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One-sided semiconvex characteristics give W2 uniqueness and stability

Statement

Assume AC and the feature-measure energy hypotheses. Fix r>0 and a nonempty closed convex constraint D⊆Ω. For every continuous moment path m:[0,T]→H, the nonautonomous inclusion X˙(t)∈−∂λV(V+ιD)(X(t))−dΦX(t)∗∇R(m(t)) has a unique forward solution from each X(0)∈D∩Qr; its characteristic map is jointly continuous in (t,X(0)) and locally Lipschitz in the initial point on each Qr. Let μt and νt be two finite-action solutions on [0,T] of the continuity equation with laws concentrated on D∩Qr and velocities vtα(x)=−argmin⁡{∣q∣:q∈dΦx∗∇R(mαt)+∂λV(V+ιD)(x)},α∈{μ,ν}, where mα=∫Φ dα. The full shifted minimum selection is Borel; it need not be continuous in position. Each finite-action PDE solution with a continuous prescribed feature moment is the pushforward by its unique characteristic map. For starts in D∩Qr, these characteristics remain in a larger QR uniformly on compact time intervals, and their velocity is the negative full shifted minimum almost everywhere. The same construction applies directly to any continuous forcing a(t)∈H in place of ∇R(m(t)). Then for all t∈[0,T], W2(μt,νt)≤e(Cr−λV)tW2(μ0,ν0),Cr=LrAr2+NrBr. Here Ar=sup⁡Qr∥dΦ∥, Br=Lip⁡Qr(dΦ), Mr=sup⁡Qr∥∂V∥ in the bounded-selection convention, and Lr,Nr are respectively a Lipschitz constant and a norm bound for dR on the closed convex hull of Φ(Qr). In particular, the localized measure-valued flow is unique for each initial law. The estimate does not assume that vt is continuous in position.

Facts & Assumptions

Given: AC, the regularity data, and two localized continuity-equation solutions.

[F1]

Each finite-action solution has a path law concentrated on absolutely continuous trajectories satisfying its velocity equation almost everywhere. Superposition for finite-action Euclidean continuity equations

[F3]

The map Φ is Ar-Lipschitz on Qr; the pointwise constrained subdifferential of V+ιD is λV-monotone, and the smooth feature-gradient difference has bounds NrBr in position and ArLr in feature moment. Feature-measure energy and its regularity assumptions

[F4]

AC supplies the superposition and disintegration constructions. The Axiom of Choice

[F6]

A uniformly equicontinuous family of maps from a compact metric space into a proper metric space with pointwise bounded images has a uniformly converging subsequence under AC. Under the Axiom of Choice, a pointwise bounded equicontinuous sequence on a nonempty compact metric domain into a proper metric target has a uniformly convergent subsequence

[F7]

Lipschitz paths are absolutely continuous, have derivatives almost everywhere, and obey the scalar absolutely continuous fundamental theorem of calculus. Apply this coordinatewise for Euclidean paths. Lipschitz characterisation within absolutely continuous functions Fundamental theorem of calculus for absolutely continuous functions

Given: AC, the data, and two solutions as in the Statement.

Proof

1.1F1F2F3F4construct

For ε>0, choose a coupling γ0 of μ0,ν0 with ∫∣x−y∣2dγ0≤W22(μ0,ν0)+ε, using the defining infimum of W2. By [F1], take path laws Πμ,Πν for the two solutions. For either path law Πα, every rational-time marginal is concentrated on Qr; closedness of Qr, continuity of paths, and countability of the rational times imply almost every path stays in Qr throughout [0,T]. Since Qr is convex and sup⁡Qr∥dΦ∥=Ar, Φ is Ar-Lipschitz there, and ∥mαt−mαs∥H≤Ar EΠα∣γ(t)−γ(s)∣≤Ar∣t−s∣1/2(EΠα∫st∣γ˙(q)∣2dq)1/2. Thus mαt and aα(t)=∇R(mαt) are continuous. Disintegrate each law conditional on its time-zero position, then combine the two kernels with γ0 using [F2]. This gives a joint law of paths (X,Y) with marginals Πμ,Πν and initial pair law γ0. Set D(t)=E∣Xt−Yt∣2. The path equations and the scalar chain rule show D is absolutely continuous and 12D′(t)=E⟨Xt−Yt,vtμ(Xt)−vtν(Yt)⟩ for almost every t. The product is integrable by Cauchy–Schwarz because both path actions and second moments are finite.

