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The Lipschitz formula for the reciprocal-power sums

Statement

For every integer k≥2 and every τ∈H, with q=e2πiτ, ∑n∈Z1(τ+n)k=(−2πi)k(k−1)!∑r=1∞rk−1qr, where the series on the left converges absolutely and the identity is independent of the order of summation.

Facts & Assumptions

Given: An integer k≥2, a point τ∈H, and q=e2πiτ.

[F1]

πcot⁡(πz)=1z+∑n≥1(1z−n+1z+n), and the series converges locally uniformly on C∖Z (The Mittag-Leffler expansion of pi cotangent).

[F2]

If the partial sums of ∑jgj of holomorphic functions converge locally uniformly to g, then g is holomorphic and g(m)=∑jgj(m) for every m, the derivative series again converging locally uniformly (A locally uniformly convergent series of holomorphic functions may be differentiated term by term, Complex analytic functions as locally representable by convergent power series).

[F3]

sin⁡z=eiz−e−iz2i, cos⁡z=eiz+e−iz2, and cot⁡z=cos⁡z/sin⁡z wherever sin⁡z≠0 (Complex sine, cosine, hyperbolic sine, and hyperbolic cosine from the complex exponential, Tangent, cotangent, secant, and cosecant on their exact natural domains).

[F4]

exp⁡(w+w′)=exp⁡(w)exp⁡(w′), exp⁡(2w)=exp⁡(w)2, exp⁡(−w)=1/exp⁡(w), and ∣exp⁡(x+iy)∣=ex for real x,y (exp⁡(z+w)=exp⁡z exp⁡w, and the complex exponential extends the real exponential, exp⁡(x+iy)=ex(cos⁡y+isin⁡y), ∣exp⁡(x+iy)∣=ex, and eiπ+1=0).

[F5]

exp⁡′=exp⁡; the chain rule and the algebra of derivatives give dmdwmeaw=ameaw and dmdwm1w+n=(−1)mm!(w+n)m+1 on their domains (The complex exponential is entire and its complex derivative is itself, The chain rule for complex derivatives, Linearity, product, reciprocal, and quotient rules for complex derivatives).

[F6]

Convergence in C is convergence in the metric d(z,w)=∣z−w∣ (The Euclidean metric, convergence, Cauchy sequences, and continuity on the complex plane); an absolutely convergent complex series converges, and every rearrangement of it has the same sum (Every absolutely convergent complex series converges, and rearrangements preserve its sum, Complex series, absolute convergence, complex power series, and radius of convergence).

Proof

1.1F1F3F4F6F7givenalgebra

The function z↦πcot⁡(πz) is holomorphic on the open set H⊆C∖Z, and by [F1] the partial sums of z−1+∑n≥1((z−n)−1+(z+n)−1) converge locally uniformly on H to it. Fix w with ∣w∣<1: the telescoping identity (1−w)∑m=0Nwm=1−wN+1, the convergence ∣w∣N+1→0 of [F7] and the metric description [F6] give ∣(1−w)∑m≤Nwm−1∣→0; dividing by the nonzero ∣1−w∣ proves ∑m≥0wm=1/(1−w). Now put u=eiπz and Q=u2=e2πiz by [F4]; then [F3] and [F4] give sin⁡(πz)=(u−u−1)/(2i)=(Q−1)/(2iu) and cos⁡(πz)=(u+u−1)/2=(Q+1)/(2u), so πcot⁡(πz)=πiQ+1Q−1=−πi(1+2∑r≥1Qr), because ∣Q∣=e−2πIm⁡z<1 for z∈H by [F4] and 1+Q1−Q=1+2∑r≥1Qr.

2.1F2F5step 1.1algebra

The series in 1.1 has holomorphic terms and locally uniformly convergent partial sums on H, so [F2] applies and, for m=k−1, differentiating termwise gives dk−1dzk−1πcot⁡(πz)=(−1)k−1(k−1)!∑n∈Z(z+n)−k on H, the displayed sum being understood through the absolutely convergent paired series of [F1] together with the term z−k differentiated from z−1; here dmdzm(z+n)−1=(−1)mm!(z+n)−m−1 by [F5]. On the other side the Q-series of 1.1 consists of entire terms with locally uniformly convergent partial sums, so differentiating it k−1 times termwise by [F2] and [F5] gives −2πi(2πi)k−1∑r≥1rk−1Qr as functions of z.

3.1F6F7step 2.1givenalgebra∎

Evaluating the two expressions of 2.1 at z=τ, where Q=e2πiτ=q, gives (−1)k−1(k−1)!∑n∈Z(τ+n)−k=−2πi(2πi)k−1∑r≥1rk−1qr. Dividing by the nonzero real number (−1)k−1(k−1)! yields the stated identity, since −2πi(2πi)k−1/(−1)k−1=(−2πi)k. Finally, for n≥2∣τ∣ one has ∣τ±n∣≥n−∣τ∣≥n/2, so ∑n≥1∣τ±n∣−k≤Cτ+2k+1∑n≥1n−k<∞ by [F7]; hence the family ((τ+n)−k)n∈Z is absolutely summable and, by [F6], every enumeration of it converges to the same sum, which is the order-independence asserted in the Statement.

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