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LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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Seifert matrices of ambient-isotopic pairs are S-equivalent

Statement

Assume the Axiom of Choice. Let (K,F) and (K′,F′) be oriented knot and spanning-surface pairs in the oriented standard three-sphere, and let ht:S3→S3 be a smooth ambient isotopy with h0 the identity, h1(K)=K′, and h1(F)=F′, preserving the given orientations. If V and V′ are their Seifert matrices in any integral bases, then the basis transported by h1 has matrix V, and any other target basis with transition matrix P has matrix V′=PTVP. Hence V and V′ are S-equivalent, meaning they are related by a finite sequence of integral unimodular congruences and the two elementary rank-two enlargement moves or their reverses.

Facts & Assumptions

Given: Full AC, two oriented knot-surface pairs and an orientation-preserving smooth ambient isotopy carrying the first pair to the second.

[A1]

Full AC supplies the Alexander-duality linking convention used by the Seifert pairing. The Axiom of Choice

[F1]

The Seifert pairing is bilinear on homology classes and is computed by linking positive normal push-offs. Seifert pairing and matrix of an oriented knot, Well-definedness of the Seifert pairing

[F2]

An orientation-preserving ambient isotopy induces homology isomorphisms on complements and carries positive meridians to positive meridians; naturality of Alexander duality preserves the total-linking coefficient. Oriented links in the three-sphere and ambient isotopy, Singular chains and singular homology are covariantly functorial, The one-variable Alexander module of an oriented link

[F3]

The positive normal is fixed by the ambient and surface orientations, so an orientation-preserving diffeomorphism carrying the oriented surface carries positive normal levels to positive normal levels. Seifert pairing and matrix of an oriented knot

[F4]

S-equivalence is generated by integral unimodular congruences, the two elementary rank-two enlargements, and their reverses. S-equivalence of integral Seifert matrices

Proof

1.1A1F1F2F3givenconstruct

Put h=h1. Because h preserves the ambient orientation and the orientations of K,F, [F3] sends each positive normal push-off of a curve ai to a positive normal push-off of h(ai), up to a homotopy within the positive collar. By [F2] the induced map on the complement preserves the positive-meridian coefficient, so lk⁡(ai+,aj)=lk⁡(h(ai)+,h(aj)). Thus the transported basis bi=h∗[ai] of H1(F′;Z) has exactly the same matrix V.

2.1F1F4step 1.1givenalgebra∎

Let c1,…,cn be any chosen integral basis on F′. There is a unique integer matrix P with [cj]=∑iPijbi; since both lists are integral bases, P∈GLn(Z). Bilinearity [F1] gives the matrix in the c basis as V′=PTVP. By [F4], this unimodular congruence is one of the defining S-equivalence moves, so the two matrices are S-equivalent.

Remarks

The conclusion uses only the congruence move in the stated S-equivalence relation; the elementary enlargements are included to fix the relation's full convention for later consumers.

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