0(X;Q)=Q, H1(X;Q)=0, H2(X;Q)=Q; H0(D[1];Q)=Q2 and H1(D[1];Q)=0; and H0(U;Q)=Q, H1(U;Q)=Q, H2(U;Q)=0, the generator being the meridian class dual to the circle.

2.1F3step 1.1algebra

The logarithmic generator. By the residue normalization of [F3] the class (2πi)−1dz/z is a nonzero rational class in H1(U;Q) pairing by 1 with the positively oriented meridian, so it generates the one-dimensional space H1(U;Q) of step 1.1; its normalized rational residue coordinates at 0 and ∞ are 1 and −1, because in the coordinate w=1/z at infinity the form dz/z equals −dw/w.

3.1F3step 1.1step 2.1algebra

The weight spectral sequence. Only a=0,1 contribute. The a=0 column has E10,0=Q(0), E10,1=0, E10,2=H2(P1;Q)=Q(−1), pure of weight 2 and type (1,1); the a=1 column has E1−1,2=Q(−1)2 and is otherwise zero. The sole possible nonzero differential is d1:E1−1,2→E10,2, a pure Hodge morphism. Since the sequence degenerates at E2 and H2(U)=0 by step 1.1, its cokernel is zero, so its rank is one. The global closed logarithmic form of step 2.1 has normalized residue vector (1,−1), which must survive this differential because it represents an actual cohomology class; hence this vector lies in its kernel. A rank-one map from a two-dimensional space has one-dimensional kernel, so ker⁡d1=Q(1,−1)≅Q(−1). Equivalently, in a rational target generator normalized to the nonzero image of (1,0), d1(r0,r∞)=r0+r∞. Thus E2−1,2=Q(−1), E20,2=0, E20,0=Q(0), and all remaining terms vanish. This computes the required weight-graded piece without assuming an unproved Gysin normalization.

4.1F3F4step 2.1step 3.1algebra

The mixed Hodge structure on H1(U,Q). By [F3] the weight-graded piece Gr⁡mWH1(U;Q) is E21−m,m, so by step 3.1 it is Q(−1) for m=2 and vanishes for every other m; in particular W1H1(U;Q)=0 and W2H1(U;Q)=H1(U;Q), which also agrees with the weights-at-least-1 and image formulas of [F3] and with H1(X;Q)=0 from step 1.1. By [F4] the class supported in weight 2 with Gr⁡2W=Q(−1) makes H1(U;Q) pure of weight 2 and type (1,1), so H1(U,Q)=Q(−1); the classical generator (2πi)−1dz/z of step 2.1 is a rational class of this structure.

5.1A1F4step 2.1step 4.1given∎

Conclusion and boundaries. The weight of H1(U,Q) is 2, strictly larger than the cohomological degree 1, and the only nonzero Hodge number is h1,1=1. The space U is nonempty and disconnected cases do not arise; H0 and H2 of U are handled by step 1.1 and carry weights 0 and at most 2; the two residue coordinates are the two components of D, and the kernel computation is finite linear algebra over Q; no choice beyond [A1] is used.

Remarks

The example is a leaf. It consumes the full logarithmic mixed Hodge theorem, including the normalized rational comparison, the shifted weight spectral sequence and its Hodge-compatible abutment; the pure type (1,1) conclusion requires that full supplier, rather than only its vector-space spectral sequence. The ordinary analytic residues of dz/z are (1,−1); after multiplication by (2πi)−1 the normalized rational coordinates still are (1,−1), while the analytic residues themselves are scaled. AC is carried explicitly in the statement because it is inherited through the theorem.

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