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LemmaStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passverified 2026-08-06 (claude-sonnet-5)
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Radial normalisation xx/x2x\mapsto x/\lVert x\rVert_2 is continuous on Rn{0}\mathbb{R}^n\setminus\{0\}

Statement

For n1n\ge1, the map ρ:Rn{0}Sn1\rho:\mathbb R^n\setminus\{0\}\to S^{n-1} defined by ρ(x)=x/x2\rho(x)=x/\lVert x\rVert_2 is continuous.

Facts & Assumptions

Given: n1n\ge1, the Euclidean norm, and a nonzero point aRna\in\mathbb R^n.

[L1]

The Euclidean norm is continuous and satisfies u2v2uv2|\lVert u\rVert_2-\lVert v\rVert_2|\le\lVert u-v\rVert_2 (The finite and reverse triangle inequalities for a norm; and for n1n \ge 1 every norm NN on Rn\mathbb{R}^n satisfies N(x)Cx1N(x) \le C\lVert x\rVert_1 and is Lipschitz, hence continuous, for d2d_2).

[L3]

The unit sphere is the set of vectors with Euclidean norm 11 (Euclidean spheres and closed balls as subspaces of Rn\mathbb{R}^n).

Proof

technique · direct
1.1

Put d:=a2>0d:=\lVert a\rVert_2>0. If xa2<d/2\lVert x-a\rVert_2<d/2, then [L1] gives x2>d/2\lVert x\rVert_2>d/2.

L1
1.2

For such xx, ρ(x)ρ(a)2xa2/x2+a21/x21/a24xa2/d\lVert\rho(x)-\rho(a)\rVert_2\le\lVert x-a\rVert_2/\lVert x\rVert_2+\lVert a\rVert_2|1/\lVert x\rVert_2-1/\lVert a\rVert_2|\le4\lVert x-a\rVert_2/d.

L1
2.1

Step 1.2 gives the epsilon-delta condition at aa, so ρ\rho is continuous on the punctured space. Also ρ(x)2=1\lVert\rho(x)\rVert_2=1, so its image lies in Sn1S^{n-1} and [L2] gives continuity with that codomain.

L2L3step 1.2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 141 results over 26 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources