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Critical complex Temperley–Lieb standard modules are simple

Statement

Let q∈C×, δ=q+q−1, n≥0, and 0≤p≤⌊n/2⌋. Put t=n−2p, let κ=ord⁡(q2), and let ϕn,t be the link-state capping form on Wn,t(C,δ). If (n,p) is critical in the sense of Complex Temperley–Lieb critical labels and reflection, then ϕn,t is nondegenerate and Wn,t(C,δ) is simple.

Facts & Assumptions

Given: q∈C×, δ=q+q−1, an allowed (n,p), and the critical-label convention.

[F1]

The complex quantum integers satisfy [r]q=(qr−q−r)/(q−q−1) for q≠±1, and [r]q=rqr−1 for q=±1; the recurrence quantum characteristic is distinct from κ at q=±1 (Temperley–Lieb quantum integers and quantum characteristic).

[F2]

Wn,t has the link-state basis indexed by p-arc partial matchings, and ϕn,t is the reflection-and-capping form (Temperley–Lieb link-state standard modules by defect number, The link-state Gram form is symmetric and invariant).

[F3]

For dn,r=(nr)−(nr−1) with (n−1)=0, its Gram determinant is det⁡Gn,p=∏j=1p([t+1+j]q[j]q)dn,p−j, where the entire product denotes its polynomial continuation in δ; individual quotients are initially rational functions (The Temperley–Lieb link-state Gram determinant).

[F4]

The nonzero cell-form quotient is simple; when the cell form is nondegenerate its radical is zero, so the quotient is the entire standard module (Nonzero Temperley–Lieb cell forms give all simple heads).

[F5]

Criticality means κ<∞ and κ∣(t+1); at κ=1 this includes every allowed label (Complex Temperley–Lieb critical labels and reflection).

Proof

technique · Evaluate each determinant factor, including its removable root limit
1.1F1F3F5givenalgebra

If κ=1, then q=±1. By [F1], every positive quantum integer is nonzero, so each factor [t+1+j]q/[j]q in [F3] is nonzero. Therefore det⁡Gn,p≠0 in this case.

1.2F1F3F5givenalgebra

Suppose κ≥2. By [F5], there is an integer m≥1 with t+1=mκ. Fix a root q0=q and write ϵ=q0mκ∈{1,−1}. For any j not divisible by κ, [j]q0≠0 and [mκ+j]q0=ϵ[j]q0, by substituting q0mκ=q0−mκ=ϵ in the quantum-integer formula. Thus this quotient is nonzero.

2.1F1F3step 1.2algebra

If j=sκ with s≥1, the quotient in [F3] has a removable zero-over-zero. Write nearby parameters as q=eu, with u0 satisfying eκu0=ϵ0∈{1,−1}. Since κ≥2, q0≠±1 and sinh⁡u0≠0. From [aκ]eu=sinh⁡(aκu)/sinh⁡u, the ratio has limit lim⁡u→u0[(m+s)κ]eu[sκ]eu=m+ss(−1)mv≠0, where κu0=πiv for an integer v; this follows by taking the ratio of the first derivatives of the two vanishing numerators. Also d(q+q−1)/dq=1−q−2≠0 at q0, so this quotient also has a removable continuation locally in δ at the chosen root. Thus every rational factor in [F3] is regular and nonzero there, and their product equals the determinant polynomial by [F3].

3.1F2F3step 1.1step 2.1algebra

The exponents dn,p−j in [F3] are nonnegative integers, and an empty product is 1. Steps 1.1–2.1 therefore give det⁡Gn,p≠0 for every critical label, so the finite-dimensional form ϕn,t is nondegenerate.

4.1F2F4step 3.1∎

By [F4], a nondegenerate cell form has zero radical and its quotient by that radical is simple. The quotient is Wn,t itself, so this standard module is simple.

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