Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

BV extension, translation, and coarea

Statement

Assume Countable Choice. For every bounded Lipschitz domain Ω⊆Rn (a bounded open set with a finite Lipschitz graph cover of its boundary, with the domain on one side of each graph), zero extension is a bounded map BV(Ω)→BV(Rn) with support in Ω‾ and satisfies ∥v~∥L1(Rn)+TV(v~;Rn)≤CΩ(∥v∥L1(Ω)+TV(v;Ω)); translations satisfy ∥w(⋅+h)−w∥L1(Rn)≤∣h∣TV(w;Rn) for w∈BV(Rn); and, for every open U⊆Rn and every u∈BV(U), if Et+:={x∈U:u(x)>t} for t>0 and Et−:={x∈U:u(x)<t} for t<0, then these sets have finite perimeter for almost every applicable t and TV(u;U)=∫0∞P(Et+;U) dt+∫−∞0P(Et−;U) dt.

Facts & Assumptions

Given: Countable Choice, bounded Lipschitz domains, and BV functions on the stated domains.

[F1]

Bounded zero extension and the full-space translation estimate hold under Countable Choice, including dimension one. (BV extension and translation bounds)

[F2]

The signed-level coarea identity and almost-everywhere finite perimeter hold under Countable Choice on arbitrary open sets. (Coarea formula for spatial BV)

Proof

Given: The hypotheses in the Statement.

1.1F1given

Apply [F1] to each bounded Lipschitz domain and to the stated full-space BV functions. This proves the support, norm and translation assertions.

2.1F2givenstep 1.1∎

Apply [F2] on the arbitrary open set U to u∈BV(U). It gives exactly the two signed level families, their almost-everywhere finite perimeters, and the displayed equality. All suppliers assume only Countable Choice.

Depends on

Used by

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Dependency tree · two levels

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Sources