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PropositionStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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The Ext balance isomorphism is natural in both variables

Statement

Assume the Axiom of Dependent Choice and the supplied resolution hypotheses of the balance theorem. For every n≥0, the balance maps βM,Nn:Ext⁡Pn(M,N)→Ext⁡In(M,N) are natural in both M and N.

Facts & Assumptions

Given: Morphisms u:M′→M and v:N→N′ in the resolved class.

Proof

technique · direct
1.1givenconstruct

Choose the projective and injective comparison maps for u and v. Projective-resolution Ext has the stated bifunctor variance and Injective-resolution Ext has the stated bifunctor variance give the two routes around the naturality square.

2.1step 1.1algebra∎

The chosen comparison maps induce a morphism of Hom double complexes. Because its squares with the projective augmentation P∙→M and the injective coaugmentation N→I∙ commute, both edge-to-total quasi-isomorphisms commute with it. Taking cohomology makes the balance square commute. The independence lemma removes the chosen comparison maps, proving naturality in both variables.

Depends on

Used by

Dependency tree · two levels

16 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources