Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The square Seifert presentation generates the knot Alexander polynomial

Statement

Assume the full Axiom of Choice. Let K⊂S3 be a smooth oriented knot, let F⊂S3 be a connected compact smooth oriented embedded surface with oriented boundary K, and let χ(F)=1−2g with g≥0. Choose an ordered integral basis a1,…,a2g of H1(F;Z), use the positive normal convention, and set Vij=lk⁡(ai+,aj). Let Λ=Z[t±1], let AK be the first homology of the infinite cyclic cover classified by total linking with t acting by the positive-meridian deck transformation, and let ΔK be a generator of the zeroth elementary ideal E0(AK). Then the square matrix M(t)=V−tVT generates that ideal:

E0(AK)=(det⁡M(t)).

For g=0, the matrix is empty and its determinant is 1. In every genus, det⁡(V−VT)=±1, so every generator ΔK satisfies ΔK(1)=±1. The ideal and determinant assertions are compatible with integral basis changes and with orientation-preserving ambient isotopies of knot-surface pairs.

Facts & Assumptions

Given: Full AC, an oriented knot K⊂S3, a connected compact oriented Seifert surface F with ∂F=K, and an ordered integral basis of H1(F;Z).

[A1]

Full AC is the assertion that every family of nonempty sets has a choice function. It is the stated hypothesis of the Alexander-module and Seifert-matrix presentation conventions used here. (The Axiom of Choice)

[F8]

Full AC implies DC and hence the Axiom of Countable Choice, which is the stated choice hypothesis of the Seifert-surface and finite surface-normal-form suppliers. (AC implies DC implies countable choice, The Axiom of Countable Choice (ACω))

[F1]

A Seifert surface is connected, compact, smooth, oriented and embedded with the given knot as oriented boundary; in the chosen basis the positive-push matrix has entries Vij=lk⁡(ai+,aj). (Oriented Seifert surfaces in the three-sphere, Seifert pairing and matrix of an oriented knot)

[F3]

The elementary ideal E0 is independent of the finite presentation and depends only on the module's isomorphism class. (Elementary ideals are independent of the presentation)

[F4]

The positive-meridian convention gives an isomorphism AK≅coker⁡(V−tVT) over Λ. (A Seifert matrix presents the one-variable Alexander module)

[F5]

The skew part of the matrix is the surface intersection matrix: V−VT=JF, and JF is unimodular. (The skew part of a Seifert matrix is the surface intersection form)

[F6]

Under an orientation-preserving ambient isotopy, a transported basis has the same Seifert matrix; a target basis change gives V′=PTVP for P∈GL2g(Z). (Seifert matrices of ambient-isotopic pairs are S-equivalent)

[F7]

An orientation-preserving ambient isotopy induces an isomorphism of Alexander modules and preserves E0(AK) and ΔK up to a unit. (The Alexander polynomial is an oriented link invariant)

Proof

1.1A1F1F8F2F3F4givenalgebra

Put n=2g and M(t)=V−tVT. By [F1] this is the positive-push matrix in the Statement, and by [F4] AK is isomorphic to the cokernel of the square presentation matrix M(t). The definition of E0 uses the n×n minors; the only such minor of an n×n matrix is its determinant. Thus the presentation gives E0(coker⁡M)=(det⁡M), including n=0, where the sole empty minor is 1. Presentation and isomorphism independence [F3] yields E0(AK)=(det⁡M).

2.1F2F5step 1.1algebra

Evaluating at t=1 gives det⁡M(1)=det⁡(V−VT)=det⁡JF=±1 by [F5]. Since E0(AK)=(det⁡M) and ΔK is a generator of that principal ideal, ΔK=udet⁡M for a unit u=±tk by [F2]; every such unit evaluates to ±1 at t=1. Hence ΔK(1)=±1.

3.1F6F7step 1.1givenalgebra∎

If the basis is changed by P∈GLn(Z), then M′(t)=PTM(t)P and det⁡M′=(det⁡P)2det⁡M=det⁡M. Under an ambient isotopy, [F6] gives this same transported-matrix relation and [F7] preserves the Alexander ideal up to its unit generator. Thus the asserted ideal-generator relation is compatible with the stated choices.

Depends on

Used by

Dependency tree · two levels

91 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources