Alphabeta Math
PropositionStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-11
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If C\mathcal C is small and D\mathcal D is locally small then [C,D][\mathcal C,\mathcal D] is locally small; if both are small it is small

Statement

If C\mathcal C is small and D\mathcal D is locally small, then [C,D][\mathcal C,\mathcal D] is locally small. If both C\mathcal C and D\mathcal D are small, then [C,D][\mathcal C,\mathcal D] is small.

Facts & Assumptions

Given: Categories C,D\mathcal C,\mathcal D with the stated size hypotheses.

[L1]

The objects and morphisms of [C,D][\mathcal C,\mathcal D] are functors and natural transformations (Functor category [C,D][\mathcal C,\mathcal D]).

[L2]

Smallness and local smallness mean set-sized object, morphism, and hom-collections as specified in Small, locally small, and large categories.

Proof

technique · direct
1.1

For fixed functors F,GF,G, a natural transformation is a family in the set-indexed product CObCD(FC,GC)\prod_{C\in\operatorname{Ob}\mathcal C}\mathcal D(FC,GC) satisfying a set of naturality equations; smallness of C\mathcal C and local smallness of D\mathcal D make this a set.

givenL1L2
2.1

Hence every hom-collection of [C,D][\mathcal C,\mathcal D] is a set, so the functor category is locally small.

step 1.1L1L2
3.1

If D\mathcal D is also small, the possible object and morphism functions of a functor lie in set-sized function spaces, and the functor equations define a subset; the union of the set-sized natural-transformation sets is then a set, so [C,D][\mathcal C,\mathcal D] is small.

step 2.1L1L2

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 12 results over 8 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources