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LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-24
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A root-free complex polynomial gives nullhomotopic normalized circle loops

Statement

Let p be a complex polynomial with no zero in C. For each real R0, evaluate p on the circle of radius R, divide by its value at the basepoint R, and radially normalize to the unit circle. Transported through the homeomorphism h:R/ZS1, this is a based circle loop αR, and every αR is nullhomotopic. In particular, every such loop has degree zero.

Facts & Assumptions

Given: A complex polynomial p such that p(z)0 for every zC, a real R0, and the unit-circle homeomorphism h:R/ZS1.

[F1]

A complex polynomial is a finite coefficient list, and its evaluation at zC is the corresponding finite sum of powers of z (Formal complex polynomials, evaluation, degree, leading coefficient, and monic polynomials).

[F2]

Under C=R2, complex continuity is continuity for the Euclidean metric (The Euclidean metric, convergence, Cauchy sequences, and continuity on the complex plane).

[L1]

Complex modulus satisfies zw=zw, z=0 exactly when z=0, and z+wz+w (Conjugation is an involutive real-field automorphism, zz=z2, and modulus is definite, multiplicative, and subadditive).

[L2]

The map h:R/ZS1, h([t])=(cos2πt,sin2πt), is a homeomorphism and sends [0] to 1S1 ([t](cos2πt,sin2πt) is a homeomorphism from R/Z to the unit circle).

[L4]

Finite sums and products of continuous real-valued maps are continuous, as are quotients on cozero sets (Sums, products, absolute values, finite maxima and minima, and quotients of continuous real-valued maps on a topological space are continuous where defined).

[L5]

A based circle loop is nullhomotopic exactly when its degree is zero (A based circle loop is nullhomotopic exactly when its degree is zero).

Proof

technique · constructive
1.1

For τ[0,1] and uR/Z, put q(τ,u)=p(τRh(u))/p(τR). Root-freeness makes numerator and denominator nonzero, so A(τ,u):=h1(q(τ,u)q(τ,u)) is defined; moreover q(τ,[0])=1, hence A(τ,[0])=[0]. Define αR(u)=A(1,u).

givenF1L1L2construct
2.1

Writing complex addition and multiplication in real and imaginary coordinates shows from [F1], [L3], and [L4] that (τ,u)p(τRh(u)) and τp(τR) are continuous. Root-freeness and [L1] make division and radial normalization continuous, and [L2] makes A continuous. At τ=0 one has q(0,u)=p(0)/p(0)=1, so A(0,u)=[0] for every u, while step 1.1 keeps the basepoint fixed for all τ. Thus A is a based homotopy on the unit interval from the constant loop to αR, including the case R=0 without division by R.

step 1.1F1F2L1L2L3L4
3.1

Hence αR is nullhomotopic for every R0, and [L5] gives deg(αR)=0.

step 2.1L5discharge-construct

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