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Two-species continuous and discrete dispersion criteria

Statement

Let F∈C1 and let y∗∈R2 be a homogeneous equilibrium, F(y∗)=0. Set J=DF(y∗)=(Jij), assume tr⁡J<0 and det⁡J>0, and let D=diag⁡(d1,d2) with d1,d2>0. For any spatial eigenfunction of −Δ with eigenvalue λ≥0, the linearized reaction-diffusion mode has matrix J−λD. For the continuous rectangular torus, λ=λk=∑j(2πkj/Lj)2 with k∈Zd. For the periodic grid of Periodic rectangular reaction-diffusion grid, the mode indexed by ℓ has λ=λh,ℓ=4∑jhj−2sin⁡2(πℓj/Nj), with 0≤ℓj<Nj.

Define

βT=d2J11+d1J22,q(λ)=det⁡(J−λD)=d1d2λ2−βTλ+det⁡J.

For either domain or grid and each actual mode, J−λD has a positive-real-part eigenvalue exactly when q(λ)<0; it is Hurwitz exactly when q(λ)>0, and has a zero eigenvalue when q(λ)=0. Thus the continuous or discrete linear instability criterion tests the actual corresponding spectrum. If all nonnegative λ are regarded as continuously available, then a diffusion-driven unstable band exists exactly when βT>0 and βT2>4d1d2det⁡J; its endpoints are

λ±=βT±βT2−4d1d2det⁡J2d1d2.

On a bounded torus or a finite grid, the band criterion alone is not enough: at least one actual Laplacian eigenvalue must lie strictly between λ− and λ+.

Facts & Assumptions

Given: The smooth two-component reaction field, homogeneous equilibrium, kinetic Jacobian J, positive diagonal diffusivities, and either a continuous periodic rectangular domain or the finite periodic grid.

[F1]

Semilinear vector reaction-diffusion systems: the diffusion matrix is diagonal and the reaction term is local, so linearization at a homogeneous equilibrium gives wt=DΔw+Jw.

[F2]

Periodic rectangular reaction-diffusion grid: the positive centered heat stencil is Ahper and the diffusion generator is its negative times D.

[F3]

Periodic heat-stencil eigenvalues and θ amplification factor: on a periodic rectangular grid the Fourier modes form a basis and the positive heat stencil has eigenvalues 4∑jhj−2sin⁡2(πℓj/Nj) when the directional diffusivities are one.

Proof

1.1F1givenconstructalgebra

Write u=y∗+εw. Differentiability of F gives F(y∗+εw)=F(y∗)+εJw+o(ε)=εJw+o(ε), so the linearized equation is wt=DΔw+Jw. For a continuous torus mode w(t,x)=a(t)e2πi∑jkjxj/Lj, direct differentiation gives Δw=−λkw and hence a′=(J−λkD)a.

1.2givenalgebra

For every λ≥0, tr⁡(J−λD)=tr⁡J−λ(d1+d2)<0. Expanding the 2×2 determinant gives det⁡(J−λD)=(J11−λd1)(J22−λd2)−J12J21=d1d2λ2−βTλ+det⁡J=q(λ).

2.1F2F3step 1.1algebra

For the grid, insert a Fourier vector from [F3] into the linearized finite system. By [F2] its diffusion part multiplies that mode by −Dλh,ℓ; the reaction Jacobian acts on the species coordinate by J. Therefore the mode coefficient satisfies a′=(J−λh,ℓD)a. The basis assertion in [F3] ensures these are the actual grid mode matrices.

2.2step 1.2algebra

The characteristic polynomial of a real 2×2 matrix A is μ2−tr⁡(A)μ+det⁡(A). If tr⁡(A)<0 and det⁡(A)<0, its discriminant tr⁡(A)2−4det⁡(A) is positive and the real roots have negative product, so one is positive. If tr⁡(A)<0 and det⁡(A)>0, real roots have negative sum and positive product, so both are negative; nonreal roots are conjugate with real part tr⁡(A)/2<0. If the determinant is zero, one eigenvalue is zero and the other is the trace, which is negative. Applying these alternatives to A=J−λD proves the mode tests in the Statement.

3.1step 1.2step 2.2algebra∎

Since d1d2>0 and det⁡J>0, the upward-opening quadratic q is negative at some λ≥0 exactly when its minimum occurs at a positive point and its discriminant is strictly positive. Its minimizer is βT/(2d1d2), so the first condition is βT>0; its discriminant is βT2−4d1d2det⁡J, so the second condition is the strict inequality in the Statement. Under these conditions both roots are positive because their sum is βT/(d1d2)>0 and product is det⁡J/(d1d2)>0, and factorization gives q<0 precisely between them. The mode tests from step 2.2 then prove the continuous-spectrum and finite-grid criteria without replacing either actual spectrum by all real wavenumbers.

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