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Bimodule tensor totalization respects differentials and homotopies

Statement

Let F,F′ be bounded cochain complexes of graded (B,A)-bimodules and let G,G′ be bounded cochain complexes of graded (A,C)-bimodules, with degree-zero internal differentials as in Bounded graded bimodule complexes and signed tensor totalization. The signed tensor differential on F⊗AG descends to the balanced tensor, preserves internal degree, commutes with the outer B- and C-actions, and squares to zero. If ϕ:F→F′ and ψ:G→G′ are internal-degree zero chain maps that are bimodule-linear, then ϕ⊗Aψ is a chain map. These assignments preserve identities and composition, so tensoring is a bifunctor on the categories of bounded complexes and chain maps.

Use cochain homotopies of internal degree zero. Thus a homotopy h:G→G′ of cochain degree −1 from ψ0 to ψ1 satisfies ψ0−ψ1=dG′h+hdG, and a homotopy k:F→F′ from ϕ0 to ϕ1 satisfies ϕ0−ϕ1=dF′k+kdF. Then the induced maps are homotopic in either variable. On a summand Fp⊗AGq, the total homotopies are

H(f⊗g)=(−1)pf⊗h(g),K(f⊗g)=k(f)⊗g.

Consequently the tensor bifunctor descends to homotopy classes in both variables.

Facts & Assumptions

Given: Bounded complexes F,F′ of graded (B,A)-bimodules and G,G′ of graded (A,C)-bimodules; their differentials, maps, and homotopies preserve internal degree and are linear for the applicable bimodule actions.

[F1]

The totalization has summands Fp⊗AGq in degree p+q and differential dF⊗1+(−1)p1⊗dG (Bounded graded bimodule complexes and signed tensor totalization).

[F2]

In the ordinary right-left module case the signed tensor differential is balanced and squares to zero (The tensor-total differential is balanced, well defined, and squares to zero).

[F3]

A chain homotopy s satisfies fn−gn=dn+1Dsn+sn−1dnC (A chain homotopy). Reindexing chain degree n=−p gives the cochain formula fp−gp=dDp−1sp+sp+1dCp, with sp:Cp→Dp−1.

[F4]

The outer actions on a balanced tensor product descend by s(m⊗n)=(sm)⊗n and (m⊗n)t=m⊗(nt); when both are present they commute (A commuting outer scalar action descends to a tensor product).

Proof

Proof technique: direct sign calculation on elementary tensors, extended linearly to the bounded total modules.

1.1givenF1algebra

For a∈A, right A-linearity of dF and left A-linearity of dG give d((fa)⊗g)=dF(f)a⊗g+(−1)pfa⊗dG(g)=dF(f)⊗ag+(−1)pf⊗adG(g)=d(f⊗ag); hence the differential descends to the balanced tensor, and additivity covers zero summands.

1.2givenF1F4algebra

For b∈B and c∈C, bimodule-linearity gives d((bf)⊗g)=b d(f⊗g) and d(f⊗(gc))=d(f⊗g)c, so the outer actions commute with d; each differential preserves internal degree and the sign (−1)p depends only on cochain degree, while [F4] supplies the descended commuting outer actions.

1.3givenF1F2algebra

Applying d twice gives d2(f⊗g)=dF2(f)⊗g+((−1)p+1+(−1)p)dF(f)⊗dG(g)+f⊗dG2(g)=0: the pure terms vanish by the complex identities and the mixed terms cancel, as in the ordinary calculation [F2]; the same formula covers zero differentials and zero summands.

1.4F1algebra

If F is supported in [a,b] and G in [c,d], the total complex is supported in [a+c,b+d] with finite diagonals; at the upper endpoint the differential has zero target and below the lower endpoint there is no preceding nonzero degree, so the totalization is bounded at both ends.

1.5givenF1algebra

For internal-degree-zero bimodule chain maps ϕ:F→F′ and ψ:G→G′, their tensor is balanced and outer-linear, and d(ϕ(f)⊗ψ(g))=ϕ(dFf)⊗ψ(g)+(−1)pϕ(f)⊗ψ(dGg)=(ϕ⊗ψ)d(f⊗g) by the chain-map identities; identities and composition agree on elementary tensors and hence on the totalization.

1.6givenF1F3algebra

Let h:G→G′ be an internal-degree-zero bimodule homotopy of cochain degree −1 with ψ0−ψ1=dG′h+hdG; for H(f⊗g)=(−1)pf⊗h(g), the mixed terms in dH+Hd have coefficients (−1)p and (−1)p+1 and cancel, leaving dH(f⊗g)+Hd(f⊗g)=f⊗(dG′h+hdG)(g)=f⊗(ψ0−ψ1)(g), so H is a homotopy from 1F⊗ψ0 to 1F⊗ψ1 with the sign forced by [F1].

1.7F1F3algebra

Let k:F→F′ be an internal-degree-zero bimodule homotopy of cochain degree −1 with ϕ0−ϕ1=dF′k+kdF; for K(f⊗g)=k(f)⊗g, the mixed terms in dK+Kd have coefficients (−1)p−1 and (−1)p and cancel, leaving dK(f⊗g)+Kd(f⊗g)=(dF′k+kdF)(f)⊗g=(ϕ0−ϕ1)(f)⊗g, so K is a homotopy from ϕ0⊗1G to ϕ1⊗1G.

2.1step 1.6step 1.7algebra∎

Decompose ϕ0⊗ψ0−ϕ1⊗ψ1=(ϕ0−ϕ1)⊗ψ0+ϕ1⊗(ψ0−ψ1); postcomposing the homotopy in step 1.7 by 1F′⊗ψ0 handles the first summand and precomposing the homotopy in step 1.6 by ϕ1⊗1G handles the second, so their sum proves well-definedness on homotopy classes in both variables. If an input is concentrated in one cochain degree the formulas reduce to one summand with no sign from its internal degree.

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