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Eisenstein series are modular forms; their Fourier coefficients

Statement

For every even k≥4: (a) Ek is a modular form of weight k for PSL2(Z); (b) writing Bk for the k-th Bernoulli number, Ek(τ)=1−2kBk∑n≥1σk−1(n)qn, q=e2πiτ, with σk−1(n)=∑d∣ndk−1; (c) Ek(∞)=1, and Gk=2ζ(k)Ek; (d) in particular E4=1+240q+2160q2+O(q3) and E6=1−504q−16632q2+O(q3).

Facts & Assumptions

Given: Even k≥4, Gk(τ)=∑(m,n)′(mτ+n)−k and Ek=Gk/(2ζ(k)) (The level-one Eisenstein series E_k and the weight-two series E_2, The Riemann zeta function on the half-plane Re⁡s>1, The divisor power sums σk).

[F1]

The family ((mτ+n)−k) is absolutely summable with locally uniform convergence on H, and the action is by ℑ(γτ)=ℑτ/∣cτ+d∣2 with γ=(abcd) (Absolute convergence and holomorphy of the lattice Eisenstein sums, The modular group and its action on the upper half-plane).

[F2]

Lipschitz: ∑n∈Z(z+n)−k=(−2πi)k(k−1)!∑r≥1rk−1e2πirz for Im⁡z>0, absolutely convergent (The Lipschitz formula for the reciprocal-power sums).

[F3]

Mk is defined by the weight-k transformation law and holomorphy at the cusp, with Ek=1+O(q) (Level-one modular forms and cusp forms, The level-one Eisenstein series E_k and the weight-two series E_2); 2ζ(k)>0 and (m,n)↦(ma+nc,mb+nd) is a bijection of Z2 for γ∈SL2(Z) (The Riemann zeta function on the half-plane Re⁡s>1, Fubini for double series: if ∑i∑j∣aij∣ converges then both iterated sums and the sum along every bijection N→N×N converge to one and the same value).

[F4]

The even zeta values follow locally without a choice assumption. For ∣z∣<1, the cotangent expansion (The Mittag-Leffler expansion of pi cotangent) gives πzcot⁡(πz)=1−2∑m≥1ζ(2m)z2m: expand 2z2/(z2−n2) geometrically and interchange the sums, whose absolute total on ∣z∣≤r<1 is bounded by 2r2(1−r2)−1∑n≥1n−2. Put t=2πiz. The exponential definitions of sine and cosine give πzcot⁡(πz)=t/(et−1)+t/2. Comparing the coefficient of z2m in the Bernoulli generating series yields ζ(2m)=(−1)m+1B2m(2π)2m/(2(2m)!) (The Bernoulli numbers are defined by the generating series t/(et−1), Complex sine, cosine, hyperbolic sine, and hyperbolic cosine from the complex exponential, exp⁡(z+w)=exp⁡z exp⁡w, and the complex exponential extends the real exponential, Fubini for double series: if ∑i∑j∣aij∣ converges then both iterated sums and the sum along every bijection N→N×N converge to one and the same value, Ratio test: lim sup⁡∣ak+1/ak∣<1 gives absolute convergence and hence convergence, and lim inf⁡∣ak+1/ak∣>1 gives divergence).

Proof

1.1F1F3givenalgebra

Let γ=(abcd)∈SL2(Z). Writing mγτ+n=(ma+nc)τ+(mb+nd)cτ+d and using that (m,n)↦(ma+nc,mb+nd) is a bijection [F3], the absolute summability [F1] permits reindexing, so Gk(γτ)=(cτ+d)kGk(τ). Hence Ek(γτ)=(cτ+d)kEk(τ). By [F3], Ek=1+O(q) as Im⁡τ→∞, so in particular Ek is bounded near the cusp, and its periodic function F extends holomorphically to q=0 by the q-expansion principle; therefore Ek∈Mk and (a) holds.

1.2F2F3givenalgebra

Split the absolutely summable sum defining Gk into m=0 and m≠0. The m=0 part is ∑n≠0n−k=2ζ(k) because k is even. For m≠0 pair m with −m and n with −n; by [F3] this reindexing preserves the sum, and each remaining term with m≥1 is handled by [F2] applied to z=mτ (whose imaginary part is positive): ∑n∈Z(mτ+n)−k=(−2πi)k(k−1)!∑r≥1rk−1qmr. Therefore Gk=2ζ(k)+2(−2πi)k(k−1)!∑m≥1∑r≥1rk−1qmr=2ζ(k)+2(−2πi)k(k−1)!∑n≥1σk−1(n)qn, the last regrouping being the absolutely summable family (rk−1qmr)m,r≥1 grouped by n=mr [F3]: for ∣q∣≤ρ<1, its absolute sum is at most (1−ρ)−1∑r≥1rk−1ρr<∞ by the ratio test (Ratio test: lim sup⁡∣ak+1/ak∣<1 gives absolute convergence and hence convergence, and lim inf⁡∣ak+1/ak∣>1 gives divergence). Dividing by 2ζ(k) gives Ek=1+(−2πi)k(k−1)!ζ(k)∑n≥1σk−1(n)qn.

2.1F4step 1.2givenalgebra∎

For even k write k=2m. Then (−2πi)k=2kπk(−i)2m=(−1)m2kπk, and by [F4] ζ(2m)=(−1)m+1Bk(2π)k2k!, so (k−1)!ζ(k)=(−1)m+1Bk(2π)k2k and the coefficient of ∑σk−1(n)qn in 1.2 is (−1)m2kπk⋅2k(−1)m+1Bk(2π)k=−2kBk, proving (b). The constant term gives Ek(∞)=1 and Gk=2ζ(k)Ek, which is (c) (see [F3]). For (d): B4=−1/30 and B6=1/42, so −2⋅4B4=240 and −2⋅6B6=−504; with σ3(1)=1, σ3(2)=1+8=9 and σ5(1)=1, σ5(2)=1+32=33 this gives E4=1+240q+2160q2+O(q3) and E6=1−504q−16632q2+O(q3), as claimed. The special values used here are the local coefficient computation in [F4].

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