Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
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One-sided Levine–Tristram signature limits exist

Statement

Assume the hypotheses and conventions of the Levine–Tristram form definition. At every root ω0∈S1∖{1} of ΔK, each one-sided limit of the nonroot signature as the parameter moves along the unit circle to ω0 exists and is an integer.

Facts & Assumptions

Given: Full AC, an oriented knot, its Seifert matrix V, and an Alexander root ω0≠1.

[A1]

Full AC and the chosen surface/basis supply a finite real Seifert matrix. Seifert pairing and matrix of an oriented knot, The Axiom of Choice

[F1]

Heiθ is a continuous Hermitian matrix family, and its singular parameters away from 1 are exactly the zeros of a nonzero Alexander polynomial. Levine–Tristram Hermitian form and signature, The singular parameters of the Levine–Tristram form, The square Seifert presentation generates the knot Alexander polynomial

[F2]

Ordered Hermitian eigenvalues vary continuously, indeed Lipschitzly in operator norm. Ordered eigenvalues of Hermitian matrices are operator-norm Lipschitz

[F3]

A continuous real function on an interval cannot take both positive and negative values without vanishing between them. Intermediate value theorem, by bisection with a canonical left-half rule: a continuous function on [a,b] takes every value between f(a) and f(b)

Proof

1.1A1F1F2givenchoose

The entries of Heiθ are continuous functions of θ. By [F2], each ordered eigenvalue λj(θ) is continuous. The determinant presentation in [F1] is a nonzero Laurent polynomial because its value at t=1 is ±1; hence it has only finitely many roots on the unit circle. Choose ϵ>0 so that each punctured one-sided arc (θ0−ϵ,θ0) and (θ0,θ0+ϵ) contains no other root. On each such arc, [F1] makes every eigenvalue nonzero.

2.1F1F3step 1.1algebra∎

On either arc, a continuous real function λj that never vanishes has constant sign: if it took both signs, [F3] would give a zero. Thus every positive/negative eigenvalue count is constant on each one-sided arc, and the signature there is a fixed integer. Each one-sided limit is that integer.

Depends on

Used by

Cited to discharge well-definedness by Levine–Tristram Hermitian form and signature.

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Sources