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A transverse volume-preserving flow implies tautness in the compact cooriented three-dimensional setting

Statement

Assume Countable Choice ACω. Let F be a transversely oriented codimension-one foliation of a closed oriented 3-manifold M, and let X be a smooth vector field transverse to F whose flow preserves a volume form μ on M, i.e. LXμ=0. Then F is taut. (The flow of X is complete because M is compact.)

Facts & Assumptions

Given: A closed oriented three-manifold M with a transversely oriented codimension-one foliation F, a smooth vector field X transverse to F with LXμ=0 for a volume form μ, and the flow ϕt of X.

[F1]

A transversely oriented foliation of a compact manifold is taut if and only if it has no dead-end component, and a dead-end component is a compact saturated submanifold whose boundary leaves carry the co-orientation inwards (A foliation is taut if and only if it has no dead-end component, Dead-end components, Taut codimension-one foliations).

[F2]

A smooth vector field on a compact manifold is complete, so its flow is defined for all real times and is a smooth one-parameter group of diffeomorphisms (Every smooth vector field on a compact manifold is complete, Complete vector fields, Local and global flows generated by a vector field).

[F3]

A tensor field is invariant under a flow if and only if its Lie derivative in the generating field vanishes, so LXμ=0 makes every ϕt preserve μ (A tensor field is flow-invariant exactly when its Lie derivative vanishes, The Lie derivative of a tensor field).

[F4]

A volume form on an oriented manifold assigns finite positive measure to every compact region with nonempty interior (Positive volume form on an oriented manifold, Open cover, subcover, and compact topological space; a compact subset is a subspace that is compact in its own right).

[F5]

The standing assumption is Countable Choice ACω as recorded for this pair (The countable-choice principle used in the foliation pair).

Proof

technique · direct
1.1F1givenchoose

Suppose F is not taut. By [F1] there is a dead-end region; take a connected component N with nonempty boundary. The sign of X relative to the chosen coorientation is constant on this connected region, so we may choose the transverse field X co-oriented so that it points inwards along ∂N: replacing X by −X preserves LXμ=0 up to sign and changes the co-orientation, so the volume-preservation hypothesis is unaffected.

2.1F1F2step 1.1

A transverse flow with this co-orientation maps N properly into itself: an integral curve starting in N cannot cross ∂N outwards without violating the inward co-orientation, so ϕt(N)⊆N for t≥0, and the inclusion is proper for every t>0 because the flow moves points of N strictly inwards across a small collar of the boundary.

3.1F3F4step 2.1

On the other hand μ(ϕt(N))=μ(N) by [F3], and μ(N)<∞ because N is compact and μ is a volume form [F4]. The proper inclusion leaves in N∖ϕt(N) a nonempty open set, hence positive measure for t>0, contradicting the equality of measures. Therefore no dead-end component exists and F is taut.

4.1F2F5step 3.1∎

This is Ranz's volume-preserving-flow lemma and the converse direction of Calegari's volume criterion, with completeness of the flow supplied by compactness of M [F2]; the argument uses only finitely many charts and one flow, so it consumes at most the standing countable choice from [F5].

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