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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Finite-dimensional compact-group representations are unitarizable

Statement

Assume the Axiom of Choice. Every finite-dimensional continuous complex representation of a compact Lie group preserves some positive-definite Hermitian inner product.

Facts & Assumptions

Given: Assume the Axiom of Choice, a compact Lie group G with normalized Haar measure μ, a finite-dimensional complex representation π:GGL(V) as in Continuous and unitary representations, and a positive-definite Hermitian inner product (,)0 on V.

[A1]

The Axiom of Choice is The Axiom of Choice; it enters here through the existence of μ and its invariance [L2].

[L1]

A representation is a continuous homomorphism π:GGL(V) with π(gh)=π(g)π(h) and π(e)=idV; its matrix entries in any basis are continuous functions on G; an inner product is linear in the first argument, conjugate-symmetric and positive definite (Continuous and unitary representations, Real and complex inner-product spaces and their induced length).

[L2]

For the normalized Haar measure μ and every integrable f, Gf(gh)dμ(g)=Gf(g)dμ(g) for every hG (Haar integration is translation and conjugation invariant).

[L3]

Every left Haar integral is strictly positive on every nonzero nonnegative continuous compactly supported function; in particular, if a continuous f0 on G satisfies f(g0)>0 for some g0, then Gfdμ>0 (Haar measure is positive on nonempty open sets and finite on compact sets).

[L4]

A finite-dimensional complex vector space admits a positive-definite Hermitian inner product: choose a basis (Every vector space has a basis) and transport the standard inner product of Cn (The standard formulas x,y=k<nxkyk on Rn and k<nxkyk on Cn are inner products).

[L5]

The Lebesgue integral is complex-linear on integrable functions, and for nonnegative Borel functions it is monotone and scalar-homogeneous; consequently, if a measurable h satisfies hc everywhere with c0 and μ is a finite measure, then hdμcμ(G)<+, so h is integrable with hdμhdμ (The Lebesgue integral is linear on L1(μ), Monotonicity and nonnegative homogeneity of the nonnegative integral, Integrable real and complex functions, and their integrals).

Proof

technique · direct
1.1

Fix a positive-definite Hermitian inner product (,)0 on V and a basis of V, and for v,wV define v,w:=G(π(g)v,π(g)w)0dμ(g). The integrand is a finite sum of products of the continuous matrix entries of π with the coordinates of w, hence continuous on G, and it is bounded because G is compact; so by [L5] the integral exists in C and the definition is unambiguous.

L1L4L5
2.1

The form , is sesquilinear: for a,bC the identity (π(g)(av+bv),π(g)w)0=a(π(g)v,π(g)w)0+b(π(g)v,π(g)w)0 holds pointwise, and complex linearity of the integral [L5] turns it into av+bv,w=av,w+bv,w; conjugate symmetry follows pointwise from conjugate symmetry of (,)0 together with reality of the integral of a real-valued function, and positive semidefiniteness follows because each integrand (π(g)v,π(g)v)00 and the integral of a nonnegative function is nonnegative.

L5step 1.1
2.2

If v0, the continuous function ϕ(g):=(π(g)v,π(g)v)0 is nonnegative and satisfies ϕ(e)=(v,v)0>0, so [L3] gives v,v=Gϕdμ>0; the form is therefore positive definite.

L1L3step 1.1
3.1

For every hG and all v,wV one has π(h)v,π(h)w=G(π(g)π(h)v,π(g)π(h)w)0dμ(g)=G(π(gh)v,π(gh)w)0dμ(g)=v,w, where the middle equality is the homomorphism property π(g)π(h)=π(gh) of [L1] and the last equality is the right-translation invariance [L2] applied to f(g)=(π(g)v,π(g)w)0.

L1L2step 2.2
4.1

By steps 2.1, 2.2 and 3.1 the form , is a positive-definite Hermitian inner product preserved by every π(h), so π is unitary for it; the Axiom of Choice was used only through the existence and translation invariance of μ in [L2].

A1step 2.1step 2.2step 3.1

Depends on

Used by

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