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The volume far-field map is bounded and is the uniform far-field limit
Statement
Assume Countable Choice. Let be as in The three-dimensional volume integral scattering model, with , and put . Then is linear and It is Lipschitz in direction with constant at most . For every , the exterior volume potential of The three-dimensional volume integral scattering model satisfies Thus is the uniform far-field amplitude under the outgoing convention.
Facts & Assumptions
Given: Countable Choice, as in the Statement, , and .
Cauchy–Schwarz gives (The complex pairing is well-defined and satisfies Cauchy–Schwarz).
For real , let on . If , it is constant. Otherwise, with , the complex derivative theorem The complex exponential is entire and its complex derivative is itself gives Thus by , , and , and identifying with , If is differentiable with integrable then ; and a bounded derivative makes Lipschitz gives .
The integral convention for the exterior potential and the far-field map is fixed in The three-dimensional volume integral scattering model.
Proof
Given: The data in the Statement.
By [F1], the defining integral of is absolutely convergent and . Taking the supremum proves the norm bound; linearity follows from linearity of the integral.
For , [F2] gives . Integrating against and using [F1] proves the stated Lipschitz bound and hence continuity in direction.
Fix , , and , and set . Then , , and because the denominator is at least . Therefore and, by [F2], .
The integrand identity and step 1.3 give a uniform pointwise error at most . Integrating against , applying [F1], and taking the supremum over proves the far-field estimate.
Depends on
- The three-dimensional volume integral scattering model
- The complex $L^2$ pairing is well-defined and satisfies Cauchy–Schwarz
- The polar surface set function on the unit sphere
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- The complex exponential by its power series
- The complex exponential is entire and its complex derivative is itself
- $\exp(x+iy)=e^x(\cos y+i\sin y)$, $|\exp(x+iy)|=e^x$, and $e^{i\pi}+1=0$
- If $f : [a,b] \to \mathbb{R}^m$ is differentiable with integrable $f'$ then $\int_a^b f' = f(b)-f(a)$; and a bounded derivative makes $f$ Lipschitz
Used by
- Cell-volume product integration for the scattering kernel Definition
- Fredholm convergence and far-field error for cell-volume product integration Theorem
Cited to discharge well-definedness by The three-dimensional volume integral scattering model.
Dependency tree · two levels
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Sources
- Otmar Scherzer and Leonidas Mindrinos, Inverse Problems: Lecture Notes, Sommersemester 2015, §5.2.2 (standard reference, not scraped)
- Maximilian Kreuzer, Quantum Theory: Lecture Notes, Chapter 8, §8.1.2 (standard reference, not scraped)