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The lemma on the logarithmic derivative

Statement

Assume Countable Choice. Let f be a nonconstant meromorphic function on C and m0(r,f′/f)=12π∫02πlog⁡+∣f′(reit)/f(reit)∣dt the standard proximity of the logarithmic derivative. Then m0(r,f′/f)=S(r,f), and the same bound holds for the normalized chordal proximity of f′/f to ∞. If f has finite order, then m0(r,f′/f)=Of(log⁡r) for every sufficiently large r without exceptions; if f is rational, then m0(r,f′/f)=Of(1) for every sufficiently large r.

Facts & Assumptions

Given: A nonconstant meromorphic f on C; Countable Choice is assumed.

[F1]

S(r,f) denotes an error term bounded by C(log⁡+T(r,f)+log⁡r) for all large r outside a measurable set of finite linear measure; the chordal proximity to infinity is m(r,∞;g)=12π∫02π12log⁡(1+∣g(reit)∣2)dt, and ∣m(r,∞;g)−m0(r,g)∣≤12log⁡2 (Nevanlinna exceptional-radius error notation, Counting, chordal proximity and characteristic).

[F2]

Separated-radius Poisson–Jensen derivative bound: for 0<α<1 and 2≤r<R, m0(r,f′/f)≤Cf,α+Cα(log⁡+T(R,f)+log⁡R+log⁡+1R−r) (Separated-radius Poisson–Jensen derivative bound).

[F3]

Finite-measure growth increment: applied to u=T(⋅,f) after increasing r0 so that T(r0,f)≥1, for ε=1 there is a measurable E of finite linear measure with T(r+T(r,f)−2,f)<T(r,f)+1 for every r∉E, r≥r0 (Finite-measure growth increment lemma).

[F4]

Ahlfors–Shimizu: T(r,f)=TAS(r,f)+C∞(f) with TAS nondecreasing and convex in log⁡r, so T(⋅,f) is continuous and nondecreasing, and T(r,f)>1 for all sufficiently large r (Ahlfors–Shimizu area form of the characteristic).

[F6]

Order is ρ(f)=lim sup⁡r→∞log⁡T(r,f)/log⁡r (Order and lower order from the Nevanlinna characteristic). If ρ(f)<∞, then for every η>0 one has T(r,f)≤rρ(f)+η for all sufficiently large r, by the definition of the upper limit. Consequently f has finite order if and only if log⁡+T(r,f)=O(log⁡r); a bound T(r,f)≤rK eventually yields only ρ(f)≤K.

[F7]

Every nonconstant complex polynomial has a complex root (Fundamental theorem of algebra by Liouville's theorem); repeated division by the corresponding linear factor gives a factorization into linear terms.

Proof

technique · apply the separated-radius derivative bound at $R=2r$ in finite order and at the Borel-increment radius $R=r+T^{-2}$ in infinite order, then handle rational functions by an explicit partial-fraction estimate
1.1F1algebra

(Reduction to the standard proximity) The two proximities differ pointwise by at most 12log⁡2, so a bound of the form C(log⁡+T(r,f)+log⁡r) for m0 transfers to m(r,∞;f′/f) with the constant enlarged by 12log⁡2, and conversely; it suffices to bound m0.

1.2F2F6algebra

(Finite order, all radii) Let f have finite order. Apply [F2] with α=12 and R=2r for r≥2: log⁡+T(2r,f)=Of(log⁡r) by [F6], log⁡R=log⁡2+log⁡r, and log⁡+1R−r=log⁡+1r=0. Hence m0(r,f′/f)≤Cf+Clog⁡r=Of(log⁡r) for every r≥2, with no exceptional set.

1.3F3F4algebra

(Infinite order, off a finite-measure set) Let f have infinite order. By [F4] the function T(⋅,f) is continuous, nondecreasing and (for nonconstant f) unbounded, so [F3] applies with ε=1: there is a measurable E of finite linear measure and r0 with T(r,f)>1 and T(r+T(r,f)−2,f)<T(r,f)+1 for every r≥r0, r∉E. Put R:=r+T(r,f)−2, so r<R≤2r and log⁡+1R−r=2log⁡+T(r,f).

1.4F1F7algebra

(Rational case, all large radii) Let f=P/Q with coprime polynomials. By [F7], factor the nonconstant polynomials into linear terms; the product rule gives P′/P=∑jmj/(z−ζj) and Q′/Q=∑knk/(z−ξk), with an empty sum for a constant polynomial. At least one polynomial is nonconstant, so the finite union of their root sets is nonempty. For r≥max⁡{2,2∣ζj∣,2∣ξk∣} each denominator satisfies ∣z−ζj∣≥r/2 on ∣z∣=r, so ∣f′/f∣≤2(deg⁡P+deg⁡Q)/r there. Consequently m0(r,f′/f)≤log⁡+(2(deg⁡P+deg⁡Q)/r)=Of(1) at every sufficiently large radius, without exceptions.

2.1F2step 1.3algebra

(Infinite order, estimate) For r≥r0, r∉E, [F2] with α=12 gives m0(r,f′/f)≤Cf+C(log⁡+T(R,f)+log⁡R+2log⁡+T(r,f)); here log⁡+T(R,f)≤log⁡+(T(r,f)+1)≤log⁡+T(r,f)+1 and log⁡R≤log⁡r+log⁡2. Hence m0(r,f′/f)≤Cf′+C′(log⁡+T(r,f)+log⁡r) for all r∉E.

3.1F1step 1.1step 1.2step 2.1

(The S statement) Combining steps 1.2 and 1.3 (the finite-order case has E=∅), m0(r,f′/f)=S(r,f) in the sense of [F1]: in the infinite-order case the exceptional set has finite linear measure, in the finite-order case the bound holds at every sufficiently large radius. By step 1.1 the chordal proximity obeys the same bound.

4.1step 3.1step 1.4∎

(Conclusion) A nonconstant meromorphic function is either rational, with m0(r,f′/f)=Of(1) at all large radii, or transcendental, of finite or infinite order, with m0(r,f′/f)=S(r,f) and the stated all-radius Of(log⁡r) refinement in the finite-order case.

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