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Two-species continuous and discrete dispersion criteria
Statement
Let and let be a homogeneous equilibrium, . Set , assume and , and let with . For any spatial eigenfunction of with eigenvalue , the linearized reaction-diffusion mode has matrix . For the continuous rectangular torus, with . For the periodic grid of Periodic rectangular reaction-diffusion grid, the mode indexed by has , with .
Define
For either domain or grid and each actual mode, has a positive-real-part eigenvalue exactly when ; it is Hurwitz exactly when , and has a zero eigenvalue when . Thus the continuous or discrete linear instability criterion tests the actual corresponding spectrum. If all nonnegative are regarded as continuously available, then a diffusion-driven unstable band exists exactly when and ; its endpoints are
On a bounded torus or a finite grid, the band criterion alone is not enough: at least one actual Laplacian eigenvalue must lie strictly between and .
Facts & Assumptions
Given: The smooth two-component reaction field, homogeneous equilibrium, kinetic Jacobian , positive diagonal diffusivities, and either a continuous periodic rectangular domain or the finite periodic grid.
Semilinear vector reaction-diffusion systems: the diffusion matrix is diagonal and the reaction term is local, so linearization at a homogeneous equilibrium gives .
Periodic rectangular reaction-diffusion grid: the positive centered heat stencil is and the diffusion generator is its negative times .
Periodic heat-stencil eigenvalues and θ amplification factor: on a periodic rectangular grid the Fourier modes form a basis and the positive heat stencil has eigenvalues when the directional diffusivities are one.
Proof
Write . Differentiability of gives , so the linearized equation is . For a continuous torus mode , direct differentiation gives and hence .
For every , . Expanding the determinant gives .
For the grid, insert a Fourier vector from [F3] into the linearized finite system. By [F2] its diffusion part multiplies that mode by ; the reaction Jacobian acts on the species coordinate by . Therefore the mode coefficient satisfies . The basis assertion in [F3] ensures these are the actual grid mode matrices.
The characteristic polynomial of a real matrix is . If and , its discriminant is positive and the real roots have negative product, so one is positive. If and , real roots have negative sum and positive product, so both are negative; nonreal roots are conjugate with real part . If the determinant is zero, one eigenvalue is zero and the other is the trace, which is negative. Applying these alternatives to proves the mode tests in the Statement.
Since and , the upward-opening quadratic is negative at some exactly when its minimum occurs at a positive point and its discriminant is strictly positive. Its minimizer is , so the first condition is ; its discriminant is , so the second condition is the strict inequality in the Statement. Under these conditions both roots are positive because their sum is and product is , and factorization gives precisely between them. The mode tests from step 2.2 then prove the continuous-spectrum and finite-grid criteria without replacing either actual spectrum by all real wavenumbers.
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Sources
- Luca Doria, Numerical Algorithms, lecture notes, Johannes Gutenberg-Universität Mainz, 2022 (standard reference, not scraped)