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One-bit J-gate teleportation branch identity

Statement

For a normalized qubit ∣ψ⟩=a∣0⟩+c∣1⟩ and real α, prepare CZ(∣ψ⟩⊗∣+⟩) and project the first qubit in the ordered basis {∣b⟩α:b=0,1} of J gate and ordered equatorial measurement vectors. The outcome-b branch operator on the second qubit is

Kb=2−1/2XbJ(α).

Thus each outcome has probability 1/2 and the normalized output is XbJ(α)∣ψ⟩. The operator identity is linear and therefore also holds when the input qubit is entangled with a finite-dimensional reference register.

Facts & Assumptions

Given: A normalized qubit ∣ψ⟩=a∣0⟩+c∣1⟩, a fresh ∣+⟩ ancilla, and a real angle α.

[F1]

The J-gate definition sets ∣b⟩α=J(α)†∣b⟩; its identity lemma gives ∣b⟩α=2−1/2(∣0⟩+(−1)be−iα∣1⟩) and proves the pair is orthonormal (J gate and ordered equatorial measurement vectors, J-gate basis and exact phase identities).

[F2]

A finite projective measurement assigns each orthogonal projection its Born outcome weight (Finite projective measurements).

[F3]

A unit representative ψ gives the density operator ∣ψ⟩⟨ψ∣; it is nonnegative with trace one. The outer product has coordinate matrix uu† (Pure state and ray, Ray-to-projector is well-defined and bijective, Density operator, Dirac Notation Conversion, Dirac Notation Coordinate Identity).

[F5]

The same two rank-one projectors are a finite POVM with weights tr⁡(∣Ψ⟩⟨Ψ∣Πb) (Finite POVMs and their outcome law).

[F6]

For an instrument branch map Ib, its conditional state is Ib(ρ)/pb only when pb>0 (Finite instruments and conditional states).

[F7]

The current matrix definitions give X=(0110), H=2−1/2(111−1), CZ=diag⁡(1,1,1,−1), and J(α)=Hdiag⁡(1,eiα) (The Pauli matrices, Controlled Phase Rotation, Exact one-qubit gates and rotations, J gate and ordered equatorial measurement vectors). Direct multiplication gives CZ∗CZ=I.

[F8]

Tensoring equal linear maps with the identity preserves their equality on the ordered product register (Tensor products of finitely many linear maps).

[F9]

The computational basis of C2 is orthonormal, so ∣+⟩=2−1/2(∣0⟩+∣1⟩) is a unit vector (Finite registers and their ordered computational bases, The computational basis is orthonormal).

Proof

1.1F1F7F9algebra

The prepared state expands as 2−1/2(a∣00⟩+a∣01⟩+c∣10⟩−c∣11⟩): expand ∣ψ⟩⊗∣+⟩, and the diagonal CZ changes only the ∣11⟩ coefficient's sign by [F7] and [F9]. Projecting the first factor onto ∣b⟩α leaves the second-factor vector Kb∣ψ⟩=12((a+(−1)beiαc)∣0⟩+(a−(−1)beiαc)∣1⟩), by [F1]. Matrix multiplication from [F7] gives J(α)∣ψ⟩=2−1/2((a+eiαc)∣0⟩+(a−eiαc)∣1⟩). For b=0 these coefficients agree; for b=1, X swaps them. Thus Kb=2−1/2XbJ(α).

2.1step 1.1F1F2F3F4F5F7F9algebra

Let Ψ=CZ(∣ψ⟩⊗∣+⟩) and Πb=∣b⟩α⟨b∣⊗I. The vector Ψ is normalized because ∣ψ⟩ and ∣+⟩ are unit, and direct multiplication of the displayed diagonal CZ matrix gives CZ∗CZ=I by [F7] and [F9]. The branch vector is ΠbΨ=∣b⟩α⊗Kb∣ψ⟩ by step 1.1 and the unit norm of ∣b⟩α from [F1]. The projective outcome law [F2] gives pb=tr⁡(∣Ψ⟩⟨Ψ∣Πb); [F5] gives the same law as a POVM. Since Πb∗=Πb=Πb2, trace cyclicity [F4] and the rank-one coordinate formula [F3] give pb=tr⁡(∣ΠbΨ⟩⟨ΠbΨ∣)=∥ΠbΨ∥2=∥Kb∣ψ⟩∥2. Direct multiplication of the displayed X matrix in [F7] gives X∗X=I, and J-gate basis and exact phase identities proves J(α) is unitary, so ∥Kb∣ψ⟩∥2=12∥XbJ(α)∣ψ⟩∥2=12∥ψ∥2=1/2. Thus the branch is positive-probability and normalization is defined.

3.1step 1.1step 2.1F6F8algebra∎

Dividing the branch vector in step 1.1 by its norm 1/2 yields XbJ(α)∣ψ⟩; equivalently, the instrument conditional density from [F6] is the rank-one operator of this normalized vector. The map identity in step 1.1 remains an identity after tensoring with the identity on any finite reference register by [F8], so it also holds for entangled inputs.

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