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The boundary kernel of a compact oriented 3-manifold is Lagrangian

Statement

Assume AC. Let M be a compact oriented smooth 3-manifold as in Oriented smooth cobordism, with closed, possibly disconnected boundary Σ, and let i:Σ↪M be inclusion. Extend the direct-sum intersection form of The intersection form on the homology of a closed oriented surface to H1(Σ;R). The boundary kernel

λM=ker⁡(i∗:H1(Σ;R)→H1(M;R))

is Lagrangian. If Σ is empty, this means λM=0 in the zero symplectic space.

Facts & Assumptions

Given: AC; a compact oriented smooth 3-manifold M, its induced boundary orientation, and the inclusion i:Σ=∂M↪M.

[F1]

The homology sequence of (M,Σ) is exact at H1(Σ), so ker⁡i∗=im⁡(∂:H2(M,Σ;R)→H1(Σ;R)) (Long exact sequence of a pair).

[F2]

Under AC, cap product with [M,Σ] is the Poincaré–Lefschetz isomorphism H1(M;R)→H2(M,Σ;R); the cap boundary identity identifies the boundary of this cap with the restriction of the cohomology class capped with [Σ], up to a fixed sign (Poincaré–Lefschetz duality, Cap product boundary identity, Relative cap products with quotient domains displayed, Relative fundamental class and boundary orientation).

[F3]

Poincaré duality on each closed oriented boundary component identifies PDΣ(β)=β∩[Σ] and the intersection pairing satisfies ωΣ(PDΣα,PDΣβ)=⟨β,PDΣα⟩ in the first-factor convention (Poincaré duality for oriented topological manifolds, The intersection form on the homology of a closed oriented surface, Kronecker evaluation pairing).

[F4]

The cohomology map i∗:H1(M;R)→H1(Σ;R) is the transpose of i∗ under the perfect field-valued Kronecker pairings; finite-dimensional annihilator identities apply (Cohomology over a field is dual to homology over that field, Compact oriented manifolds with boundary have finite-dimensional field cohomology, The kronecker pairing is independent of cocycle and cycle representatives).

[A1]

Full AC is used only through the Poincaré–Lefschetz and Poincaré duality suppliers in [F2]–[F4] (The Axiom of Choice).

Proof

Given: The data in the Statement.

1.1F1F2A1given

Exactness [F1] gives λM=im⁡(∂:H2(M,Σ;R)→H1(Σ;R)). By [F2], every relative class is u∩[M,Σ] for some u∈H1(M;R). The cap boundary identity gives ∂(u∩[M,Σ])=±(i∗u)∩[Σ]. Therefore λM=PDΣ(im⁡i∗); the sign does not change this subspace.

2.1F3step 1.1algebra

Let E=im⁡i∗⊆H1(Σ;R). For x∈H1(Σ;R), [F3] gives ωΣ(x,PDΣβ)=⟨β,x⟩ for β∈E. Hence x is orthogonal to PDΣ(E)=λM exactly when every functional in E vanishes on x.

3.1F1F4step 2.1algebra∎

By [F4], E is the annihilator of ker⁡i∗ in H1(Σ;R); finite-dimensional double-annihilator duality says the vectors annihilated by every element of E are exactly ker⁡i∗=λM. Step 2.1 therefore gives λM⊥=λM. This equality implies isotropy and half-dimension, so λM is Lagrangian. If Σ is empty, both sides are zero directly.

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