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The discriminant is a nonvanishing cusp form of weight 12

Statement

Define Δ:=(E43−E62)/1728. Then Δ is a cusp form of weight 12 whose q-expansion is Δ(τ)=q−24q2+O(q3),q=e2πiτ; in particular Δ≠0 and ord⁡∞(Δ)=1, and the valence formula gives Δ(τ)≠0 for every τ∈H. Moreover E43 and E62 are linearly independent in M12, this space being two-dimensional with basis {E43,E62}.

Facts & Assumptions

Given: E4∈M4 and E6∈M6 with E4=1+240q+2160q2+O(q3) and E6=1−504q−16632q2+O(q3) (Eisenstein series are modular forms; their Fourier coefficients, The level-one Eisenstein series E_k and the weight-two series E_2, The divisor power sums σk).

[F1]

M12 is a two-dimensional complex vector space. Multiplication adds weights, with M4M4⊆M8, M8M4⊆M12 and M6M6⊆M12; the cusp forms are the kernel of the constant-term functional f↦f(∞) (The dimension of the space of level-one modular forms, Level-one modular forms and cusp forms).

[F2]

Valence formula: for even k and 0≠f∈Mk, ∑P≠∞ord⁡P(f)/νP=k/12−ord⁡∞(f) (The level-one valence formula).

Proof

1.1F1givenalgebra

E43∈M12 and E62∈M12 by [F1], hence Δ=(E43−E62)/1728∈M12. From the displayed expansions, E43=1+720q+(3⋅2160+3⋅2402)q2+O(q3)=1+720q+179280q2+O(q3) and E62=1−1008q+(5042−2⋅16632)q2+O(q3)=1−1008q+220752q2+O(q3). Therefore Δ=11728(1728q−41472q2+O(q3))=q−24q2+O(q3). In particular Δ≠0, Δ(∞)=0, so Δ is a cusp form, and ord⁡∞(Δ)=1.

2.1F1F2step 1.1givenalgebra∎

Applying the valence formula [F2] to Δ of weight 12 gives ∑P≠∞ord⁡P(Δ)/νP=12/12−1=0; every summand is a nonnegative multiple of 1/νP, so all vanish and Δ has no zeros on H. Finally, if aE43+bE62=0 then comparing constant terms gives a+b=0 and comparing q-coefficients gives 720a−1008b=0, whence (720+1008)a=0 and a=b=0; so E43,E62 are linearly independent in the two-dimensional space M12 and therefore form a basis.

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