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A Hilbert polynomial bounds regularity independently of ambient dimension

Statement

Assume AC and DC. For every numerical polynomial P there is an integer b(P)≥0 such that, over every field and for every n,p≥0, the kernel and quotient of any coherent quotient OPnp↠F with Hilbert polynomial P are b(P)-regular. The bound is independent of both n and p. For realizable nonzero P it can be defined recursively by a=b(ΔP), b(P)=a+max⁡(0,P(a))+1, where ΔP(t)=P(t)−P(t−1) and b(0)=0. For unrealizable polynomials any bound suffices.

Facts & Assumptions

Given: AC and DC and the hypotheses of the statement.

[F1]

Regularity propagation and section multiplication are supplied in Regularity gives generation, multiplication, and vanishing. For fixed n,p and the polynomial of I, Uniform regularity for all quotients with a fixed Hilbert polynomial supplies some regularity bound; propagation therefore gives eventual vanishing of every positive cohomology group of I. Associated points are finite and detect zero divisors (Finite modules over Noetherian rings have finitely many associated primes, Zero divisors on a module over a Noetherian ring are the union of its associated primes).

[F2]

A nonzero coherent sheaf on projective space has Hilbert polynomial of degree equal to its support dimension and nonzero leading coefficient (Degree of the coherent Hilbert polynomial). In particular zero polynomial means the zero sheaf.

[F3]

On projective space, coherent cohomology commutes with every field extension (Flat field extension commutes with coherent cohomology). Twists commute with pullback, as is seen from their standard-chart transition functions; hence the Hilbert polynomial and regularity are preserved. Vanishing descends because a vector space whose scalar extension is zero is itself zero. Flatness also preserves the quotient sequence and its kernel.

[F4]

The Hilbert polynomial equals the Euler characteristic at every integral twist (Euler characteristic is a Hilbert polynomial), and Euler characteristic is additive in coherent exact sequences (Euler characteristic is additive in short exact sequences). The cohomology of twists gives h0(O(t))=(n+tn) for t≥0 and shows that O is 0-regular (Cohomology of O(d) on projective space).

Proof

1.1F1F2F3F4construct

Induct on the degree of a realizable nonzero P, adjoining the zero polynomial as the initial case. If P=0, [F2] gives F=0 and the kernel is Op, which is 0-regular. If n=0, all coherent sheaves are regular in every degree, so the proposed bound also works. Otherwise extend to the infinite field k(u) using [F3], and choose a hyperplane H avoiding the associated points of F and of its kernel I. Tor exactness gives 0→IH→OHp→FH→0, and the restriction sequence and [F4] give PFH=ΔP. For degree-zero P the hyperplane misses the finite support, so FH=0; in all other cases [F2] reduces the induction degree. Thus IH is a-regular with a=b(ΔP), independent of n,p.

2.1F1F3F4step 1.1algebra∎

The exact hyperplane sequence and [F1] give Hi(I(t))=0 for i≥2 and t≥a−i: compare successive twists using vanishing of the two adjacent groups of IH, then iterate to an eventual-vanishing twist supplied by [F1]. They also show that h1(I(t)) decreases strictly after twist a until it becomes zero, because equality h1(I(t))=h1(I(t+1)) for t≥a makes H0(I(t+1))→H0(IH(t+1)) onto; multiplication for IH propagates that surjectivity, so equality would persist to the eventual zero value. At twist a≥0, the vanishings and [F4] therefore give h1(I(a))=h0(I(a))−χ(I(a))≤p(n+an)−(p(n+an)−P(a))=P(a). The entire ambient term cancels. After at most max⁡(0,P(a)) decreases, H1(I(b(P)−1))=0; the other regularity positions vanish by the sharper range above. Thus I is b(P)-regular and the exact sequence with Op makes F regular as well. Field descent in [F3] proves the result over all fields.

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