Alphabeta Math
False statementConstruction: AI-adaptedVerification: AI-adaptedPipeline-generatedaudited 2026-09-22
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Peter–Weyl gives density, not finite equality

Statement

Assume the Axiom of Choice. Every continuous function on a compact Lie group is a finite sum of matrix coefficients.

Facts & Assumptions

Given: Assume the Axiom of Choice; the group G=S1=R/Z.

[L1]

Finite linear combinations of matrix coefficients are uniformly dense in C(G) (Matrix coefficients are uniformly dense in C(G)).

[L2]

Every finite-dimensional continuous complex representation of a compact group is unitarizable and completely reducible. For an irreducible representation of the abelian group S1, every representing operator is an equivariant endomorphism and hence is scalar, so irreducibility forces dimension one; the resulting characters are exactly zzn, nZ (Finite-dimensional compact-group representations are unitarizable, Complete reducibility for compact Lie groups, Over an algebraically closed field, every endomorphism of an irreducible representation is scalar, Characters are the integral weights, The one-dimensional torus and its normalized Haar integral).

Refutation

technique · direct
1.1

By [L2] every finite-dimensional continuous representation of S1 is a direct sum of characters zzn, so all of its matrix coefficients are finite linear combinations of those characters. Hence every finite sum of matrix coefficients is a function of the form θp(eiθ) for a Laurent polynomial p, which is smooth in the real variable θ.

L2
2.1

The continuous function f(eiθ):=θ for θ(π,π] on S1 is not differentiable at θ=0, while every function θp(eiθ) with p a Laurent polynomial is differentiable there; hence f is not a finite sum of matrix coefficients.

step 1.1
3.1

On the other hand, by [L1] the finite sums of matrix coefficients are uniformly dense, so f is a uniform limit of such sums; Peter–Weyl therefore gives density, not finite equality, and the statement of this item is false.

L1step 2.1

Depends on

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