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The upper half-plane Poisson boundary density

Example

Assume the Axiom of Countable Choice for the Lebesgue measure and integral interface and the locally uniform harmonic-limit theorem. For z=x+iy∈H={z:Im⁡z>0} put kz(t):=yπ((t−x)2+y2)(t∈R). Then dωHz(t)=kz(t) dt is a Borel probability measure on R of total mass one, and for every bounded continuous f:R→R the function uf(z):=∫Rf(t) kz(t) dλ1(t) is harmonic on H and satisfies lim⁡z→t0, z∈Huf(z)=f(t0) at every finite boundary point t0∈R. The density identity and the arctangent antiderivative are choice-free calculations. The measure and integral interface and the locally uniform harmonic-limit theorem use ACω. This is an explicit unbounded-domain analogue of harmonic measure; the bounded-domain boundary-transport theorem is not invoked.

Facts & Assumptions

Given: A point z=x+iy∈H, the Axiom of Countable Choice ACω for the Lebesgue interface and harmonic-limit theorem (The Axiom of Countable Choice (ACω)), and the unit disc D, the upper half-plane H and modulus as in The unit disc, the upper half-plane, and Blaschke factors and Real and imaginary parts, complex conjugation, and modulus.

[F1]

The Poisson kernel of the disc is P(w,ζ)=(1−∣w∣2)/∣ζ−w∣2 for w∈D, ζ∈∂D, and for every continuous ψ:∂D→R its Poisson integral is harmonic on D, continuous on D‾, and agrees with ψ on ∂D (The Poisson kernel on the unit disc, The Poisson integral gives the unique continuous harmonic extension on the closed unit disc).

[F2]

If u is harmonic on an open V⊆C and ϕ:U→V is holomorphic on an open U, then u∘ϕ is harmonic on U (Plane harmonicity is preserved by holomorphic and antiholomorphic changes of coordinate).

[F3]

The principal inverse tangent arctan⁡:R→(−π/2,π/2) is the continuous strictly increasing inverse of the tangent principal branch, with ddxarctan⁡x=11+x2 and arctan⁡x=∫0xdt1+t2; consequently arctan⁡s→±π/2 as s→±∞, because the tangent branch is strictly increasing and onto R (The principal inverse tangent arctan⁡:R→(−π/2,π/2), Principal arctangent: derivative, integral, power series, and the Gregory–Leibniz series, Tangent is a continuous strictly increasing bijection from (−π/2,π/2) onto R).

[F4]

One-dimensional change of variables: if φ is C1 and injective with φ′≠0 on a neighbourhood of [a,b], and g is continuous on an interval containing φ([a,b]), then ∫min⁡{φ(a),φ(b)}max⁡{φ(a),φ(b)}g(s) ds=∫abg(φ(t))∣φ′(t)∣ dt (In one dimension the compact-Jordan formula is substitution over the unoriented image interval with the absolute derivative); a continuous real function on a compact interval is Riemann integrable (A continuous function on [a,b] is Riemann integrable, by Heine-Cantor and Riemann's criterion).

[F5]

Under ACω the Lebesgue measure λ1 is a complete measure on a sigma-algebra containing the Borel sets; for a nonnegative measurable ρ the set function A↦∫Aρ dλ1 is a measure; and if a nonnegative f is Riemann integrable on every compact interval and its improper Riemann integral converges, then f is Lebesgue integrable with equal integrals (Lebesgue measurable sets, the family L(Rn), and the restricted set function λn, Assuming countable choice, L(Rn) is a sigma-algebra containing every elementary set and λn is a complete measure extending elementary volume, The indefinite integral of a nonnegative measurable function is a measure, A nonnegative improper Riemann integral on a half-line agrees with the Lebesgue integral).

[F6]

Under ACω, a locally uniform limit of harmonic functions on a domain is harmonic (Locally uniform limits of harmonic functions are harmonic).

Verification

technique · direct
1.1F3algebra

Define the Cayley map C(w):=(w−i)/(w+i), which is holomorphic on C∖{−i} and in particular on H, and satisfies ∣C(w)∣<1 for w∈H because ∣w+i∣2−∣w−i∣2=4Im⁡w>0. For real t one computes C(t)=(t−i)2t2+1=t2−1−2tit2+1=eiθ(t),θ(t):=2arctan⁡t−π∈(−2π,0), so ∣C(t)∣=1, C(t)≠1, and by the chain rule and [F3] C′(t)=2i(t+i)2,∣C′(t)∣=2t2+1=θ′(t).

1.2F3F4F5algebra

For every R>0 the substitution s=(t−x)/y on [−R,R], which is admissible by [F4] with φ(t)=(t−x)/y and g(s)=1/(π(1+s2)), gives ∫−RRkz(t) dt=1π(arctan⁡R−xy−arctan⁡−R−xy), and letting R→∞ with [F3] yields the improper Riemann integral ∫Rkz dt=1. Since kz is continuous and nonnegative, [F5] makes kz Lebesgue integrable with ∫Rkz dλ1=1.

