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The Sobolev space H1 is a Hilbert space

Statement

Assume Countable Choice. Let Ω⊆Rn be open, n≥1, and K∈{R,C}. On H1(Ω)=W1,2(Ω;K) (Integer-order Sobolev spaces and their norms, The notation Hk and the reserved zero-boundary symbol) define (u,v)H1:=(u,v)L2+∑i=1n(Diu,Div)L2, with the L2 inner product of L2 with the integral pairing is a Hilbert space. Then (⋅,⋅)H1 is an inner product on the Sobolev classes whose induced norm is the W1,2 norm of Integer-order Sobolev spaces and their norms, and H1(Ω) is a Hilbert space for it. The zero-boundary space H01(Ω) is a closed subspace of H1(Ω) (Zero-boundary Sobolev space as a norm closure) and hence a Hilbert space for the restricted inner product. The pairing is linear in the first argument and conjugate-linear in the second, in the convention of Real and complex inner-product spaces and their induced length.

Facts & Assumptions

Given: Countable Choice; an open Ω⊆Rn, n≥1; a field K∈{R,C}; the space H1(Ω)=W1,2(Ω;K) with index set A1={α∈N0n:∣α∣≤1}={0,e1,…,en} and the pairing (u,v)H1:=(u,v)L2+∑i=1n(Diu,Div)L2.

[F1]

Sobolev structure: each Dαu is a well-defined L2 class and the W1,2 norm is ∥u∥W1,2=(∑α∈A1∥Dαu∥L22)1/2; H1(Ω)=W1,2(Ω;K) by notation (Integer-order Sobolev spaces and their norms, The notation Hk and the reserved zero-boundary symbol, The Sobolev norm descends to equivalence classes, The Axiom of Countable Choice (ACω)).

[F2]

L2 is a Hilbert space for the integral pairing: on real L2 the pairing ∫fg and on complex L2 the pairing ∫fg‾ are well-defined inner products with ⟨f,f⟩=∥f∥22, complete for the quotient L2 norm (L2 with the integral pairing is a Hilbert space, The space Lp(μ) as the quotient by null functions, The Lp norm descends to the quotient and makes Lp a normed space for 1≤p≤∞, Complex Lp classes and Euclidean test-function conventions).

[F3]

An inner product is linear in the first argument, conjugate-symmetric, and positive definite; its induced length is a norm, and a Hilbert space is an inner-product space complete for that norm (Real and complex inner product spaces, with the inner product linear in the first argument, Real and complex inner-product spaces and their induced length, The induced length is a norm, Hilbert space).

[F4]

H"older: for L2 classes f,g, ∣∫fg‾∣≤∥f∥2∥g∥2, with the real form ∣∫fg∣≤∥f∥2∥g∥2 (Complex Holder, Minkowski, and the quotient norm, Holder's inequality for integrals, including the endpoint cases).

[F5]

Cc∞(Ω;K) is a K-vector space of test functions, and H01(Ω) is its closure in H1: explicitly, u∈H01(Ω) if and only if for every δ>0 there is a test function φ with ∥u−φ∥W1,2<δ. A closure is closed and is the smallest closed superset (Complex Lp classes and Euclidean test-function conventions, Zero-boundary Sobolev space as a norm closure, The closure of a nonempty A is {x:d(x,A)=0}, equals A together with its limit points, and is the smallest closed superset).

[F6]

A closed linear subspace of a Banach space, with the restricted norm, is a Banach space (A closed subspace of a Banach space is Banach).

Proof

1.1F1F2F3

The pairing is a well-defined inner product: each summand (Dαu,Dαv)L2 is the L2 pairing of the well-defined classes Dαu and Dαv, hence representative-independent; each is linear in the first argument and conjugate-linear in the second over K, and conjugate-symmetric. A finite sum of maps with these properties again has them, so (u,v)H1 is well defined on classes, linear in u, conjugate-linear in v and conjugate-symmetric. It is positive definite, since (u,u)H1=∑α∈A1∥Dαu∥L22≥0 equals 0 only when every Dαu=0, in particular u=D0u=0, while u=0 plainly gives 0.

1.2F5algebra

H01(Ω) is a linear subspace. It contains the zero class, as the zero test function shows. Let u,v∈H01(Ω) and a,b∈K, and let δ>0. Using the test-function approximation of [F5], choose test functions φ,ψ with ∥u−φ∥W1,2<δ/(2(∣a∣+∣b∣+1)) and ∥v−ψ∥W1,2<δ/(2(∣a∣+∣b∣+1)); then aφ+bψ is again a test function, and ∥(au+bv)−(aφ+bψ)∥W1,2≤∣a∣ ∥u−φ∥W1,2+∣b∣ ∥v−ψ∥W1,2<δ. So au+bv∈H01(Ω); the space is a subspace and, being a closure, it is closed in H1(Ω).

2.1F1F2step 1.1algebra

Its induced norm is the Sobolev norm: (u,u)H1=∑α∈A1∥Dαu∥L22=∥u∥W1,22, so the induced length is ∥u∥W1,2.

3.1F1F2F4step 2.1

Completeness: let (um) be a Cauchy sequence in H1. For each α∈A1 the inequality ∥Dαum−Dαul∥L2≤∥um−ul∥W1,2 shows that (Dαum)m is Cauchy in L2, so it has a limit class fα. Fix i and a test function φ. The weak-derivative identity gives ∫Ωum Diφ dx=−∫ΩDium φ dx for every m; H"older's inequality makes both sides converge to ∫Ωf0 Diφ dx and −∫Ωfi φ dx, respectively, where f0 is the limit of the classes um=D0um. Hence ∫f0Diφ=−∫fiφ for every test function φ, so f0∈W1,2(Ω;K) with Dif0=fi, and ∥um−f0∥W1,22=∑α∈A1∥Dαum−fα∥L22→0. Thus every Cauchy sequence in H1 converges in H1: the space is complete in its Sobolev norm.

4.1F1F3step 1.1step 2.1step 3.1

Consequences for the pairing: by steps 1.1, 2.1 the pairing is an inner product inducing the Sobolev norm, and by step 3.1 the space is complete for that norm; therefore H1(Ω) is a Hilbert space over K for the pairing.

5.1F3F5F6step 4.1step 1.2

H01(Ω) is a Hilbert space: it is a closed linear subspace of the Hilbert space H1(Ω), hence complete for the restricted norm by [F6] applied to the underlying Banach space, and the restriction of the inner product is an inner product whose induced norm is the restriction of the Sobolev norm.

6.1step 4.1step 5.1∎

The pairing (⋅,⋅)H1 is therefore an inner product on H1(Ω) inducing the W1,2 norm, making H1(Ω) a Hilbert space, while H01(Ω) is a closed subspace and a Hilbert space for the restricted pairing; the pairing is linear in the first argument and conjugate-linear in the second, as required.

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