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Absolute convergence and holomorphy of the lattice Eisenstein sums

Statement

For every even k≥4 and every τ∈H the family ((mτ+n)−k)(m,n)∈Z2∖{(0,0)} is absolutely summable, and the convergence is uniform on compact subsets of H. Consequently Gk(τ):=∑(m,n)′(mτ+n)−k defines a holomorphic function on H, and it depends only on the lattice Λτ=Z+Zτ assigned to τ.

Facts & Assumptions

Given: An even integer k≥4, the upper half-plane H with Im⁡>0 (The modular group and its action on the upper half-plane), and a compact K⊆H with Im⁡τ≥y0>0 and ∣Re⁡τ∣≤X for all τ∈K.

[F2]

If 0≤aj≤bj eventually and ∑bj converges then ∑aj converges (If 0≤ak≤bk eventually, convergence of ∑bk gives convergence of ∑ak, and divergence of ∑ak gives divergence of ∑bk); ∑jj−p converges for rational p>1 (For rational p>0, ∑1/kp converges iff p>1).

[F3]

For a complex double family with summable absolute values, apply the real double-series theorem separately to its real and imaginary parts. The family may then be summed in any order, in particular iterated or regrouped into shells (Fubini for double series: if ∑i∑j∣aij∣ converges then both iterated sums and the sum along every bijection N→N×N converge to one and the same value, If ∑∣ak∣ converges then ∑ak converges).

[F4]

If holomorphic functions on an open set converge locally uniformly, their limit is holomorphic (Locally uniform limits of holomorphic functions are holomorphic and their derivatives converge locally uniformly).

[F5]

∣z+w∣≥∣∣z∣−∣w∣∣, ∣zw∣=∣z∣∣w∣, and ∣Re⁡z∣≤∣z∣ (Conjugation is an involutive real-field automorphism, zz‾=∣z∣2, and modulus is definite, multiplicative, and subadditive, Real and imaginary parts, complex conjugation, and modulus).

Proof

1.1F5givenalgebra

Since mτ+n=0 with (m,n)≠(0,0) would give τ=−n/m∈R when m≠0 and n=0 when m=0, no denominator vanishes. Let cK:=min⁡(1/2, y0/max⁡(1,2X))>0. For (m,n)≠(0,0) and τ∈K we claim ∣mτ+n∣≥cKmax⁡(∣m∣,∣n∣). If ∣n∣≥2X∣m∣, then ∣Re⁡(mτ+n)∣=∣mRe⁡τ+n∣≥∣n∣−X∣m∣≥∣n∣/2 by [F5]; if moreover ∣n∣≥∣m∣ then ∣mτ+n∣≥∣n∣/2≥max⁡(∣m∣,∣n∣)/2, while if ∣n∣<∣m∣ then the imaginary part gives ∣mτ+n∣≥y0∣m∣=y0max⁡(∣m∣,∣n∣). If instead ∣n∣<2X∣m∣, then max⁡(∣m∣,∣n∣)≤max⁡(1,2X)∣m∣ and the imaginary part gives ∣mτ+n∣≥y0∣m∣≥y0max⁡(1,2X)max⁡(∣m∣,∣n∣). In all cases the claim holds.

2.1F1F2F3step 1.1givenalgebra

Regroup the nonzero pairs by the shell j:=max⁡(∣m∣,∣n∣)≥1; the shell has (2j+1)2−(2j−1)2=8j elements, and by 1.1 each contributes at most (cKj)−k, so shell j contributes at most 8cK−kj1−k. Since k≥4 gives k−1>1, the bound ∑j≥18cK−kj1−k<∞ follows from [F2]. The shell partial sums of the family are therefore nonnegative and bounded uniformly in τ∈K by an absolute constant, so they converge by the bounded-partial-sums criterion of [F1]; in the terminology of [F1] the family ((mτ+n)−k)(m,n)≠(0,0) is absolutely summable for each τ∈K, the regrouping being licensed by [F3], and the tail beyond shell J is bounded uniformly on K by 8cK−k∑j>Jj1−k.

3.1F3F4step 2.1givenalgebra∎

Each term τ↦(mτ+n)−k is holomorphic on H for (m,n)≠(0,0), being a power of the nonvanishing holomorphic function τ↦mτ+n. By 2.1 the partial sums over shells converge uniformly on every compact K⊆H (compactness supplies some y0,X), so [F4] makes the shell-sum limit Gk holomorphic on H, and this limit agrees with the (absolutely summable, hence order-independent by [F3]) family sum. Finally (m,n)↦mτ+n is a bijection of Z2 onto the lattice Λτ=Z+Zτ, so the summed family is exactly the family of values λ−k over the nonzero points λ∈Λτ; hence Gk(τ) depends only on Λτ and not on the enumeration.

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