1.2F3F4F5construct

We construct characteristics for any continuous a:[0,T]→H, with M=max⁡t∥a(t)∥, g(t,x)=dΦx∗a(t), f=V+ιD and λ=λV. The sets Qs cover Ω: for q∈Q1 the neighborhood condition puts x∈Ω in Q1+∣x−q∣, increasing the radius slightly when necessary. Thus every bounded subset of Ω lies in a Qs. Bounded supporting potential subgradients at x,y∈Qs give ∣V(y)−V(x)∣≤(C1+C2s)∣y−x∣+∣λ∣∣y−x∣2/2. Subdivide the segment into n equal pieces and let n→∞ to see that V is (C1+C2s)-Lipschitz on Qs. Therefore f is proper, lower semicontinuous and λ-semiconvex, and its subdifferential is nonempty everywhere on D. Its supporting inequalities give ⟨ξ−η,x−y⟩≥λ∣x−y∣2. For 1+hλ>0, the function f(y)+∣y−z∣2/(2h) is coercive and strongly convex: use a supporting inequality at a fixed point of D for the quadratic lower bound. Finite-dimensional compactness gives its unique minimizer Jhz, and testing minimality along segments gives (z−Jhz)/h∈∂λf(Jhz). Adding two such inequalities gives ∣Jhz−Jhw∣≤∣z−w∣/(1+hλ).

2.1F1F3step 1.1

Write each full shifted selection as dΦx∗∇R(mμt)+ξμ(x) and dΦy∗∇R(mνt)+ξν(y), with the two potential sections in ∂λV(V+ιD); they need not coincide as functions of position. Adding their supporting inequalities gives ⟨ξμ(x)−ξν(y),x−y⟩≥λV∣x−y∣2. For the smooth terms, add and subtract dΦy∗∇R(mμt): their difference has norm at most NrBr∣x−y∣+ArLr∣mμt−mνt∣. Along the joint law, ∣mμt−mνt∣≤ArE∣Xt−Yt∣≤ArD(t)1/2. Hence [F3] gives 12D′(t)≤(Cr−λV)D(t). Multiplying by e−2(Cr−λV)t and differentiating proves D(t)≤e2(Cr−λV)tD(0). The time-t path pair couples μt,νt, so W22(μt,νt)≤D(t); using D(0)≤W22(μ0,ν0)+ε, letting ε↓0, and taking square roots proves the stated estimate. If the initial laws agree, its right side is zero, proving uniqueness.

2.2F3F4F5F6step 1.2construct

For h=T/n, h∣λ∣≤1/2, define x0=u∈D∩Qr, xk=Jh(xk−1−hg(tk,xk−1)), vk=(xk−xk−1)/h, and ξk=−vk−g(tk,xk−1)∈∂λf(xk). Put Sk=∑j≤kh∣vj∣. The neighborhood condition gives xk∈Qr+Sk. Compare ξk with a supporting potential vector ηk−1 at xk−1 of norm at most C1+C2(r+Sk−1). Monotonicity yields (1+hλ)∣vk∣2≤−⟨g(tk,xk−1)+ηk−1,vk⟩, so ∣vk∣≤A+BSk−1, where A=2(M+1)(C1+C2r) and B=2(M+1)C2. Hence Sk≤(1+hB)Sk−1+hA and Sk≤S∗=(A/B)(eBT−1), with S∗=AT when B=0. All iterates and affine interpolants Xh lie in D∩QR, where R=r+S∗+1, and have speed at most K=A+BS∗. For each fixed u, their images lie in the compact ball B‾(u,KT) and they are uniformly Lipschitz. Arzelà–Ascoli gives a subsequence converging uniformly to a K-Lipschitz D∩QR-valued path X. Both constant interpolants converge uniformly to X, V(xk) converges uniformly to V(X) by step 1.2, and gh(t)=g(tk,xk−1) converges uniformly to g(t,X(t)) by continuity of a and the Lipschitz bound on dΦ on QR.

