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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-13
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The legs of a limiting cone are jointly monic, and the legs of a colimiting cocone are jointly epic

Statement

If (L,λj) is a limiting cone and r,s:XL satisfy λjr=λjs for every j, then r=s. Dually, if (Q,ρj) is colimiting and r,s:QX satisfy rρj=sρj for every j, then r=s.

Facts & Assumptions

Given: A limiting cone (L,λ) and morphisms r,s:XL with equal composites through every leg.

[F2]

Monomorphisms and epimorphisms are defined by left and right cancellation, respectively (Monomorphism and epimorphism by left and right cancellation).

Proof

technique · universal property
1.1

The common family ξj:=λjr=λjs is a cone, since both families arise by composing the cone λ with an apex morphism.

given
2.1

Both r and s are cone morphisms (X,ξ)(L,λ). The uniqueness clause in [F1] therefore gives r=s.

F1step 1.1
3.1

Reverse every arrow in steps 1.1 and 2.1. By [L1] this says that equal composites after all legs of a colimiting cocone force equality of the two arrows out of its apex.

L1step 1.1step 2.1
4.1

These two cancellation properties are precisely joint monicity and joint epicity; for a one-legged family they reduce to the notions in [F2].

F2step 2.1step 3.1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 13 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources