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The lemma on the logarithmic derivative
Statement
Assume Countable Choice. Let be a nonconstant meromorphic function on and the standard proximity of the logarithmic derivative. Then and the same bound holds for the normalized chordal proximity of to . If has finite order, then for every sufficiently large without exceptions; if is rational, then for every sufficiently large .
Facts & Assumptions
Given: A nonconstant meromorphic on ; Countable Choice is assumed.
denotes an error term bounded by for all large outside a measurable set of finite linear measure; the chordal proximity to infinity is , and (Nevanlinna exceptional-radius error notation, Counting, chordal proximity and characteristic).
Separated-radius Poisson–Jensen derivative bound: for and , (Separated-radius Poisson–Jensen derivative bound).
Finite-measure growth increment: applied to after increasing so that , for there is a measurable of finite linear measure with for every , (Finite-measure growth increment lemma).
Ahlfors–Shimizu: with nondecreasing and convex in , so is continuous and nondecreasing, and for all sufficiently large (Ahlfors–Shimizu area form of the characteristic).
Order is (Order and lower order from the Nevanlinna characteristic). If , then for every one has for all sufficiently large , by the definition of the upper limit. Consequently has finite order if and only if ; a bound eventually yields only .
Every nonconstant complex polynomial has a complex root (Fundamental theorem of algebra by Liouville's theorem); repeated division by the corresponding linear factor gives a factorization into linear terms.
Proof
(Reduction to the standard proximity) The two proximities differ pointwise by at most , so a bound of the form for transfers to with the constant enlarged by , and conversely; it suffices to bound .
(Finite order, all radii) Let have finite order. Apply [F2] with and for : by [F6], , and . Hence for every , with no exceptional set.
(Infinite order, off a finite-measure set) Let have infinite order. By [F4] the function is continuous, nondecreasing and (for nonconstant ) unbounded, so [F3] applies with : there is a measurable of finite linear measure and with and for every , . Put , so and .
(Rational case, all large radii) Let with coprime polynomials. By [F7], factor the nonconstant polynomials into linear terms; the product rule gives and , with an empty sum for a constant polynomial. At least one polynomial is nonconstant, so the finite union of their root sets is nonempty. For each denominator satisfies on , so there. Consequently at every sufficiently large radius, without exceptions.
(Infinite order, estimate) For , , [F2] with gives ; here and . Hence for all .
(The statement) Combining steps 1.2 and 1.3 (the finite-order case has ), in the sense of [F1]: in the infinite-order case the exceptional set has finite linear measure, in the finite-order case the bound holds at every sufficiently large radius. By step 1.1 the chordal proximity obeys the same bound.
(Conclusion) A nonconstant meromorphic function is either rational, with at all large radii, or transcendental, of finite or infinite order, with and the stated all-radius refinement in the finite-order case.
Depends on
- Counting, chordal proximity and characteristic
- Nevanlinna exceptional-radius error notation
- Finite-measure growth increment lemma
- Separated-radius Poisson–Jensen derivative bound
- Ahlfors–Shimizu area form of the characteristic
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Order and lower order from the Nevanlinna characteristic
- Fundamental theorem of algebra by Liouville's theorem
Used by
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Sources
- Goldberg–Ostrovskii, Value Distribution of Meromorphic Functions (standard reference, not scraped)
- I. Laine, Complex Analysis III lecture notes (standard reference, not scraped)
- Alexandre Eremenko, Lectures on Nevanlinna Theory, §6 (standard reference, not scraped)