How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Nonsplit torsion-free abelian extensions preserve absence of group-ring zero divisors
Statement
Let be a commutative field and let be a normal subgroup with torsion-free abelian quotient . If has no zero divisors, then has no zero divisors. The group extension need not split; neither finite generation of nor an order on all of is assumed.
Statement references
Facts & Assumptions
Given: The field , normal subgroup , and torsion-free abelian quotient .
Group-ring elements have unique finite expansions, multiplication is -bilinear with , and each is a unit (The group ring of finitely supported formal -linear combinations of group elements, The group ring is a unital -algebra with basis , and each is a unit of ).
Every finitely generated torsion-free abelian group is isomorphic to for some finite (Finite torsion-free abelian freeness by explicit rational coordinates without choice).
The ring has no zero divisors.
Proof
Given: Two nonzero elements and [A1].
Let be the subgroup of generated by the images of the finite supports of and . It is finitely generated, torsion-free and abelian, so [F2] identifies it with . Transport the lexicographic order from to . This is a total order invariant under addition. No order on the whole quotient or on is needed. Let be the finite quotient supports of . Choose lifts for the finitely many elements of , using the same lift for any repeated element. By grouping terms in each coset, [F1] gives unique expressions and with . Distinct cosets have disjoint group bases, so these grouped coefficients are nonzero.
For these lifts put on and . Normality makes a ring automorphism, with inverse conjugation by . Direct multiplication gives . This is the crossed-product multiplication on the finite supports. The factor is retained and is a unit; it is not assumed to be . Its compatibility with iterated multiplication is inherited from associativity in . Thus the calculation applies to a nonsplit extension.
Let and . Every other pair satisfies : if , then , and if but , addition invariance gives the same strict inequality. Hence the coefficient of in is the single term . It is nonzero by [A1], invertibility of and injectivity of . By disjointness of coset bases, . Since were arbitrary, has no zero divisors. Only finitely many lifts were chosen, so the proof introduces no choice axiom.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Tim D. Cochran, Kent E. Orr, and Peter Teichner, Knot concordance, Whitney towers and L²-signatures, §2.1 (standard reference, not scraped)
- C. Löh, Geometric Group Theory: An Introduction (standard reference, not scraped)