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Trefoil Seifert matrix and basis changes

Example

Assume the Axiom of Choice and take the genus-one Seifert surface for the trefoil described as K1 in Cattabriga–Francaviglia, Example 6.2.11. In their basis f1,f2, their negative-first Seifert form has matrix A=(10−11), and they identify K1 as the trefoil. Their convention is α(x,y)=lk⁡(x−,y); the positive-first convention here is θ(x,y)=lk⁡(x+,y). In the swapped basis a1=f2, a2=f1, the positive-first Seifert matrix is

V=(10−11),V−VT=(01−10),det⁡(V−tVT)=1−t+t2.

The determinant-one basis change P0=(1101) gives P0TVP0=(1101). It changes the off-diagonal entries but not the diagonal entries. The determinant-one basis change P1=(1123) gives P1TVP1=(3547), changing every entry. For either P, the transformed Alexander presentation matrix is PT(V−tVT)P, so it presents an isomorphic Λ-module.

Facts & Assumptions

Given: Full AC, the cited genus-one oriented trefoil surface, its negative-first matrix in the source basis, and the positive-first convention of this run.

[A1]

Full AC supplies the choice hypotheses of the Seifert-surface and normal-form interfaces. The Axiom of Choice, AC implies DC implies countable choice

[F1]

The source's genus-one example gives A=(10−11) for α(x,y)=lk⁡(x−,y) and identifies its K1 as a trefoil. Cattabriga–Francaviglia, Example 6.2.11, printed p. 45

[F2]

The positive-first matrix is defined by Vij=lk⁡(ai+,aj), linking is symmetric, and moving both curves through a disjoint collar preserves linking. Seifert pairing and matrix of an oriented knot, Well-definedness of the Seifert pairing

[F3]

For an integral basis change P, the new Seifert matrix is PTVP and the Alexander presentation matrix is V−tVT. Seifert matrices of ambient-isotopic pairs are S-equivalent, A Seifert matrix presents the one-variable Alexander module

Proof

1.1A1F1F2givenalgebra

Under [A1], apply the Seifert-pairing convention to the source's supplied oriented surface and basis. In the original source basis, Aij=lk⁡(fi−,fj). By symmetry and a simultaneous positive normal translation, this equals lk⁡(fj+,fi), which is the (j,i) entry of the positive-first matrix in the same basis. Thus that matrix is AT. Let S=(0110) be the basis swap. Then STATS=A, so the positive-first matrix in the swapped basis is the displayed V.

2.1F2F3step 1.1algebra

Direct multiplication gives V−VT=(01−10). Also V−tVT=(1−tt−11−t), whose determinant is (1−t)2+t=1−t+t2. The skew-part identity agrees with the oriented genus-one handle intersection block in the stated positive-normal convention.

2.2F3step 1.1algebra

For P0, VP0=(11−10) and P0T(VP0)=(1101). For P1, VP1=(1112) and P1T(VP1)=(3547). Both determinants are 1, so both are integral basis changes; the second matrix differs from V in all four entries.

3.1F3step 2.1step 2.2algebra∎

For either unimodular P, (PTVP)−t(PTVTP)=PT(V−tVT)P. Right multiplication by P does not change the image of the map on Λ2, and left multiplication by the automorphism PT identifies the two cokernels. The module presentation is therefore independent of these basis changes, as asserted.

Remarks

The following schematic is the closure of a two-strand braid with three crossings. Gaps mark under-strands and the uninterrupted local arc at each crossing is the over-strand. It identifies the knot picture only; the matrix and determinant calculations above use the cited source matrix and the explicit convention translation in step 1.1.

\begin{tikzpicture}[scale=0.85,>=stealth]
  \draw[thick] (-1,3)--(-1.35,2.8).. controls (-1.55,2) and (-1.55,1) ..(-1.35,0.2)--(-1,0);
  \draw[thick] (1,3)--(1.35,2.8).. controls (1.55,2) and (1.55,1) ..(1.35,0.2)--(1,0);
  \draw[thick] (-1,3)--(0,2.5)--(1,2)--(0,1.5)--(-1,1)--(0,0.5)--(1,0);
  \draw[thick] (1,3)--(0,2.5)--(-1,2)--(0,1.5)--(1,1)--(0,0.5)--(-1,0);
  \draw[white,line width=4pt] (0.28,2.64)--(-0.28,2.36);
  \draw[thick] (-0.28,2.64)--(0.28,2.36);
  \draw[white,line width=4pt] (0.28,1.64)--(-0.28,1.36);
  \draw[thick] (-0.28,1.64)--(0.28,1.36);
  \draw[white,line width=4pt] (0.28,0.64)--(-0.28,0.36);
  \draw[thick] (-0.28,0.64)--(0.28,0.36);
  \node at (0,3.35) {$\text{two braid strands}$};
  \node at (0,-0.35) {$\text{three crossings; closure arcs at the sides}$};
\end{tikzpicture}

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