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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Coarea formula for spatial BV

Statement

Assume Countable Choice. Let Ω⊆Rn be open, let u∈BV(Ω), and for t>0 set Et+:={x∈Ω:u(x)>t} while for t<0 set Et−:={x∈Ω:u(x)<t}. Then for almost every applicable t these sets have finite perimeter relative to Ω, and TV(u;Ω)=∫0∞P(Et+;Ω) dt+∫−∞0P(Et−;Ω) dt.

Facts & Assumptions

Given: Countable Choice, an open Ω⊆Rn, and u∈BV(Ω).

[A1]

Countable Choice is the assigned axiom strength for this item. (The Axiom of Countable Choice (ACω))

[F1]

Strict smooth approximation and the smooth-level coarea calculation are available under Countable Choice. (Strict smooth approximation in BV, Coarea identity for smooth scalar functions)

[F2]

Under Countable Choice, finite distributional test variation of an arbitrary real L1 function is equivalent to membership in BV, with equality to its total variation. In particular this implication and lower semicontinuity apply to limits of level indicators. (Test-field formula and L1 lower semicontinuity of spatial TV)

Proof

Given: The hypotheses in the Statement.

1.1A1F2F3givenconstruct

For any real f∈L1(Ω), define its extended test variation V(f) as the supremum of ∫fdiv⁡φ over smooth compactly supported vector fields with ∣φ∣≤1. It is a lower semicontinuous extended nonnegative function on L1: each test integral is a continuous linear functional and {f:V(f)>a} is the union of its open superlevel sets. By [F2], V(f)<∞ is equivalent to f∈BV, in which case V(f)=TV(f;Ω). For t>0 the indicator χ{f>t} lies in L1, since its norm is at most ∥f∥1/t, and it is right continuous as an L1-valued function of t: if tj↓t>0, its indicators increase to χ{f>t} and their errors tend to zero by monotone convergence. Dyadic right-step approximations therefore make this map Borel measurable. For t<0, t↦χ{f<t} is similarly left continuous and Borel. Composition with the lower semicontinuous V shows that both extended level-variation functions are measurable.

2.1A1F1F2F3step 1.1choosealgebra

By [F1], take smooth strict approximants uj with ∥uj−u∥1<2−j and ∫∣∇uj∣→TV(u;Ω), passing to a subsequence by least indices if needed. For real numbers a,b, the total length of the positive and negative levels at which their signed superlevel or sublevel indicators differ is ∣a−b∣. Hence [F3] gives ∫0∞∥χ{uj>t}−χ{u>t}∥1 dt+∫−∞0∥χ{uj<t}−χ{u<t}∥1 dt=∥uj−u∥1. Sum over j and apply [F3]: for almost every applicable nonzero level, the indicator errors are summable, and in particular the level indicators converge in L1. The lower semicontinuity from step 1.1 gives V(χEt±)≤lim inf⁡jV(χ{uj≷t}) at those levels. Fatou and the smooth coarea identity [F1] consequently give ∫0∞V(χEt+) dt+∫−∞0V(χEt−) dt≤lim inf⁡j∫Ω∣∇uj∣ dx=TV(u;Ω). The integral is finite, so its integrands are finite almost everywhere; [F2] then proves the stated almost-everywhere finite-perimeter assertion.

3.1F2F3step 1.1step 2.1algebra∎

For any admissible smooth test field φ, signed layer cake gives u(x)=∫0∞χEt+(x) dt−∫−∞0χEt−(x) dt almost everywhere. The absolute integral against div⁡φ is bounded by ∥div⁡φ∥∞∥u∥1, so iterated integration is valid. Each level test integral in absolute value is at most its extended variation, using also −φ in step 1.1. Therefore ∫udiv⁡φ is at most the sum of the two perimeter integrals. Take the supremum over φ and apply [F2] to u to obtain the reverse of the inequality in step 2.1. Equality follows. Changing the representative of u changes each level set only by a spatial null set, so all conclusions concern the given L1 class.

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