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LemmaStatement: AI-adaptedProof: AI-adaptedprecheck passverified 2026-08-09 (gpt-5.6-terra-codex-subscription)
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The topology of a nonempty completely regular space is induced by the gauge of its continuous [0,1]-valued pseudometrics

Statement

The topology of a nonempty completely regular space is induced by the gauge of pseudometrics pf(x,y)=∣f(x)−f(y)∣, where f:X→[0,1] ranges over continuous maps.

Facts & Assumptions

Given: A nonempty completely regular space X.

[L1]

Complete regularity separates a point from a closed set by a continuous [0,1]-valued function (Completely regular spaces and Tychonoff (T312) spaces, Intervals of R: the nine order-convex forms, nondegeneracy, and length).

[L2]

Such functions are continuous in the neighbourhood sense (Continuity of a map of topological spaces at a point and globally).

[L3]

A gauge generates a uniformity from finite simultaneous pseudometric balls (A gauge of pseudometrics and, on a nonempty set, the uniformity it generates).

[L4]

Absolute value is nonnegative, vanishes only at zero and is even (Basic properties of the absolute value), and it satisfies ∣u+v∣≤∣u∣+∣v∣ (The triangle inequality).

Proof

technique · constructive
1.1

For each continuous f:X→[0,1], direct substitution in [L4] shows that pf(x,y)=∣f(x)−f(y)∣ is nonnegative, symmetric, zero on the diagonal and satisfies the triangle inequality, so it is a pseudometric; its balls about x are original-open by [L2].

L2L4construct
1.2

Conversely, if x∈U is original-open, apply [L1] to the closed set X∖U to obtain f with f(x)=1 and f[X∖U]={0}; then the pf-ball of radius 1/2 about x lies in U.

L1L3choose
2.1

Hence every gauge-open set is original-open.

step 1.1L3
3.1

Thus original-open and gauge-open sets contain one another, so the two topologies agree.

step 2.1step 1.2discharge-construct∎

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