Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Polynomial convolutions force activation polynomiality almost everywhere

Statement

Assume Countable Choice. Let σ∈M. If every convolution

gφ(x)=∫Rσ(x−t)φ(t) dt,φ∈Cc∞(R),supp⁡φ⊆[−1,1],

is a polynomial, then σ agrees almost everywhere with a polynomial. Equivalently, if σ is not polynomial almost everywhere, at least one such test function has a nonpolynomial convolution.

Facts & Assumptions

Given: Countable Choice and a measurable, locally essentially bounded activation σ∈M.

[F1]

Such an activation is locally integrable, and its regular distribution is defined by integration against test functions (Locally essentially bounded activations with null discontinuity closure, Regular distribution from a locally integrable function).

[F2]

If every convolution with a real-valued test function supported in [−1,1] is polynomial, their degrees have a common finite bound (Polynomial activation convolutions have a common degree bound).

[F3]

Unit-mass mollifications converge locally in distribution pairings under Countable Choice (Mollifier approximation in distributions, The mollifier family generated by a unit-mass smooth bump).

[F4]

A distribution whose (N+1)st derivative vanishes is a polynomial distribution of degree at most N (A distribution with a vanishing derivative is a polynomial).

[F5]

The map from locally integrable functions modulo almost-everywhere equality to regular distributions is injective under Countable Choice (Locally integrable functions embed in distributions).

[F6]

The distributional derivative of a polynomial's regular distribution is its classical derivative, so the derivative of order N+1 of a degree-at-most-N polynomial vanishes (The formal derivative of a polynomial, Distributional differentiation is continuous and commutes).

[F7]

A nonnegative smooth cutoff supported in (−1,1) and positive near zero can be normalized by its finite positive integral to obtain a unit-mass bump supported in [−1,1] (Test function cutoffs and euclidean localization).

[F8]

Distributional derivatives are defined by ⟨DmT,ψ⟩=(−1)m⟨T,ψ(m)⟩ (Distributional derivative).

[F9]

Since σ is real-valued and Tσ(ψ)=∫σψ, its regular distribution takes real values on every real-valued test function and is therefore a real distribution under the convention of A distribution with a vanishing derivative is a polynomial (Locally essentially bounded activations with null discontinuity closure, Regular distribution from a locally integrable function).

[A1]

Countable Choice means every sequence of nonempty sets has a function choosing one element from each (The Axiom of Countable Choice (ACω)); it is assumed by [F3] and [F5].

Proof

1.1givenF1F2F3F7F9A1choose

Let Tσ be the regular distribution induced by σ. It is real by [F9]. The hypothesis of the Statement includes all real-valued test functions. Applying [F2] to that subclass gives N∈N0 such that every real-test convolution supported in [−1,1] is a polynomial of degree at most N. By [F7], choose a nonnegative smooth bump supported in (−1,1) and divide by its positive finite integral to obtain the real unit-mass test ρ. Its rescalings ρε for 0<ε≤1 remain supported in [−1,1], so gε=σ∗ρε is a polynomial of degree at most N.

2.1step 1.1F2F3F6F8A1algebra

By [F3], the regular distributions induced by gε converge to Tσ on every test function. For every ψ∈Cc∞(R), the definition [F8] and this convergence give ⟨DN+1Tσ,ψ⟩=(−1)N+1⟨Tσ,ψ(N+1)⟩=lim⁡ε↓0(−1)N+1∫gε(x)ψ(N+1)(x) dx=0, because [F6] makes each integral zero for the polynomial gε of degree at most N. Thus DN+1Tσ=0.

3.1step 2.1F4F5A1∎

By [F4], Tσ is the regular distribution of a polynomial p. Since both σ and p are locally integrable, injectivity [F5] implies σ=p almost everywhere. This proves the forward implication; its contrapositive is the equivalent existence assertion.

Depends on

Used by

Dependency tree · two levels

49 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources