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Higher Hochschild cohomology vanishes for linearly reductive groups
Statement
Let be a field and let be a linearly reductive affine algebraic group over (Affine schemes and their coordinate rings): every finite-dimensional rational representation of is a direct sum of simple representations, equivalently for every finite-dimensional representation (Linear reductivity is equivalent to vanishing of first Hochschild cohomology). Then and for every rational representation of , where is Hochschild cohomology (Hochschild cohomology of algebraic groups and the classification of Hochschild extensions).
Facts & Assumptions
Given: A field , a linearly reductive affine algebraic group over , a rational representation of , and an integer .
Cohomology is computed from the Hochschild complex ; a short exact sequence of rational -modules induces a long exact sequence in cohomology through degreewise tensor exactness. (Hochschild cohomology of algebraic groups and the classification of Hochschild extensions)
Every rational representation is the filtered union of its finite-dimensional subrepresentations, and Hochschild cohomology commutes with filtered colimits of coefficient modules: for directed systems of subrepresentations. (Milne, Algebraic Groups, Section 15(e); the colimit statement is the standard exactness of filtered colimits applied degreewise to the rational cochain complex : tensor products commute with filtered colimits, which are exact over a field.)
Milne's Lemma 15.14: every class for finite-dimensional and dies in for some finite-dimensional representation containing . (Milne, Algebraic Groups, Lemma 15.14; the vanishing input is Shapiro's lemma for the trivial subgroup and acyclicity of free comodules.)
for every finite-dimensional representation of a linearly reductive . (Linear reductivity is equivalent to vanishing of first Hochschild cohomology)
Proof
Given: A field , a linearly reductive affine algebraic group over , a rational representation , and .
By [F2] the representation is the filtered union of its finite-dimensional subrepresentations , and . It therefore suffices to prove for every finite-dimensional representation and every ; fix such a .
I prove by induction on . For this is [F4]. For , let ; by [F3] there is a finite-dimensional representation containing such that maps to zero in . The short exact sequence of finite-dimensional representations gives, by [F1], the exact sequence , so for some . By the induction hypothesis and [step 1.1] applied to the finite-dimensional representation , the group vanishes; hence and . Therefore for all finite-dimensional and all , and by [step 1.1] the same holds for every rational representation.
Depends on
Used by
- Extensions of multiplicative-type groups by a one-dimensional vector group with a linear action split Proposition
- Conjugacy of diagonalizable complements and maximal subgroups under smoothness hypotheses Theorem
- Splitting trigonalizable extensions: algebraically closed fields and two perfect-field cases Theorem
Dependency tree · two levels
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Sources
- J. S. Milne, Algebraic Groups (corrected 2022 printing, Cambridge University Press) (standard reference, not scraped)
- J. S. Milne, Algebraic Groups (v2.00, 20 December 2015 author-hosted preliminary edition) (standard reference, not scraped)