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The link-state Gram form is symmetric and invariant
Statement
Let , , , and be as in Temperley–Lieb link-state standard modules by defect number. For link states , let denote reflection across a horizontal line. The diagram is either for some or has fewer than propagating components. Define in the first case and in the second, and extend -bilinearly. Then is symmetric and satisfies
for all and . Here is reflection across a horizontal line. The matrix of in the link-state basis is the Gram matrix obtained by reflecting and capping two link states, with one factor for each closed loop.
Facts & Assumptions
Given: A commutative ring with unit, , , an allowed , and link-state representatives in .
The link states are the basis cosets of diagrams with propagating components, and the right action is (Temperley–Lieb link-state standard modules by defect number, The link-state quotient is a right Temperley–Lieb module).
Diagram composition is associative and each closed component contributes one factor (Temperley–Lieb planar diagram data and endomorphism modules, Stacking is associative and horizontal juxtaposition is strict monoidal).
Proof
For basis link states and , the composite is a diagram from to . If all boundary points propagate, planarity forces them to connect in their order, so after removing closed loops the result is for a unique . Otherwise it has fewer than propagating components. Thus the stated value is determined by the matching and loop count, and it extends uniquely to an -bilinear form on the free link-state basis [F1, F2].
Reflection reverses the order of stacking, fixes each scalar , and sends to . Hence exactly when with the same ; the lower-propagating case is also preserved. Therefore on basis states and, by bilinearity, on all module elements.
For basis states and a basis diagram , reflection gives . Both form values are therefore the coefficient of in the same associative composite . They have the same exterior matching and number of removed loops, so their coefficients of agree. If an intermediate term has fewer than propagating components, it remains lower-propagating after further stacking and contributes zero on both sides. This proves the invariance identity for basis states and basis diagrams; bilinearity proves it for all .
Depends on
Used by
- A zero Temperley–Lieb cell form can have a nonzero simple module Counterexample
- An order-three noncritical link-state form with a one-dimensional radical Example
- The rank-three one-defect link-state module Example
- Complex-root standard radicals, simple heads and reflection linkage Lemma
- Critical complex Temperley–Lieb standard modules are simple Lemma
- Exact Temperley–Lieb truncation reduces decomposition to trivial factors Lemma
- Root Gram ranks give the reflected simple-head dimensions Lemma
- The Temperley–Lieb link-state Gram determinant Lemma
- The zero-loop perfect-matching standard module is simple Lemma
- The link-state form is identically zero only at zero loop value with no defects Proposition
- All Hom spaces between complex Temperley–Lieb standards Theorem
- The Temperley–Lieb link-state diagram basis is cellular Theorem
Dependency tree · two levels
13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- David Ridout and Yvan Saint-Aubin, Standard Modules, Induction and the Structure of the Temperley-Lieb Algebra (standard reference, not scraped)
- Andrew Mathas, Hecke algebras and Schur algebras of the symmetric group, complete prepublication manuscript (1998; expanded published edition: AMS University Lecture Series 15, 1999) (standard reference, not scraped)