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ACL representatives recover their weak gradients by Fubini
Sources
- Juha Kinnunen, Sobolev Spaces, Chapter 2 §2.6, Theorem 2.36, converse proof, printed p. 59 (PDF pp. 60–61). On almost every coordinate line the source applies one-dimensional integration by parts and then Fubini to get the weak derivative identity. Here the argument is written on coordinate boxes, with the completion and endpoint hypotheses made explicit.
- John K. Hunter, Notes on Partial Differential Equations, Chapter 3 §3.5, Definition 3.23, printed p. 59 (PDF p. 63), for the function and weak derivative conventions used by the Sobolev interface.
Statement
Assume the Axiom of Choice. Let be open, , , and . Let have one measurable ACL representative , and suppose measurable functions , , satisfy the following: on almost every line parallel to the th coordinate axis, the one-dimensional derivative of the ACL section of exists and equals the section of almost everywhere. Then is the weak derivative for every , that is, The integrals are bilinear, without conjugation. If , the assertion is vacuous.
The Axiom of Choice is used only to invoke the cited Countable Choice and Dependent Choice interfaces for completed-product Fubini and one-dimensional absolute-continuity integration by parts; no representative is selected in the proof.
Facts & Assumptions
Given: AC, an open , , , the a.e. class , one ACL representative , and its measurable local line derivatives as in the Statement.
An ACL representative is absolutely continuous on compact subintervals of almost every coordinate line in each rational coordinate box (Absolute continuity on almost every coordinate line).
For absolutely continuous real functions on , The complex-valued version follows by applying this real identity to real and imaginary parts (Integration by parts for absolutely continuous functions).
If is integrable for the completed product of sigma-finite measures, its sections are integrable almost everywhere and the iterated integrals equal its product integral (Tonelli and Fubini for the completed product, with only almost-everywhere section measurability).
For positive integers , Euclidean Lebesgue measure on is the completion of the product of the factor Lebesgue measures (The Euclidean Lebesgue measure is the completion of the product of the factor Lebesgue measures).
Every open cover of has a locally finite smooth partition of unity with compact supports subordinate to its members (Test function cutoffs and euclidean localization).
Complex Hölder gives for conjugate exponents including and (Complex Holder, Minkowski, and the quotient norm).
Every bounded Lebesgue-measurable subset of has finite measure (Lebesgue measure is sigma-finite, and every metrically bounded subset of has finite outer measure).
AC supplies a choice function for every family of nonempty sets (The Axiom of Choice), and the cited consequence supplies Countable Choice and prescribed-start Dependent Choice (AC supplies the countable and dependent choices used in Banach integration).
The weak derivative identity is the signed test-function identity for every (Weak derivative of a locally integrable function).
Proof
If or , the identity holds with both sides zero.
Otherwise cover by its rational coordinate boxes and use [F5] to write as a locally finite sum of compactly supported smooth functions, each supported in one such box. Only finitely many summands meet the compact support of , so it is enough by linearity to prove the identity for a test function supported in a single coordinate box . [F5, given]
Fix such a and a coordinate .
When and as a.e. classes, both integrals vanish. Otherwise, the support of lies in a compact sub-box, so its restriction to every -coordinate section vanishes near the two endpoints of the side interval of . Choose a compact interval strictly inside that side interval and containing the projection of onto the th coordinate. For almost every transverse point the section of is absolutely continuous on ; by hypothesis its derivative equals the section of almost everywhere. Apply [F2] on . Since the section of vanishes at , This gives for almost every transverse . When this is directly the same one-dimensional identity, with no transverse integral. For , both products are in : the test and its derivative are bounded, has finite measure by [F7], and local with [F6] gives local . By [F4], Lebesgue measure on is the completion of the corresponding product measure, so [F3] integrates the line identity over the transverse variables. Since almost everywhere, this gives AC supplies the Countable Choice and Dependent Choice hypotheses required by [F2] and [F3], exactly as stated in [F8]. [F1, F2, F3, F4, F6, F7, F8, given]
Sum the finitely many partition identities.
Their sum is the original test function, so the same identity holds on . By [F9] this says precisely that weakly. The argument applies to every coordinate; the endpoints and are included by [F6]. [F5, F6, F9, given, step 1.1, step 1.2]
Depends on
- Absolute continuity on almost every coordinate line
- Weak derivative of a locally integrable function
- Fundamental theorem of calculus for absolutely continuous functions
- Integration by parts for absolutely continuous functions
- Tonelli and Fubini for the completed product, with only almost-everywhere section measurability
- The Euclidean Lebesgue measure is the completion of the product of the factor Lebesgue measures
- Test function cutoffs and euclidean localization
- Complex Holder, Minkowski, and the quotient norm
- Lebesgue measure is sigma-finite, and every metrically bounded subset of $\mathbb{R}^n$ has finite outer measure
- AC supplies the countable and dependent choices used in Banach integration
- The Axiom of Choice
Used by
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Sources
- Juha Kinnunen, Sobolev Spaces (2026), Chapter 2 §2.6 (standard reference, not scraped)
- John K. Hunter, Notes on Partial Differential Equations (2014), Chapter 3 §3.5 (standard reference, not scraped)