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The boundary kernel of a compact oriented 3-manifold is Lagrangian
Statement
Assume AC. Let be a compact oriented smooth 3-manifold as in Oriented smooth cobordism, with closed, possibly disconnected boundary , and let be inclusion. Extend the direct-sum intersection form of The intersection form on the homology of a closed oriented surface to . The boundary kernel
is Lagrangian. If is empty, this means in the zero symplectic space.
Facts & Assumptions
Given: AC; a compact oriented smooth 3-manifold , its induced boundary orientation, and the inclusion .
The homology sequence of is exact at , so (Long exact sequence of a pair).
Under AC, cap product with is the Poincaré–Lefschetz isomorphism ; the cap boundary identity identifies the boundary of this cap with the restriction of the cohomology class capped with , up to a fixed sign (Poincaré–Lefschetz duality, Cap product boundary identity, Relative cap products with quotient domains displayed, Relative fundamental class and boundary orientation).
Poincaré duality on each closed oriented boundary component identifies and the intersection pairing satisfies in the first-factor convention (Poincaré duality for oriented topological manifolds, The intersection form on the homology of a closed oriented surface, Kronecker evaluation pairing).
The cohomology map is the transpose of under the perfect field-valued Kronecker pairings; finite-dimensional annihilator identities apply (Cohomology over a field is dual to homology over that field, Compact oriented manifolds with boundary have finite-dimensional field cohomology, The kronecker pairing is independent of cocycle and cycle representatives).
Full AC is used only through the Poincaré–Lefschetz and Poincaré duality suppliers in [F2]–[F4] (The Axiom of Choice).
Proof
Given: The data in the Statement.
Exactness [F1] gives . By [F2], every relative class is for some . The cap boundary identity gives . Therefore ; the sign does not change this subspace.
Let . For , [F3] gives for . Hence is orthogonal to exactly when every functional in vanishes on .
By [F4], is the annihilator of in ; finite-dimensional double-annihilator duality says the vectors annihilated by every element of are exactly . Step 2.1 therefore gives . This equality implies isotropy and half-dimension, so is Lagrangian. If is empty, both sides are zero directly.
Depends on
- Oriented smooth cobordism
- The intersection form on the homology of a closed oriented surface
- The Axiom of Choice
- Compact oriented manifolds with boundary have finite-dimensional field cohomology
- Poincaré–Lefschetz duality
- Poincaré duality for oriented topological manifolds
- Long exact sequence of a pair
- Cap product boundary identity
- Relative cap products with quotient domains displayed
- Relative fundamental class and boundary orientation
- Kronecker evaluation pairing
- The kronecker pairing is independent of cocycle and cycle representatives
- Cohomology over a field is dual to homology over that field
Used by
Dependency tree · two levels
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Sources
- Allen Hatcher, Algebraic Topology, Theorem 3.43 and §3.3 (standard reference, not scraped)
- J. Peter May, A Concise Course in Algebraic Topology, Chapter 21 §4 (standard reference, not scraped)