2.1F1F3step 1.1algebra

For w∈H and real t, direct expansion gives 1−∣C(w)∣2=4Im⁡w∣w+i∣2,∣C(t)−C(w)∣=2∣t−w∣∣t+i∣ ∣w+i∣, the second identity because (t−i)(w+i)−(w−i)(t+i)=2i(t−w). Multiplying, and using [F1], [F3] and step 1.1, P(C(w),C(t)) ∣C′(t)∣2π=4y∣w+i∣2⋅∣t+i∣2∣w+i∣24∣t−w∣2⋅22π(t2+1)=yπ((t−x)2+y2)=kz(t) whenever w=z=x+iy.

2.2F5step 1.2

By [F5] the set function ωz(A):=∫Akz dλ1, defined on the Lebesgue sigma-algebra and hence on the Borel sets of R, is a measure, and ωz(R)=1 by step 1.2. So dωHz=kz dλ1 is a Borel probability measure on R.

3.1F1F2F4step 1.1step 2.1

Representation for compactly supported data. Let f be continuous with compact support and define ψ on ∂D by ψ(ζ):=f(i(1+ζ)/(1−ζ)) for ζ≠1 and ψ(1):=0; this is well defined with C-values on the unit circle, and it is continuous: near ζ=1 one has ∣1+ζ∣≥2−∣1−ζ∣, so the parameter i(1+ζ)/(1−ζ) tends to infinity and ψ vanishes there because f does, while continuity away from 1 follows from continuity of f and of ζ↦i(1+ζ)/(1−ζ). Let uD be the Poisson integral of ψ and u:=uD∘C on H. Then u is harmonic by [F2], and for z∈H the definition of the Poisson integral, the identity ψ(C(t))=f(t) and step 2.1 give u(z)=12π∫02πψ(eiθ)P(C(z),eiθ) dθ=12π∫Rf(t)P(C(z),C(t))∣C′(t)∣ dt=∫Rf dωHz, the middle equality being the substitution θ=θ(t) of step 1.1 on a compact parameter interval, legitimate by [F4] and the vanishing of the integrand near the ends 0 and −2π of the period interval, together with 2π-periodicity.

4.1F1step 3.1

Boundary limits for compactly supported data. If zj→t0 with t0∈R and zj∈H, then C(zj)→C(t0)∈∂D∖{1} by continuity of C at t0, and uD is continuous on D‾ with boundary values ψ by [F1]; hence u(zj)=uD(C(zj))→ψ(C(t0))=f(t0) by step 3.1.

4.2F6step 3.1algebra

General bounded continuous data. Let f be bounded and continuous and let χN:R→[0,1] be continuous with χN=1 on [−N,N] and χN=0 outside [−N−1,N+1] (for instance χN(t)=max⁡{0,min⁡{1,N+1−∣t∣}}). Each fN:=fχN is continuous with compact support, so ufN is harmonic on H by step 3.1. If K⊆H is compact and R is such that ∣w∣≤R on K, then for N>2R and w=x+iy∈K the tail bound ∫∣t∣>Nkw(t) dt≤2Rπ∫N∞4t2 dt=8RπN holds, because ∣t−x∣≥∣t∣−R≥∣t∣/2 and (t−x)2+y2≥(t−x)2 there; hence ∣uf−ufN∣≤∥f∥∞⋅8R/(πN) on K and ufN→uf locally uniformly on H. Therefore uf is harmonic on H by [F6].

5.1F3step 1.2step 4.2algebra

Boundary limits for general data. Fix t0∈R and η>0. Continuity of f at t0 gives δ>0 with ∣f(t)−f(t0)∣<η for ∣t−t0∣<δ. Splitting the defining integral at ∣t−t0∣=δ and using ∫Rkz=1 from step 1.2, ∣uf(z)−f(t0)∣≤η+2∥f∥∞∫∣t−t0∣≥δkz(t) dt, and the last integral equals 1π(π−arctan⁡t0+δ−xy+arctan⁡t0−δ−xy), which tends to 0 as x→t0, y↓0 by [F3], since then (t0±δ−x)/y→±∞. Hence uf(z)→f(t0) as z→t0 inside H.

6.1F5F6step 2.1step 2.2step 4.2step 5.1∎

The density kz therefore defines a Borel probability measure of total mass one on R (step 2.2) whose integrals produce, for every bounded continuous boundary function, a harmonic function with the prescribed limit at every finite boundary point of H (steps 4.2 and 5.1). Steps 1.2 and 2.2 use ACω through the measure and integral interface of [F5], as does the integral interpretation in step 3.1; step 4.2 also uses it through the locally uniform harmonic-limit theorem [F6], while steps 1.1, 2.1 and the arctangent limits are choice-free calculations.

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