Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Induced embeddings compose, and the induced-subgraph relation is transitive up to isomorphism

Statement

If φ:HindG\varphi:H\hookrightarrow_{\mathrm{ind}}G and ψ:GindK\psi:G\hookrightarrow_{\mathrm{ind}}K, then ψφ:HindK\psi\circ\varphi:H\hookrightarrow_{\mathrm{ind}}K. Consequently, being an induced subgraph up to isomorphism is transitive.

Facts & Assumptions

Given: Induced embeddings φ:HG\varphi:H\to G and ψ:GK\psi:G\to K.

[F1]

An induced embedding is injective and preserves adjacency in both directions (Induced embeddings and induced copies of a graph).

[F2]

A composite of injections is injective (Injection, surjection, bijection).

[F3]

Graph isomorphism is compatible with composition (Graph isomorphisms, automorphisms and graph complements).

Proof

technique · direct
1.1

The composite ψφ\psi\circ\varphi is injective.

F2
1.2

For distinct x,yV(H)x,y\in V(H), one has xyE(H)xy\in E(H) if and only if φ(x)φ(y)E(G)\varphi(x)\varphi(y)\in E(G), if and only if ψφ(x)ψφ(y)E(K)\psi\varphi(x)\psi\varphi(y)\in E(K).

F1
2.1

Hence ψφ\psi\circ\varphi is an induced embedding. Replacing induced copies by their isomorphic representatives gives the stated transitivity up to isomorphism.

step 1.1step 1.2F1F3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 15 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources