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LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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The normalized large-radius loop of a monic degree-n polynomial has degree n

Statement

Let p(z)=zn+j<najzj be a monic complex polynomial of degree n1, and put S=j<naj. If R>max{1,S}, then the based normalized circle loop

αR(u)=h1(p(Rh(u))/p(R)p(Rh(u))/p(R)),uR/Z,

is well defined and has degree n.

Facts & Assumptions

Given: A monic polynomial p(z)=zn+j<najzj of degree n1, the number S=j<naj, and a real R>max{1,S}.

[F1]

For a nonzero complex polynomial, degree is the final coefficient index and monic means that its leading coefficient is 1 (Formal complex polynomials, evaluation, degree, leading coefficient, and monic polynomials).

[L2]

The homeomorphism h:R/ZS1 sends [0] to 1S1 ([t](cos2πt,sin2πt) is a homeomorphism from R/Z to the unit circle).

[L4]

Path-homotopic based circle loops have the same degree (Path-homotopic based circle loops have the same degree).

[L5]

The standard loop ωm has degree m for every integer m (deg(ωn)=n for every integer n).

Proof

technique · constructive
1.1

If z=R, then j<najzjj<najRjSRn1<Rn=zn. The estimate includes n=1 and S=0, since R>1 and S<R.

givenF1L1algebra
2.1

For s[0,1] put ps(z)=zn+sj<najzj. Step 1.1 remains strict with sSS, so ps never vanishes on z=R, in particular ps(R)0. The formula H(s,u)=h1(ps(Rh(u))/ps(R)ps(Rh(u))/ps(R)) is therefore a continuous based homotopy by [L2] and [L3]. At s=1 it is αR, while at s=0 it is uh1(h(u)n)=ωn(u).

step 1.1L1L2L3construct
3.1

Homotopy invariance and the standard-loop calculation give deg(αR)=deg(ωn)=n.

step 2.1L4L5discharge-construct

Depends on

Used by

Dependency tree · two levels

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Sources