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The selected pointwise field is a strong Wasserstein subgradient

Statement

Assume AC and the feature-measure energy hypotheses. Fix r>0 and μ∈P2(Ω) concentrated on Qr. Define gμ(u)=S(∇R(∫Φ dμ),u), the minimum-norm element of dΦu∗∇R(∫Φ dμ)+∂λV(V+ιQr)(u). For every η∈P2(Ω) concentrated on Qr and every coupling γ of μ and η, F(η)≥F(μ)+∫gμ(x)⋅(y−x)dγ(x,y)+λV−Cr2∫∣y−x∣2dγ(x,y),Cr=LrAr2+NrBr. In particular, gμ is a strong Wasserstein subgradient of the localized functional Fr, defined as F on laws concentrated on Qr and +∞ otherwise, in the all-coupling sense, with zero remainder after the stated quadratic term. Here Ar=sup⁡Qr∥dΦ∥, Br=Lip⁡Qr(dΦ), and Lr,Nr are respectively a Lipschitz constant and norm bound for dR on the closed convex hull of Φ(Qr); put λr=λV−Cr. It is the unique minimum-norm vector field among all all-coupling strong subgradients in L2(μ;Rd).

Facts & Assumptions

Given: AC, r, μ,η, and a coupling γ as in the Statement.

[F1]

The localized lifted energy has semiconvexity coefficient λV−Cr. The localized lifted feature energy is semiconvex

[F2]

The localized lifted subdifferential equals the smooth feature gradient plus the pointwise constrained potential subdifferential, and its minimum section is measurable. The localized lifted subdifferential is a pointwise constrained subdifferential

[F3]

The first marginal of a coupling is μ and the second is η. The Euclidean quadratic Wasserstein space

[F4]

AC supplies Countable Choice for the inherited Bochner approximation branches. Measurability and the norm bound for the full shifted minimum section are supplied by [F2]. The Axiom of Choice AC implies DC implies countable choice The Axiom of Countable Choice (ACω) Bochner dominated convergence theorem

Proof

Given: AC and the data above.

1.1F2F3F4construct

On (Rd×Rd,γ), set X(x,y)=x and Y(x,y)=y. This is a Euclidean Borel probability label space of dimension 2d, with output dimension d; the arbitrary-label lift and subdifferential formula therefore apply. These are admissible lifts because both marginals are concentrated on Qr. Their laws are μ and η by [F3], so their lifted energies are F(μ) and F(η). The pointwise minimum section and smooth gradient in [F2] give the lifted subgradient s(x,y)=gμ(x)∈L2(γ;Rd).

2.1F1step 1.1

Apply the semiconvex subgradient inequality [F1] to the two lifts. The Hilbert inner product is ∫gμ(x)⋅(y−x)dγ and the squared displacement norm is ∫∣y−x∣2dγ. Substitution gives exactly the asserted inequality for this coupling. Since γ was arbitrary, it holds for every coupling and proves the strong-subgradient claim.

3.1F1F2step 2.1∎

Conversely let h∈L2(μ) satisfy the all-coupling strong-subgradient inequality. Lift on (Rd,μ) with X(x)=x, and take the coupling (X,(1−t)X+tY)#μ for any admissible Y. Its displacement norm is t∥Y−X∥2. Dividing the strong inequality by t gives the lower bound ⟨h,Y−X⟩ for the directional derivative of Er at X in direction Y−X. Semiconvexity of Er implies its secant slope is at least that directional derivative plus λr∥Y−X∥22/2; consequently h∈∂λrEr(X). The pointwise formula [F2] gives h(x)∈dΦx∗∇R(mμ)+∂λV(V+ιQr)(x) almost everywhere. The full shifted minimum has norm no larger pointwise, so ∥gμ∥2≤∥h∥2. Equality forces equality pointwise by strict convexity and the projection inequality. This proves the claimed minimality and uniqueness.

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