3.1F5F7step 1.2step 2.2

Write xh+(t)=xk on (tk−1,tk]. The discrete supporting inequality is ⟨Xh′,xh+−z⟩+V(xh+)+⟨gh,xh+−z⟩+(λ/2)∣xh+−z∣2≤V(z) for every z∈D. Replace xh+ by Xh only in the derivative pairing; its error is at most K2h. Integrating over any [b,c]⊂[0,T] makes that pairing the exact endpoint difference (∣Xh(c)−z∣2−∣Xh(b)−z∣2)/2. All other terms converge uniformly by step 2.2, yielding (∣X(c)−z∣2−∣X(b)−z∣2)/2+∫bc[V(X)+⟨g(t,X),X−z⟩+(λ/2)∣X−z∣2]dt≤(c−b)V(z). Choose countably many dense z∈D and differentiate this interval inequality where the scalar absolutely continuous functions and coordinates of X are differentiable. Outside their common null set the inequality says −X′−g(t,X)∈∂λf(X), first for these tests and then for every z∈D by continuity of V on bounded sets. This proves the inclusion without any continuity or convergence assertion for the nonsmooth minimum field.

4.1F3F7step 2.2step 3.1

Two solutions X,Y to the same forcing have bounded images in a common Qs. Monotonicity gives (∣X−Y∣2/2)′≤(MBs−λ)∣X−Y∣2, so multiplication by the scalar integrating factor proves uniqueness. Therefore all converging Euler subsequences have the same limit and compactness gives uniform convergence of the entire family. For all starts in D∩Qr, step 2.2 gives the same radius R and time-Lipschitz constant K; the same distance estimate gives ∣X(t,u)−X(t,w)∣≤e(MBR−λ)t∣u−w∣. Together these prove joint continuity in (t,u) and uniform Lipschitz dependence on the initial point. Nearby starts lie in a common Qs by the neighborhood property. For different forcings a,b and paths in Qs, monotonicity gives (∣X−Y∣2/2)′≤c∣X−Y∣2+As∥a−b∥∣X−Y∣, c=(max⁡∥a∥)Bs−λ. Apply this to ∣X−Y∣2+ε2 and let ε↓0 to obtain ∣X(t)−Y(t)∣≤ect∣X(0)−Y(0)∣+As∫0tec(t−q)∥a(q)−b(q)∥dq. This is forcing stability. All finite horizons patch uniquely.

4.2F3F7step 1.2step 3.1

Since V∘X is Lipschitz, at a time where it and X are differentiable and the inclusion holds, test any η∈∂λf(X(t)) against X(t+h) for both signs of h. Division by h and passage to zero give (V∘X)′=⟨η,X′⟩ for every such η simultaneously. For ξ=−X′−g(t,X) this gives ⟨η−ξ,X′⟩=0, so ∣g+η∣2=∣−X′∣2+∣η−ξ∣2. Thus −X′ is the full shifted minimum. Its Borel measurability for fixed forcing follows directly from qε(t,x)=(x−Jε(x−εg(t,x)))/ε: these are continuous, and monotonicity gives (1+ελ)∣qε∣2≤⟨g(t,x)+η,qε⟩ for every η∈∂λf(x). Therefore qε is bounded and its prox point tends to x. Continuity of V passes the supporting inequalities to every cluster point q, placing it in the shifted subdifferential; the displayed inequality becomes its minimum-norm projection inequality. All cluster points equal the unique minimum, so the entire sequence converges. The pointwise limit of the continuous qε is Borel.

5.1F1step 2.1step 2.2step 4.1step 4.2∎

For any finite-action PDE solution with this velocity and fixed continuous forcing, [F1] represents it by absolutely continuous paths. Their positions lie in closed D at every rational time and hence every time. Each path solves the inclusion, so uniqueness from step 4.1 identifies it with X(⋅,u), where u is its initial point. Thus μt=X(t,⋅)#μ0, with the same radius bound from step 2.2 whenever μ0 is concentrated on Qr. This argument uses neither a backward inverse nor continuity of the minimum field. With a(t)=∇R(m(t)) it proves the characteristic assertion in the Statement; steps 1.1–2.1 prove the self-consistent law stability assertion.

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