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A root-free complex polynomial gives nullhomotopic normalized circle loops
Statement
Let be a complex polynomial with no zero in . For each real , evaluate on the circle of radius , divide by its value at the basepoint , and radially normalize to the unit circle. Transported through the homeomorphism , this is a based circle loop , and every is nullhomotopic. In particular, every such loop has degree zero.
Facts & Assumptions
Given: A complex polynomial such that for every , a real , and the unit-circle homeomorphism .
A complex polynomial is a finite coefficient list, and its evaluation at is the corresponding finite sum of powers of (Formal complex polynomials, evaluation, degree, leading coefficient, and monic polynomials).
Under , complex continuity is continuity for the Euclidean metric (The Euclidean metric, convergence, Cauchy sequences, and continuity on the complex plane).
Complex modulus satisfies , exactly when , and (Conjugation is an involutive real-field automorphism, , and modulus is definite, multiplicative, and subadditive).
The map , , is a homeomorphism and sends to ( is a homeomorphism from to the unit circle).
A map into a finite product is continuous exactly when each component is continuous, and continuity of maps into is componentwise (A map into a product is continuous iff each of its components is; the projections are continuous and open; and each projection is surjective when every factor is nonempty, which for an infinite index set uses the Axiom of Choice, A vector-valued function has a limit, or is continuous, if and only if each of its components does; with the algebra of continuous vector-valued functions).
Finite sums and products of continuous real-valued maps are continuous, as are quotients on cozero sets (Sums, products, absolute values, finite maxima and minima, and quotients of continuous real-valued maps on a topological space are continuous where defined).
A based circle loop is nullhomotopic exactly when its degree is zero (A based circle loop is nullhomotopic exactly when its degree is zero).
Proof
For and , put . Root-freeness makes numerator and denominator nonzero, so is defined; moreover , hence . Define .
Writing complex addition and multiplication in real and imaginary coordinates shows from [F1], [L3], and [L4] that and are continuous. Root-freeness and [L1] make division and radial normalization continuous, and [L2] makes continuous. At one has , so for every , while step 1.1 keeps the basepoint fixed for all . Thus is a based homotopy on the unit interval from the constant loop to , including the case without division by .
Hence is nullhomotopic for every , and [L5] gives .
Depends on
- Formal complex polynomials, evaluation, degree, leading coefficient, and monic polynomials
- The Euclidean metric, convergence, Cauchy sequences, and continuity on the complex plane
- Conjugation is an involutive real-field automorphism, $z\overline z=|z|^2$, and modulus is definite, multiplicative, and subadditive
- $[t]\mapsto(\cos 2\pi t,\sin 2\pi t)$ is a homeomorphism from $\mathbb R/\mathbb Z$ to the unit circle
- A vector-valued function has a limit, or is continuous, if and only if each of its components does; with the algebra of continuous vector-valued functions
- Sums, products, absolute values, finite maxima and minima, and quotients of continuous real-valued maps on a topological space are continuous where defined
- A map into a product is continuous iff each of its components is; the projections are continuous and open; and each projection is surjective when every factor is nonempty, which for an infinite index set uses the Axiom of Choice
- A based circle loop is nullhomotopic exactly when its degree is zero
Used by
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Sources
- Allen Hatcher, Algebraic Topology, proof of Theorem 1.8 (standard reference, not scraped)
- J. Peter May, A Concise Course in Algebraic Topology, Chapter 1, §7 (standard reference, not scraped)