Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The chain rule for complex derivatives

Statement

Let f:U→V and g:V→C, where U,V⊆C are open. If f is complex differentiable at a∈U and g is complex differentiable at f(a), then g∘f is complex differentiable at a and

(g∘f)′(a)=g′(f(a))f′(a).

Facts & Assumptions

Given: The maps, domains, point, and differentiability hypotheses in the Statement.

[L1]

Complex differentiability at a point is equivalent to real total differentiability with total derivative given by multiplication by the complex derivative (Complex differentiability is equivalent to real total differentiability together with a complex-linear derivative, with ∂zˉf=0, or with the Cauchy–Riemann equations).

[L2]

If f is totally differentiable at a and g is totally differentiable at f(a), then D(g∘f)(a)=Dg(f(a))∘Df(a) (The chain rule for total derivatives: D(g∘f)(a)=Dg(f(a))∘Df(a)).

Proof

technique · direct
1.1

By [L1], Df(a) is multiplication by f′(a) and Dg(f(a)) is multiplication by g′(f(a)).

givenL1
2.1

By [L2], g∘f is real totally differentiable and its derivative is the composite of the maps in step 1.1, namely multiplication by g′(f(a))f′(a).

step 1.1L2algebra
3.1

Applying the reverse implication of [L1] gives complex differentiability of g∘f and the asserted derivative.

step 2.1L1∎

Depends on

Used by

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources